def gen_random_tufo(form):
iden = hexlify(random.bytes(16)).decode('utf8')
props = {}
for propname in form:
if random.random() <= INTEGER_VAL_RATE:
val = random.randint(-2 ** 62, 2 ** 63)
else:
val = random_string(random_val_len())
props[propname] = val
return (iden, props)
def test_base64():
random.seed(73101)
for i in xrange(6):
for n in xrange(20):
s = random.bytes(n)
ours = base64_encode(s)
theirs = base64.b64encode(s)
assert ours==theirs
assert base64_decode(ours)==s
for s in '====','&&&&','++==','+++=':
try:
base64_decode(s)
except ValueError:
pass
def get_random_bytes(size, seed):
random.seed(seed)
return random.bytes(size)
def test_bytes(self):
random.seed(101)
self.assertEqual(random.bytes(10), "_\xb32\x84\x0bFs\x8dQE")
from numpy.random import bytes print repr(bytes(5)) # string of 5 random bytes print repr(bytes(5)) # another string of 5 random bytes
def rand_chars():
n_bytes = random.randint(0, 10)
return random.bytes(n_bytes).decode("latin1")
'''[[-0.84341992 -0.51332541]
[-0.0435368 -0.27530091]
[-1.56306679 -0.79563099]
[ 0.9305844 0.67776741]
[ 0.69844026 0.17360206]]'''
x = random.normal(size=(5, 2))
# 产生5个，n=5，p=0.5的二项分布样本
x = random.binomial(n=5, p=0.5, size=5)
print(x)
a = np.arange(10)
print(a)
# 从a中有回放的随机采样7个
x = random.choice(a, 7)
print(x)
# 从a中无回放的随机采样7个
x = random.choice(a, 7, replace=False)
print(x)
# 对a进行乱序并返回一个新的array
b = random.permutation(a)
print(b)
# 对a进行in-place乱序
print('start', a)
random.shuffle(a)
print('end', a)
# 生成一个长度为9的随机bytes序列并作为str返回
# '\x96\x9d\xd1?\xe6\x18\xbb\x9a\xec'
x = random.bytes(9)
print(x)
import sys
sys.path.append('../cryptoutils/')
import AES
import binascii
import numpy.random as rand
import time
secret = binascii.a2b_base64(
'Um9sbGluJyBpbiBteSA1LjAKV2l0aCBteSByYWctdG9wIGRvd24gc28gbXkgUm9sbGluJyBpbiBteSA1LjAKV2l0aCBteSByYWctdG9wIGRvd24gc28gbXkgaGFpciBjYW4gYmxvdwpUaGUgZ2lybGllcyBvbiBzdGFuZGJ5IHdhdmluZyBqdXN0IHRvIHNheSBoaQpEaWQgeW91IHN0b3A/IE5vLCBJIGp1c3QgZHJvdmUgYnkK'
)
key = rand.bytes(16)
prefix_len = rand.randint(1, 16)
prefix = rand.bytes(prefix_len)
def oracle(s):
plain = prefix + s + secret
return AES.ecb_encrypt(plain, key)
"""
This is not a clean solution but it is a soultion i am proud of
it doesn't break any assumptions (i guess i don't find block size but hey)
it is a huge advancement over break_ecb
"""
def break_ecb():
def get_random_bytes(size, seed):
with local_seed(seed):
return random.bytes(size)
def get_random_bytes(size, seed):
random.seed(seed)
return random.bytes(size)
