# It sometimes returns two dates if it is exactly half a year after the
# holiday. In this case, the smaller distance (182 days) is returned.
return (index - holiday_date[0]).days
return distance_to_day
EasterSunday = Holiday("Easter Sunday",
month=1,
day=1,
offset=[Easter(), Day(0)])
NewYearsDay = Holiday("New Years Day", month=1, day=1)
SuperBowl = Holiday("Superbowl",
month=2,
day=1,
offset=DateOffset(weekday=SU(1)))
MothersDay = Holiday("Mothers Day",
month=5,
day=1,
offset=DateOffset(weekday=SU(2)))
IndependenceDay = Holiday("Independence Day", month=7, day=4)
ChristmasEve = Holiday("Christmas", month=12, day=24)
ChristmasDay = Holiday("Christmas", month=12, day=25)
NewYearsEve = Holiday("New Years Eve", month=12, day=31)
BlackFriday = Holiday("Black Friday",
month=11,
day=1,
offset=[pd.DateOffset(weekday=TH(4)),
Day(1)])
CyberMonday = Holiday(
"Cyber Monday",
index - pd.Timedelta(days=MAX_WINDOW),
index + pd.Timedelta(days=MAX_WINDOW),
)
assert (
len(holiday_date) != 0
), f"No closest holiday for the date index {index} found."
# It sometimes returns two dates if it is exactly half a year after the
# holiday. In this case, the smaller distance (182 days) is returned.
return (index - holiday_date[0]).days
return distance_to_day
EasterSunday = Holiday("Easter Sunday", month=1, day=1, offset=[Easter(), Day(0)])
NewYearsDay = Holiday("New Years Day", month=1, day=1)
SuperBowl = Holiday("Superbowl", month=2, day=1, offset=DateOffset(weekday=SU(1)))
MothersDay = Holiday("Mothers Day", month=5, day=1, offset=DateOffset(weekday=SU(2)))
IndependenceDay = Holiday("Independence Day", month=7, day=4)
ChristmasEve = Holiday("Christmas", month=12, day=24)
ChristmasDay = Holiday("Christmas", month=12, day=25)
NewYearsEve = Holiday("New Years Eve", month=12, day=31)
BlackFriday = Holiday(
"Black Friday", month=11, day=1, offset=[pd.DateOffset(weekday=TH(4)), Day(1)]
)
CyberMonday = Holiday(
"Cyber Monday",
month=11,
day=1,
offset=[pd.DateOffset(weekday=TH(4)), Day(4)],
)
assert (
len(holiday_date) != 0
), f"No closest holiday for the date index {index} found."
# It sometimes returns two dates if it is exactly half a year after the
# holiday. In this case, the smaller distance (182 days) is returned.
return (index - holiday_date[0]).days
return distance_to_day
EasterSunday = Holiday(
"Easter Sunday", month=1, day=1, offset=[Easter(), Day(0)]
)
NewYearsDay = Holiday("New Years Day", month=1, day=1)
SuperBowl = Holiday(
"Superbowl", month=2, day=1, offset=DateOffset(weekday=SU(1))
)
MothersDay = Holiday(
"Mothers Day", month=5, day=1, offset=DateOffset(weekday=SU(2))
)
IndependenceDay = Holiday("Independence Day", month=7, day=4)
ChristmasEve = Holiday("Christmas", month=12, day=24)
ChristmasDay = Holiday("Christmas", month=12, day=25)
NewYearsEve = Holiday("New Years Eve", month=12, day=31)
BlackFriday = Holiday(
"Black Friday",
month=11,
day=1,
offset=[pd.DateOffset(weekday=TH(4)), Day(1)],
)
CyberMonday = Holiday(