def factor_sum(self, limits=None, radical=False, clear=False, fraction=False, sign=True):
"""Helper function for Sum simplification
if limits is specified, "self" is the inner part of a sum
Returns the sum with constant factors brought outside
"""
from sympy.core.exprtools import factor_terms
from sympy.concrete.summations import Sum
result = self.function if limits is None else self
limits = self.limits if limits is None else limits
#avoid any confusion w/ as_independent
if result == 0:
return S.Zero
#get the summation variables
sum_vars = set([limit.args[0] for limit in limits])
#finally we try to factor out any common terms
#and remove the from the sum if independent
retv = factor_terms(result, radical=radical, clear=clear, fraction=fraction, sign=sign)
#avoid doing anything bad
if not result.is_commutative:
return Sum(result, *limits)
i, d = retv.as_independent(*sum_vars)
if isinstance(retv, Add):
return i * Sum(1, *limits) + Sum(d, *limits)
else:
return i * Sum(d, *limits)
def factor_sum(self, limits=None, radical=False, clear=False, fraction=False, sign=True):
"""Helper function for Sum simplification
if limits is specified, "self" is the inner part of a sum
Returns the sum with constant factors brought outside
"""
from sympy.core.exprtools import factor_terms
from sympy.concrete.summations import Sum
result = self.function if limits is None else self
limits = self.limits if limits is None else limits
#avoid any confusion w/ as_independent
if result == 0:
return S.Zero
#get the summation variables
sum_vars = set([limit.args[0] for limit in limits])
#finally we try to factor out any common terms
#and remove the from the sum if independent
retv = factor_terms(result, radical=radical, clear=clear, fraction=fraction, sign=sign)
#avoid doing anything bad
if not result.is_commutative:
return Sum(result, *limits)
i, d = retv.as_independent(*sum_vars)
if isinstance(retv, Add):
return i * Sum(1, *limits) + Sum(d, *limits)
else:
return i * Sum(d, *limits)
def clear_coefficients(expr, rhs=S.Zero):
"""Return `p, r` where `p` is the expression obtained when Rational
additive and multiplicative coefficients of `expr` have been stripped
away in a naive fashion (i.e. without simplification). The operations
needed to remove the coefficients will be applied to `rhs` and returned
as `r`.
Examples
========
>>> from sympy.simplify.simplify import clear_coefficients
>>> from sympy.abc import x, y
>>> from sympy import Dummy
>>> expr = 4*y*(6*x + 3)
>>> clear_coefficients(expr - 2)
(y*(2*x + 1), 1/6)
When solving 2 or more expressions like `expr = a`,
`expr = b`, etc..., it is advantageous to provide a Dummy symbol
for `rhs` and simply replace it with `a`, `b`, etc... in `r`.
>>> rhs = Dummy('rhs')
>>> clear_coefficients(expr, rhs)
(y*(2*x + 1), _rhs/12)
>>> _[1].subs(rhs, 2)
1/6
"""
was = None
free = expr.free_symbols
if expr.is_Rational:
return (S.Zero, rhs - expr)
while expr and was != expr:
was = expr
m, expr = (
expr.as_content_primitive()
if free else
factor_terms(expr).as_coeff_Mul(rational=True))
rhs /= m
c, expr = expr.as_coeff_Add(rational=True)
rhs -= c
expr = signsimp(expr, evaluate = False)
if _coeff_isneg(expr):
expr = -expr
rhs = -rhs
return expr, rhs
def clear_coefficients(expr, rhs=S.Zero):
"""Return `p, r` where `p` is the expression obtained when Rational
additive and multiplicative coefficients of `expr` have been stripped
away in a naive fashion (i.e. without simplification). The operations
needed to remove the coefficients will be applied to `rhs` and returned
as `r`.
Examples
========
>>> from sympy.simplify.simplify import clear_coefficients
>>> from sympy.abc import x, y
>>> from sympy import Dummy
>>> expr = 4*y*(6*x + 3)
>>> clear_coefficients(expr - 2)
(y*(2*x + 1), 1/6)
When solving 2 or more expressions like `expr = a`,
`expr = b`, etc..., it is advantageous to provide a Dummy symbol
for `rhs` and simply replace it with `a`, `b`, etc... in `r`.
>>> rhs = Dummy('rhs')
>>> clear_coefficients(expr, rhs)
(y*(2*x + 1), _rhs/12)
>>> _[1].subs(rhs, 2)
1/6
"""
was = None
free = expr.free_symbols
if expr.is_Rational:
return (S.Zero, rhs - expr)
while expr and was != expr:
was = expr
m, expr = (
expr.as_content_primitive()
if free else
factor_terms(expr).as_coeff_Mul(rational=True))
rhs /= m
c, expr = expr.as_coeff_Add(rational=True)
rhs -= c
expr = signsimp(expr, evaluate = False)
if _coeff_isneg(expr):
expr = -expr
rhs = -rhs
return expr, rhs
def simplify(expr, ratio=1.7, measure=count_ops, fu=False):
"""
Simplifies the given expression.
Simplification is not a well defined term and the exact strategies
this function tries can change in the future versions of SymPy. If
your algorithm relies on "simplification" (whatever it is), try to
determine what you need exactly - is it powsimp()?, radsimp()?,
together()?, logcombine()?, or something else? And use this particular
function directly, because those are well defined and thus your algorithm
will be robust.
