def testEnds(self):
cc = Chaincode([0, 0], "2460") # Can I test more than one path? How?
end = [0, 0]
self.failUnless(cc.matchend(end))
def testEndsFalse(self):
cc = Chaincode([0, 0], "24460")
end = [0, 0]
self.failIf(cc.matchend(end))
def testSubBoundingBoxX(self):
cc = Chaincode([0, 0], "44464660012075602223")
self.failUnless(cc.subBoundingBox(xedge=[0.1, 2]) == [0, 3])
def testSubBoundingBoxY(self):
cc = Chaincode([0, 0], "44464660012075602223")
self.failUnless(cc.subBoundingBox(yedge=[-1, 0.5]) == [0, 3])
def testBoundingBox(self): #needs of np.array... I think
cc = Chaincode([0, 0], "00033344")
boundingbox = [[-3, 2], [-3, 0]] # [[x0,x1],[y0,y1]] (like cc)
self.failUnless(np.all(cc.BoundingBox() == np.array(boundingbox)))
def testBoundingBoxFalse(self):
cc = Chaincode([0, 0], "002")
boundingbox = [[-1, 0], [-1, 0]]
self.failIf(np.all(cc.BoundingBox() != np.array(boundingbox)))
def testnparray(self):
# Let's test that the shape of the array matchs the expected
# To do so we need to use np.array, instead of lists.
cc = Chaincode([0, 0], "2460")
shape = (2,5)
self.failUnless(cc.coordinates.shape == shape)
def testScaleEnd(self):
cc = Chaincode([1.2, 3],"0723", xdelta=2.629, ydelta=2.629)
end = [-1.429, 0.371]
self.failUnless(cc.matchany(end, -1))
def testScaleSecond(self):
cc = Chaincode([0, 0], "0723", xdelta=0.5, ydelta=0.5)
second = [-1, 0.5]
self.failUnless(cc.matchany(second, 2))
def testSecondCoordinateFails(self):
cc = Chaincode([1, 0], "0023")
second = [-2, 0]
self.failIf(cc.matchany(second, 2))
def testSecondCoordinate(self):
cc = Chaincode([0, 0], "0023")
second = [-2, 0]
self.failUnless(cc.matchany(second, 2))
