look(foo['c'])
# selectre
table1 = (('foo', 'bar', 'baz'),
('aa', 4, 9.3),
('aaa', 2, 88.2),
('b', 1, 23.3),
('ccc', 8, 42.0),
('bb', 7, 100.9),
('c', 2))
from petl import selectre, look
look(table1)
table2 = selectre(table1, 'foo', '[ab]{2}')
look(table2)
# rowreduce
table1 = [['foo', 'bar'],
['a', 3],
['a', 7],
['b', 2],
['b', 1],
['b', 9],
['c', 4]]
from petl import rowreduce, look
look(table1)
look(foo['c'])
# selectre
table1 = (('foo', 'bar', 'baz'),
('aa', 4, 9.3),
('aaa', 2, 88.2),
('b', 1, 23.3),
('ccc', 8, 42.0),
('bb', 7, 100.9),
('c', 2))
from petl import selectre, look
look(table1)
table2 = selectre(table1, 'foo', '[ab]{2}')
look(table2)
# rowreduce
table1 = [['foo', 'bar'],
['a', 3],
['a', 7],
['b', 2],
['b', 1],
['b', 9],
['c', 4]]
from petl import rowreduce, look
look(table1)