Nonetheless, especially for interactive use, or when you don't know
anything about the structure of the expression, simplify() tries to apply
intelligent heuristics to make the input expression "simpler". For
example:
>>> from sympy import simplify, cos, sin
>>> from sympy.abc import x, y
>>> a = (x + x**2)/(x*sin(y)**2 + x*cos(y)**2)
>>> a
(x**2 + x)/(x*sin(y)**2 + x*cos(y)**2)
>>> simplify(a)
x + 1
Note that we could have obtained the same result by using specific
simplification functions:
>>> from sympy import trigsimp, cancel
>>> trigsimp(a)
(x**2 + x)/x
>>> cancel(_)
x + 1
In some cases, applying :func:`simplify` may actually result in some more
complicated expression. The default ``ratio=1.7`` prevents more extreme
cases: if (result length)/(input length) > ratio, then input is returned
unmodified. The ``measure`` parameter lets you specify the function used
to determine how complex an expression is. The function should take a
single argument as an expression and return a number such that if
expression ``a`` is more complex than expression ``b``, then
``measure(a) > measure(b)``. The default measure function is
:func:`count_ops`, which returns the total number of operations in the
expression.
For example, if ``ratio=1``, ``simplify`` output can't be longer
than input.
::
>>> from sympy import sqrt, simplify, count_ops, oo
>>> root = 1/(sqrt(2)+3)
Since ``simplify(root)`` would result in a slightly longer expression,
root is returned unchanged instead::
>>> simplify(root, ratio=1) == root
True
If ``ratio=oo``, simplify will be applied anyway::
>>> count_ops(simplify(root, ratio=oo)) > count_ops(root)
True
Note that the shortest expression is not necessary the simplest, so
setting ``ratio`` to 1 may not be a good idea.
Heuristically, the default value ``ratio=1.7`` seems like a reasonable
choice.
You can easily define your own measure function based on what you feel
should represent the "size" or "complexity" of the input expression. Note
that some choices, such as ``lambda expr: len(str(expr))`` may appear to be
good metrics, but have other problems (in this case, the measure function
may slow down simplify too much for very large expressions). If you don't
know what a good metric would be, the default, ``count_ops``, is a good
one.
For example:
>>> from sympy import symbols, log
>>> a, b = symbols('a b', positive=True)
>>> g = log(a) + log(b) + log(a)*log(1/b)
>>> h = simplify(g)
>>> h
log(a*b**(-log(a) + 1))
>>> count_ops(g)
8
>>> count_ops(h)
5
So you can see that ``h`` is simpler than ``g`` using the count_ops metric.
However, we may not like how ``simplify`` (in this case, using
``logcombine``) has created the ``b**(log(1/a) + 1)`` term. A simple way
to reduce this would be to give more weight to powers as operations in
``count_ops``. We can do this by using the ``visual=True`` option:
>>> print(count_ops(g, visual=True))
2*ADD + DIV + 4*LOG + MUL
>>> print(count_ops(h, visual=True))
2*LOG + MUL + POW + SUB
>>> from sympy import Symbol, S
>>> def my_measure(expr):
... POW = Symbol('POW')
... # Discourage powers by giving POW a weight of 10
... count = count_ops(expr, visual=True).subs(POW, 10)
... # Every other operation gets a weight of 1 (the default)
... count = count.replace(Symbol, type(S.One))
... return count
>>> my_measure(g)
8
>>> my_measure(h)
14
>>> 15./8 > 1.7 # 1.7 is the default ratio
True
>>> simplify(g, measure=my_measure)
-log(a)*log(b) + log(a) + log(b)
Note that because ``simplify()`` internally tries many different
simplification strategies and then compares them using the measure
function, we get a completely different result that is still different
from the input expression by doing this.
"""
expr = sympify(expr)
try:
return expr._eval_simplify(ratio=ratio, measure=measure)
except AttributeError:
pass
original_expr = expr = signsimp(expr)
from sympy.simplify.hyperexpand import hyperexpand
from sympy.functions.special.bessel import BesselBase
from sympy import Sum, Product
if not isinstance(expr, Basic) or not expr.args: # XXX: temporary hack
return expr
if not isinstance(expr, (Add, Mul, Pow, ExpBase)):
if isinstance(expr, Function) and hasattr(expr, "inverse"):
if len(expr.args) == 1 and len(expr.args[0].args) == 1 and \
isinstance(expr.args[0], expr.inverse(argindex=1)):
return simplify(expr.args[0].args[0], ratio=ratio,
measure=measure, fu=fu)
return expr.func(*[simplify(x, ratio=ratio, measure=measure, fu=fu)
for x in expr.args])
# TODO: Apply different strategies, considering expression pattern:
# is it a purely rational function? Is there any trigonometric function?...
# See also https://github.com/sympy/sympy/pull/185.
def shorter(*choices):
'''Return the choice that has the fewest ops. In case of a tie,
the expression listed first is selected.'''
if not has_variety(choices):
return choices[0]
return min(choices, key=measure)
expr = bottom_up(expr, lambda w: w.normal())
expr = Mul(*powsimp(expr).as_content_primitive())
_e = cancel(expr)
expr1 = shorter(_e, _mexpand(_e).cancel()) # issue 6829
expr2 = shorter(together(expr, deep=True), together(expr1, deep=True))
if ratio is S.Infinity:
expr = expr2
else:
expr = shorter(expr2, expr1, expr)
if not isinstance(expr, Basic): # XXX: temporary hack
return expr
expr = factor_terms(expr, sign=False)
# hyperexpand automatically only works on hypergeometric terms
expr = hyperexpand(expr)
expr = piecewise_fold(expr)
if expr.has(BesselBase):
expr = besselsimp(expr)
if expr.has(TrigonometricFunction) and not fu or expr.has(
HyperbolicFunction):
expr = trigsimp(expr, deep=True)
if expr.has(log):
expr = shorter(expand_log(expr, deep=True), logcombine(expr))
if expr.has(CombinatorialFunction, gamma):
expr = combsimp(expr)
if expr.has(Sum):
expr = sum_simplify(expr)
if expr.has(Product):
expr = product_simplify(expr)
short = shorter(powsimp(expr, combine='exp', deep=True), powsimp(expr), expr)
short = shorter(short, factor_terms(short), expand_power_exp(expand_mul(short)))
if short.has(TrigonometricFunction, HyperbolicFunction, ExpBase):
short = exptrigsimp(short, simplify=False)
# get rid of hollow 2-arg Mul factorization
hollow_mul = Transform(
lambda x: Mul(*x.args),
lambda x:
x.is_Mul and
len(x.args) == 2 and
x.args[0].is_Number and
x.args[1].is_Add and
x.is_commutative)
expr = short.xreplace(hollow_mul)
numer, denom = expr.as_numer_denom()
if denom.is_Add:
n, d = fraction(radsimp(1/denom, symbolic=False, max_terms=1))
if n is not S.One:
expr = (numer*n).expand()/d
if expr.could_extract_minus_sign():
n, d = fraction(expr)
if d != 0:
expr = signsimp(-n/(-d))
if measure(expr) > ratio*measure(original_expr):
expr = original_expr
return expr
def powsimp(expr, deep=False, combine='all', force=False, measure=count_ops):
"""
reduces expression by combining powers with similar bases and exponents.
Notes
=====
If deep is True then powsimp() will also simplify arguments of
functions. By default deep is set to False.
If force is True then bases will be combined without checking for
assumptions, e.g. sqrt(x)*sqrt(y) -> sqrt(x*y) which is not true
if x and y are both negative.
You can make powsimp() only combine bases or only combine exponents by
changing combine='base' or combine='exp'. By default, combine='all',
which does both. combine='base' will only combine::
a a a 2x x
x * y => (x*y) as well as things like 2 => 4
and combine='exp' will only combine
::
a b (a + b)
x * x => x
combine='exp' will strictly only combine exponents in the way that used
to be automatic. Also use deep=True if you need the old behavior.
When combine='all', 'exp' is evaluated first. Consider the first
example below for when there could be an ambiguity relating to this.
This is done so things like the second example can be completely
combined. If you want 'base' combined first, do something like
powsimp(powsimp(expr, combine='base'), combine='exp').
Examples
========
>>> from sympy import powsimp, exp, log, symbols
>>> from sympy.abc import x, y, z, n
>>> powsimp(x**y*x**z*y**z, combine='all')
x**(y + z)*y**z
>>> powsimp(x**y*x**z*y**z, combine='exp')
x**(y + z)*y**z
>>> powsimp(x**y*x**z*y**z, combine='base', force=True)
x**y*(x*y)**z
>>> powsimp(x**z*x**y*n**z*n**y, combine='all', force=True)
(n*x)**(y + z)
>>> powsimp(x**z*x**y*n**z*n**y, combine='exp')
n**(y + z)*x**(y + z)
>>> powsimp(x**z*x**y*n**z*n**y, combine='base', force=True)
(n*x)**y*(n*x)**z
>>> x, y = symbols('x y', positive=True)
>>> powsimp(log(exp(x)*exp(y)))
log(exp(x)*exp(y))
>>> powsimp(log(exp(x)*exp(y)), deep=True)
x + y
Radicals with Mul bases will be combined if combine='exp'
>>> from sympy import sqrt, Mul
>>> x, y = symbols('x y')
Two radicals are automatically joined through Mul:
>>> a=sqrt(x*sqrt(y))
>>> a*a**3 == a**4
True
But if an integer power of that radical has been
autoexpanded then Mul does not join the resulting factors:
>>> a**4 # auto expands to a Mul, no longer a Pow
x**2*y
>>> _*a # so Mul doesn't combine them
x**2*y*sqrt(x*sqrt(y))
>>> powsimp(_) # but powsimp will
(x*sqrt(y))**(5/2)
>>> powsimp(x*y*a) # but won't when doing so would violate assumptions
x*y*sqrt(x*sqrt(y))
"""
from sympy.matrices.expressions.matexpr import MatrixSymbol
def recurse(arg, **kwargs):
_deep = kwargs.get('deep', deep)
_combine = kwargs.get('combine', combine)
_force = kwargs.get('force', force)
_measure = kwargs.get('measure', measure)
return powsimp(arg, _deep, _combine, _force, _measure)
expr = sympify(expr)
if (not isinstance(expr, Basic) or isinstance(expr, MatrixSymbol) or (
expr.is_Atom or expr in (exp_polar(0), exp_polar(1)))):
return expr
if deep or expr.is_Add or expr.is_Mul and _y not in expr.args:
expr = expr.func(*[recurse(w) for w in expr.args])
if expr.is_Pow:
return recurse(expr*_y, deep=False)/_y
if not expr.is_Mul:
return expr
# handle the Mul
if combine in ('exp', 'all'):
# Collect base/exp data, while maintaining order in the
# non-commutative parts of the product
c_powers = defaultdict(list)
nc_part = []
newexpr = []
coeff = S.One
for term in expr.args:
if term.is_Rational:
coeff *= term
continue
if term.is_Pow:
term = _denest_pow(term)
if term.is_commutative:
b, e = term.as_base_exp()
if deep:
b, e = [recurse(i) for i in [b, e]]
if b.is_Pow or isinstance(b, exp):
# don't let smthg like sqrt(x**a) split into x**a, 1/2
# or else it will be joined as x**(a/2) later
b, e = b**e, S.One
c_powers[b].append(e)
else:
# This is the logic that combines exponents for equal,
# but non-commutative bases: A**x*A**y == A**(x+y).
if nc_part:
b1, e1 = nc_part[-1].as_base_exp()
b2, e2 = term.as_base_exp()
if (b1 == b2 and
e1.is_commutative and e2.is_commutative):
nc_part[-1] = Pow(b1, Add(e1, e2))
continue
nc_part.append(term)
# add up exponents of common bases
for b, e in ordered(iter(c_powers.items())):
# allow 2**x/4 -> 2**(x - 2); don't do this when b and e are
# Numbers since autoevaluation will undo it, e.g.
# 2**(1/3)/4 -> 2**(1/3 - 2) -> 2**(1/3)/4
if (b and b.is_Rational and not all(ei.is_Number for ei in e) and \
coeff is not S.One and
b not in (S.One, S.NegativeOne)):
m = multiplicity(abs(b), abs(coeff))
if m:
e.append(m)
coeff /= b**m
c_powers[b] = Add(*e)
if coeff is not S.One:
if coeff in c_powers:
c_powers[coeff] += S.One
else:
c_powers[coeff] = S.One
# convert to plain dictionary
c_powers = dict(c_powers)
# check for base and inverted base pairs
be = list(c_powers.items())
skip = set() # skip if we already saw them
for b, e in be:
if b in skip:
continue
bpos = b.is_positive or b.is_polar
if bpos:
binv = 1/b
if b != binv and binv in c_powers:
if b.as_numer_denom()[0] is S.One:
c_powers.pop(b)
c_powers[binv] -= e
else:
skip.add(binv)
e = c_powers.pop(binv)
c_powers[b] -= e
# check for base and negated base pairs
be = list(c_powers.items())
_n = S.NegativeOne
for i, (b, e) in enumerate(be):
if ((-b).is_Symbol or b.is_Add) and -b in c_powers:
if (b.is_positive in (0, 1) or e.is_integer):
c_powers[-b] += c_powers.pop(b)
if _n in c_powers:
c_powers[_n] += e
else:
c_powers[_n] = e
# filter c_powers and convert to a list
c_powers = [(b, e) for b, e in c_powers.items() if e]
# ==============================================================
# check for Mul bases of Rational powers that can be combined with
# separated bases, e.g. x*sqrt(x*y)*sqrt(x*sqrt(x*y)) ->
# (x*sqrt(x*y))**(3/2)
# ---------------- helper functions
def ratq(x):
'''Return Rational part of x's exponent as it appears in the bkey.
'''
return bkey(x)[0][1]
def bkey(b, e=None):
'''Return (b**s, c.q), c.p where e -> c*s. If e is not given then
it will be taken by using as_base_exp() on the input b.
e.g.
x**3/2 -> (x, 2), 3
x**y -> (x**y, 1), 1
x**(2*y/3) -> (x**y, 3), 2
exp(x/2) -> (exp(a), 2), 1
'''
if e is not None: # coming from c_powers or from below
if e.is_Integer:
return (b, S.One), e
elif e.is_Rational:
return (b, Integer(e.q)), Integer(e.p)
else:
c, m = e.as_coeff_Mul(rational=True)
if c is not S.One:
if m.is_integer:
return (b, Integer(c.q)), m*Integer(c.p)
return (b**m, Integer(c.q)), Integer(c.p)
else:
return (b**e, S.One), S.One
else:
return bkey(*b.as_base_exp())
def update(b):
'''Decide what to do with base, b. If its exponent is now an
integer multiple of the Rational denominator, then remove it
and put the factors of its base in the common_b dictionary or
update the existing bases if necessary. If it has been zeroed
out, simply remove the base.
'''
newe, r = divmod(common_b[b], b[1])
if not r:
common_b.pop(b)
if newe:
for m in Mul.make_args(b[0]**newe):
b, e = bkey(m)
if b not in common_b:
common_b[b] = 0
common_b[b] += e
if b[1] != 1:
bases.append(b)
# ---------------- end of helper functions
# assemble a dictionary of the factors having a Rational power
common_b = {}
done = []
bases = []
for b, e in c_powers:
b, e = bkey(b, e)
if b in common_b:
common_b[b] = common_b[b] + e
else:
common_b[b] = e
if b[1] != 1 and b[0].is_Mul:
bases.append(b)
bases.sort(key=default_sort_key) # this makes tie-breaking canonical
bases.sort(key=measure, reverse=True) # handle longest first
for base in bases:
if base not in common_b: # it may have been removed already
continue
b, exponent = base
last = False # True when no factor of base is a radical
qlcm = 1 # the lcm of the radical denominators
while True:
bstart = b
qstart = qlcm
bb = [] # list of factors
ee = [] # (factor's expo. and it's current value in common_b)
for bi in Mul.make_args(b):
bib, bie = bkey(bi)
if bib not in common_b or common_b[bib] < bie:
ee = bb = [] # failed
break
ee.append([bie, common_b[bib]])
bb.append(bib)
if ee:
# find the number of integral extractions possible
# e.g. [(1, 2), (2, 2)] -> min(2/1, 2/2) -> 1
min1 = ee[0][1]//ee[0][0]
for i in range(1, len(ee)):
rat = ee[i][1]//ee[i][0]
if rat < 1:
break
min1 = min(min1, rat)
else:
# update base factor counts
# e.g. if ee = [(2, 5), (3, 6)] then min1 = 2
# and the new base counts will be 5-2*2 and 6-2*3
for i in range(len(bb)):
common_b[bb[i]] -= min1*ee[i][0]
update(bb[i])
# update the count of the base
# e.g. x**2*y*sqrt(x*sqrt(y)) the count of x*sqrt(y)
# will increase by 4 to give bkey (x*sqrt(y), 2, 5)
common_b[base] += min1*qstart*exponent
if (last # no more radicals in base
or len(common_b) == 1 # nothing left to join with
or all(k[1] == 1 for k in common_b) # no rad's in common_b
):
break
# see what we can exponentiate base by to remove any radicals
# so we know what to search for
# e.g. if base were x**(1/2)*y**(1/3) then we should
# exponentiate by 6 and look for powers of x and y in the ratio
# of 2 to 3
qlcm = lcm([ratq(bi) for bi in Mul.make_args(bstart)])
if qlcm == 1:
break # we are done
b = bstart**qlcm
qlcm *= qstart
if all(ratq(bi) == 1 for bi in Mul.make_args(b)):
last = True # we are going to be done after this next pass
# this base no longer can find anything to join with and
# since it was longer than any other we are done with it
b, q = base
done.append((b, common_b.pop(base)*Rational(1, q)))
# update c_powers and get ready to continue with powsimp
c_powers = done
# there may be terms still in common_b that were bases that were
# identified as needing processing, so remove those, too
for (b, q), e in common_b.items():
if (b.is_Pow or isinstance(b, exp)) and \
q is not S.One and not b.exp.is_Rational:
b, be = b.as_base_exp()
b = b**(be/q)
else:
b = root(b, q)
c_powers.append((b, e))
check = len(c_powers)
c_powers = dict(c_powers)
assert len(c_powers) == check # there should have been no duplicates
# ==============================================================
# rebuild the expression
newexpr = expr.func(*(newexpr + [Pow(b, e) for b, e in c_powers.items()]))
if combine == 'exp':
return expr.func(newexpr, expr.func(*nc_part))
else:
return recurse(expr.func(*nc_part), combine='base') * \
recurse(newexpr, combine='base')
elif combine == 'base':
# Build c_powers and nc_part. These must both be lists not
# dicts because exp's are not combined.
c_powers = []
nc_part = []
for term in expr.args:
if term.is_commutative:
c_powers.append(list(term.as_base_exp()))
else:
nc_part.append(term)
# Pull out numerical coefficients from exponent if assumptions allow
# e.g., 2**(2*x) => 4**x
for i in range(len(c_powers)):
b, e = c_powers[i]
if not (all(x.is_nonnegative for x in b.as_numer_denom()) or e.is_integer or force or b.is_polar):
continue
exp_c, exp_t = e.as_coeff_Mul(rational=True)
if exp_c is not S.One and exp_t is not S.One:
c_powers[i] = [Pow(b, exp_c), exp_t]
# Combine bases whenever they have the same exponent and
# assumptions allow
# first gather the potential bases under the common exponent
c_exp = defaultdict(list)
for b, e in c_powers:
if deep:
e = recurse(e)
c_exp[e].append(b)
del c_powers
# Merge back in the results of the above to form a new product
c_powers = defaultdict(list)
for e in c_exp:
bases = c_exp[e]
# calculate the new base for e
if len(bases) == 1:
new_base = bases[0]
elif e.is_integer or force:
new_base = expr.func(*bases)
else:
# see which ones can be joined
unk = []
nonneg = []
neg = []
for bi in bases:
if bi.is_negative:
neg.append(bi)
elif bi.is_nonnegative:
nonneg.append(bi)
elif bi.is_polar:
nonneg.append(
bi) # polar can be treated like non-negative
else:
unk.append(bi)
if len(unk) == 1 and not neg or len(neg) == 1 and not unk:
# a single neg or a single unk can join the rest
nonneg.extend(unk + neg)
unk = neg = []
elif neg:
# their negative signs cancel in groups of 2*q if we know
# that e = p/q else we have to treat them as unknown
israt = False
if e.is_Rational:
israt = True
else:
p, d = e.as_numer_denom()
if p.is_integer and d.is_integer:
israt = True
if israt:
neg = [-w for w in neg]
unk.extend([S.NegativeOne]*len(neg))
else:
unk.extend(neg)
neg = []
del israt
# these shouldn't be joined
for b in unk:
c_powers[b].append(e)
# here is a new joined base
new_base = expr.func(*(nonneg + neg))
# if there are positive parts they will just get separated
# again unless some change is made
def _terms(e):
# return the number of terms of this expression
# when multiplied out -- assuming no joining of terms
if e.is_Add:
return sum([_terms(ai) for ai in e.args])
if e.is_Mul:
return prod([_terms(mi) for mi in e.args])
return 1
xnew_base = expand_mul(new_base, deep=False)
if len(Add.make_args(xnew_base)) < _terms(new_base):
new_base = factor_terms(xnew_base)
c_powers[new_base].append(e)
# break out the powers from c_powers now
c_part = [Pow(b, ei) for b, e in c_powers.items() for ei in e]
# we're done
return expr.func(*(c_part + nc_part))
else:
raise ValueError("combine must be one of ('all', 'exp', 'base').")
def powsimp(expr, deep=False, combine='all', force=False, measure=count_ops):
"""
reduces expression by combining powers with similar bases and exponents.
Explanation
===========
If ``deep`` is ``True`` then powsimp() will also simplify arguments of
functions. By default ``deep`` is set to ``False``.
If ``force`` is ``True`` then bases will be combined without checking for
assumptions, e.g. sqrt(x)*sqrt(y) -> sqrt(x*y) which is not true
if x and y are both negative.
You can make powsimp() only combine bases or only combine exponents by
changing combine='base' or combine='exp'. By default, combine='all',
which does both. combine='base' will only combine::
a a a 2x x
x * y => (x*y) as well as things like 2 => 4
and combine='exp' will only combine
::
a b (a + b)
x * x => x
combine='exp' will strictly only combine exponents in the way that used
to be automatic. Also use deep=True if you need the old behavior.
When combine='all', 'exp' is evaluated first. Consider the first
example below for when there could be an ambiguity relating to this.
This is done so things like the second example can be completely
combined. If you want 'base' combined first, do something like
powsimp(powsimp(expr, combine='base'), combine='exp').
Examples
========
>>> from sympy import powsimp, exp, log, symbols
>>> from sympy.abc import x, y, z, n
>>> powsimp(x**y*x**z*y**z, combine='all')
x**(y + z)*y**z
>>> powsimp(x**y*x**z*y**z, combine='exp')
x**(y + z)*y**z
>>> powsimp(x**y*x**z*y**z, combine='base', force=True)
x**y*(x*y)**z
>>> powsimp(x**z*x**y*n**z*n**y, combine='all', force=True)
(n*x)**(y + z)
>>> powsimp(x**z*x**y*n**z*n**y, combine='exp')
n**(y + z)*x**(y + z)
>>> powsimp(x**z*x**y*n**z*n**y, combine='base', force=True)
(n*x)**y*(n*x)**z
>>> x, y = symbols('x y', positive=True)
>>> powsimp(log(exp(x)*exp(y)))
log(exp(x)*exp(y))
>>> powsimp(log(exp(x)*exp(y)), deep=True)
x + y
Radicals with Mul bases will be combined if combine='exp'
>>> from sympy import sqrt
>>> x, y = symbols('x y')
Two radicals are automatically joined through Mul:
>>> a=sqrt(x*sqrt(y))
>>> a*a**3 == a**4
True
But if an integer power of that radical has been
autoexpanded then Mul does not join the resulting factors:
>>> a**4 # auto expands to a Mul, no longer a Pow
x**2*y
>>> _*a # so Mul doesn't combine them
x**2*y*sqrt(x*sqrt(y))
>>> powsimp(_) # but powsimp will
(x*sqrt(y))**(5/2)
>>> powsimp(x*y*a) # but won't when doing so would violate assumptions
x*y*sqrt(x*sqrt(y))
"""
from sympy.matrices.expressions.matexpr import MatrixSymbol
def recurse(arg, **kwargs):
_deep = kwargs.get('deep', deep)
_combine = kwargs.get('combine', combine)
_force = kwargs.get('force', force)
_measure = kwargs.get('measure', measure)
return powsimp(arg, _deep, _combine, _force, _measure)
expr = sympify(expr)
if (not isinstance(expr, Basic) or isinstance(expr, MatrixSymbol)
or (expr.is_Atom or expr in (exp_polar(0), exp_polar(1)))):
return expr
if deep or expr.is_Add or expr.is_Mul and _y not in expr.args:
expr = expr.func(*[recurse(w) for w in expr.args])
if expr.is_Pow:
return recurse(expr * _y, deep=False) / _y
if not expr.is_Mul:
return expr
# handle the Mul
if combine in ('exp', 'all'):
# Collect base/exp data, while maintaining order in the
# non-commutative parts of the product
c_powers = defaultdict(list)
nc_part = []
newexpr = []
coeff = S.One
for term in expr.args:
if term.is_Rational:
coeff *= term
continue
if term.is_Pow:
term = _denest_pow(term)
if term.is_commutative:
b, e = term.as_base_exp()
if deep:
b, e = [recurse(i) for i in [b, e]]
if b.is_Pow or isinstance(b, exp):
# don't let smthg like sqrt(x**a) split into x**a, 1/2
# or else it will be joined as x**(a/2) later
b, e = b**e, S.One
c_powers[b].append(e)
else:
# This is the logic that combines exponents for equal,
# but non-commutative bases: A**x*A**y == A**(x+y).
if nc_part:
b1, e1 = nc_part[-1].as_base_exp()
b2, e2 = term.as_base_exp()
if (b1 == b2 and e1.is_commutative and e2.is_commutative):
nc_part[-1] = Pow(b1, Add(e1, e2))
continue
nc_part.append(term)
# add up exponents of common bases
for b, e in ordered(iter(c_powers.items())):
# allow 2**x/4 -> 2**(x - 2); don't do this when b and e are
# Numbers since autoevaluation will undo it, e.g.
# 2**(1/3)/4 -> 2**(1/3 - 2) -> 2**(1/3)/4
if (b and b.is_Rational and not all(ei.is_Number for ei in e) and \
coeff is not S.One and
b not in (S.One, S.NegativeOne)):
m = multiplicity(abs(b), abs(coeff))
if m:
e.append(m)
coeff /= b**m
c_powers[b] = Add(*e)
if coeff is not S.One:
if coeff in c_powers:
c_powers[coeff] += S.One
else:
c_powers[coeff] = S.One
# convert to plain dictionary
c_powers = dict(c_powers)
# check for base and inverted base pairs
be = list(c_powers.items())
skip = set() # skip if we already saw them
for b, e in be:
if b in skip:
continue
bpos = b.is_positive or b.is_polar
if bpos:
binv = 1 / b
if b != binv and binv in c_powers:
if b.as_numer_denom()[0] is S.One:
c_powers.pop(b)
c_powers[binv] -= e
else:
skip.add(binv)
e = c_powers.pop(binv)
c_powers[b] -= e
# check for base and negated base pairs
be = list(c_powers.items())
_n = S.NegativeOne
for b, e in be:
if (b.is_Symbol or b.is_Add) and -b in c_powers and b in c_powers:
if (b.is_positive is not None or e.is_integer):
if e.is_integer or b.is_negative:
c_powers[-b] += c_powers.pop(b)
else: # (-b).is_positive so use its e
e = c_powers.pop(-b)
c_powers[b] += e
if _n in c_powers:
c_powers[_n] += e
else:
c_powers[_n] = e
# filter c_powers and convert to a list
c_powers = [(b, e) for b, e in c_powers.items() if e]
# ==============================================================
# check for Mul bases of Rational powers that can be combined with
# separated bases, e.g. x*sqrt(x*y)*sqrt(x*sqrt(x*y)) ->
# (x*sqrt(x*y))**(3/2)
# ---------------- helper functions
def ratq(x):
'''Return Rational part of x's exponent as it appears in the bkey.
'''
return bkey(x)[0][1]
def bkey(b, e=None):
'''Return (b**s, c.q), c.p where e -> c*s. If e is not given then
it will be taken by using as_base_exp() on the input b.
e.g.
x**3/2 -> (x, 2), 3
x**y -> (x**y, 1), 1
x**(2*y/3) -> (x**y, 3), 2
exp(x/2) -> (exp(a), 2), 1
'''
if e is not None: # coming from c_powers or from below
if e.is_Integer:
return (b, S.One), e
elif e.is_Rational:
return (b, Integer(e.q)), Integer(e.p)
else:
c, m = e.as_coeff_Mul(rational=True)
if c is not S.One:
if m.is_integer:
return (b, Integer(c.q)), m * Integer(c.p)
return (b**m, Integer(c.q)), Integer(c.p)
else:
return (b**e, S.One), S.One
else:
return bkey(*b.as_base_exp())
def update(b):
'''Decide what to do with base, b. If its exponent is now an
integer multiple of the Rational denominator, then remove it
and put the factors of its base in the common_b dictionary or
update the existing bases if necessary. If it has been zeroed
out, simply remove the base.
'''
newe, r = divmod(common_b[b], b[1])
if not r:
common_b.pop(b)
if newe:
for m in Mul.make_args(b[0]**newe):
b, e = bkey(m)
if b not in common_b:
common_b[b] = 0
common_b[b] += e
if b[1] != 1:
bases.append(b)
# ---------------- end of helper functions
# assemble a dictionary of the factors having a Rational power
common_b = {}
done = []
bases = []
for b, e in c_powers:
b, e = bkey(b, e)
if b in common_b:
common_b[b] = common_b[b] + e
else:
common_b[b] = e
if b[1] != 1 and b[0].is_Mul:
bases.append(b)
bases.sort(key=default_sort_key) # this makes tie-breaking canonical
bases.sort(key=measure, reverse=True) # handle longest first
for base in bases:
if base not in common_b: # it may have been removed already
continue
b, exponent = base
last = False # True when no factor of base is a radical
qlcm = 1 # the lcm of the radical denominators
while True:
bstart = b
qstart = qlcm
bb = [] # list of factors
ee = [] # (factor's expo. and it's current value in common_b)
for bi in Mul.make_args(b):
bib, bie = bkey(bi)
if bib not in common_b or common_b[bib] < bie:
ee = bb = [] # failed
break
ee.append([bie, common_b[bib]])
bb.append(bib)
if ee:
# find the number of integral extractions possible
# e.g. [(1, 2), (2, 2)] -> min(2/1, 2/2) -> 1
min1 = ee[0][1] // ee[0][0]
for i in range(1, len(ee)):
rat = ee[i][1] // ee[i][0]
if rat < 1:
break
min1 = min(min1, rat)
else:
# update base factor counts
# e.g. if ee = [(2, 5), (3, 6)] then min1 = 2
# and the new base counts will be 5-2*2 and 6-2*3
for i in range(len(bb)):
common_b[bb[i]] -= min1 * ee[i][0]
update(bb[i])
# update the count of the base
# e.g. x**2*y*sqrt(x*sqrt(y)) the count of x*sqrt(y)
# will increase by 4 to give bkey (x*sqrt(y), 2, 5)
common_b[base] += min1 * qstart * exponent
if (last # no more radicals in base
or len(common_b) == 1 # nothing left to join with
or all(k[1] == 1
for k in common_b) # no rad's in common_b
):
break
# see what we can exponentiate base by to remove any radicals
# so we know what to search for
# e.g. if base were x**(1/2)*y**(1/3) then we should
# exponentiate by 6 and look for powers of x and y in the ratio
# of 2 to 3
qlcm = lcm([ratq(bi) for bi in Mul.make_args(bstart)])
if qlcm == 1:
break # we are done
b = bstart**qlcm
qlcm *= qstart
if all(ratq(bi) == 1 for bi in Mul.make_args(b)):
last = True # we are going to be done after this next pass
# this base no longer can find anything to join with and
# since it was longer than any other we are done with it
b, q = base
done.append((b, common_b.pop(base) * Rational(1, q)))
# update c_powers and get ready to continue with powsimp
c_powers = done
# there may be terms still in common_b that were bases that were
# identified as needing processing, so remove those, too
for (b, q), e in common_b.items():
if (b.is_Pow or isinstance(b, exp)) and \
q is not S.One and not b.exp.is_Rational:
b, be = b.as_base_exp()
b = b**(be / q)
else:
b = root(b, q)
c_powers.append((b, e))
check = len(c_powers)
c_powers = dict(c_powers)
assert len(c_powers) == check # there should have been no duplicates
# ==============================================================
# rebuild the expression
newexpr = expr.func(*(newexpr +
[Pow(b, e) for b, e in c_powers.items()]))
if combine == 'exp':
return expr.func(newexpr, expr.func(*nc_part))
else:
return recurse(expr.func(*nc_part), combine='base') * \
recurse(newexpr, combine='base')
elif combine == 'base':
# Build c_powers and nc_part. These must both be lists not
# dicts because exp's are not combined.
c_powers = []
nc_part = []
for term in expr.args:
if term.is_commutative:
c_powers.append(list(term.as_base_exp()))
else:
nc_part.append(term)
# Pull out numerical coefficients from exponent if assumptions allow
# e.g., 2**(2*x) => 4**x
for i in range(len(c_powers)):
b, e = c_powers[i]
if not (all(x.is_nonnegative for x in b.as_numer_denom())
or e.is_integer or force or b.is_polar):
continue
exp_c, exp_t = e.as_coeff_Mul(rational=True)
if exp_c is not S.One and exp_t is not S.One:
c_powers[i] = [Pow(b, exp_c), exp_t]
# Combine bases whenever they have the same exponent and
# assumptions allow
# first gather the potential bases under the common exponent
c_exp = defaultdict(list)
for b, e in c_powers:
if deep:
e = recurse(e)
c_exp[e].append(b)
del c_powers
# Merge back in the results of the above to form a new product
c_powers = defaultdict(list)
for e in c_exp:
bases = c_exp[e]
# calculate the new base for e
if len(bases) == 1:
new_base = bases[0]
elif e.is_integer or force:
new_base = expr.func(*bases)
else:
# see which ones can be joined
unk = []
nonneg = []
neg = []
for bi in bases:
if bi.is_negative:
neg.append(bi)
elif bi.is_nonnegative:
nonneg.append(bi)
elif bi.is_polar:
nonneg.append(
bi) # polar can be treated like non-negative
else:
unk.append(bi)
if len(unk) == 1 and not neg or len(neg) == 1 and not unk:
# a single neg or a single unk can join the rest
nonneg.extend(unk + neg)
unk = neg = []
elif neg:
# their negative signs cancel in groups of 2*q if we know
# that e = p/q else we have to treat them as unknown
israt = False
if e.is_Rational:
israt = True
else:
p, d = e.as_numer_denom()
if p.is_integer and d.is_integer:
israt = True
if israt:
neg = [-w for w in neg]
unk.extend([S.NegativeOne] * len(neg))
else:
unk.extend(neg)
neg = []
del israt
# these shouldn't be joined
for b in unk:
c_powers[b].append(e)
# here is a new joined base
new_base = expr.func(*(nonneg + neg))
# if there are positive parts they will just get separated
# again unless some change is made
def _terms(e):
# return the number of terms of this expression
# when multiplied out -- assuming no joining of terms
if e.is_Add:
return sum([_terms(ai) for ai in e.args])
if e.is_Mul:
return prod([_terms(mi) for mi in e.args])
return 1
xnew_base = expand_mul(new_base, deep=False)
if len(Add.make_args(xnew_base)) < _terms(new_base):
new_base = factor_terms(xnew_base)
c_powers[new_base].append(e)
# break out the powers from c_powers now
c_part = [Pow(b, ei) for b, e in c_powers.items() for ei in e]
# we're done
return expr.func(*(c_part + nc_part))
else:
raise ValueError("combine must be one of ('all', 'exp', 'base').")
def simplify(expr, ratio=1.7, measure=count_ops, rational=False):
# type: (object, object, object, object) -> object
"""
Simplifies the given expression.
Simplification is not a well defined term and the exact strategies
this function tries can change in the future versions of SymPy. If
your algorithm relies on "simplification" (whatever it is), try to
determine what you need exactly - is it powsimp()?, radsimp()?,
together()?, logcombine()?, or something else? And use this particular
function directly, because those are well defined and thus your algorithm
will be robust.
Nonetheless, especially for interactive use, or when you don't know
anything about the structure of the expression, simplify() tries to apply
intelligent heuristics to make the input expression "simpler". For
example:
>>> from sympy import simplify, cos, sin
>>> from sympy.abc import x, y
>>> a = (x + x**2)/(x*sin(y)**2 + x*cos(y)**2)
>>> a
(x**2 + x)/(x*sin(y)**2 + x*cos(y)**2)
>>> simplify(a)
x + 1
Note that we could have obtained the same result by using specific
simplification functions:
>>> from sympy import trigsimp, cancel
>>> trigsimp(a)
(x**2 + x)/x
>>> cancel(_)
x + 1
In some cases, applying :func:`simplify` may actually result in some more
complicated expression. The default ``ratio=1.7`` prevents more extreme
cases: if (result length)/(input length) > ratio, then input is returned
unmodified. The ``measure`` parameter lets you specify the function used
to determine how complex an expression is. The function should take a
single argument as an expression and return a number such that if
expression ``a`` is more complex than expression ``b``, then
``measure(a) > measure(b)``. The default measure function is
:func:`count_ops`, which returns the total number of operations in the
expression.
For example, if ``ratio=1``, ``simplify`` output can't be longer
than input.
::
>>> from sympy import sqrt, simplify, count_ops, oo
>>> root = 1/(sqrt(2)+3)
Since ``simplify(root)`` would result in a slightly longer expression,
root is returned unchanged instead::
>>> simplify(root, ratio=1) == root
True
If ``ratio=oo``, simplify will be applied anyway::
>>> count_ops(simplify(root, ratio=oo)) > count_ops(root)
True
Note that the shortest expression is not necessary the simplest, so
setting ``ratio`` to 1 may not be a good idea.
Heuristically, the default value ``ratio=1.7`` seems like a reasonable
choice.
You can easily define your own measure function based on what you feel
should represent the "size" or "complexity" of the input expression. Note
that some choices, such as ``lambda expr: len(str(expr))`` may appear to be
good metrics, but have other problems (in this case, the measure function
may slow down simplify too much for very large expressions). If you don't
know what a good metric would be, the default, ``count_ops``, is a good
one.
For example:
>>> from sympy import symbols, log
>>> a, b = symbols('a b', positive=True)
>>> g = log(a) + log(b) + log(a)*log(1/b)
>>> h = simplify(g)
>>> h
log(a*b**(-log(a) + 1))
>>> count_ops(g)
8
>>> count_ops(h)
5
So you can see that ``h`` is simpler than ``g`` using the count_ops metric.
However, we may not like how ``simplify`` (in this case, using
``logcombine``) has created the ``b**(log(1/a) + 1)`` term. A simple way
to reduce this would be to give more weight to powers as operations in
``count_ops``. We can do this by using the ``visual=True`` option:
>>> print(count_ops(g, visual=True))
2*ADD + DIV + 4*LOG + MUL
>>> print(count_ops(h, visual=True))
2*LOG + MUL + POW + SUB
>>> from sympy import Symbol, S
>>> def my_measure(expr):
... POW = Symbol('POW')
... # Discourage powers by giving POW a weight of 10
... count = count_ops(expr, visual=True).subs(POW, 10)
... # Every other operation gets a weight of 1 (the default)
... count = count.replace(Symbol, type(S.One))
... return count
>>> my_measure(g)
8
>>> my_measure(h)
14
>>> 15./8 > 1.7 # 1.7 is the default ratio
True
>>> simplify(g, measure=my_measure)
-log(a)*log(b) + log(a) + log(b)
Note that because ``simplify()`` internally tries many different
simplification strategies and then compares them using the measure
function, we get a completely different result that is still different
from the input expression by doing this.
If rational=True, Floats will be recast as Rationals before simplification.
If rational=None, Floats will be recast as Rationals but the result will
be recast as Floats. If rational=False(default) then nothing will be done
to the Floats.
"""
expr = sympify(expr)
try:
return expr._eval_simplify(ratio=ratio, measure=measure)
except AttributeError:
pass
original_expr = expr = signsimp(expr)
from sympy.simplify.hyperexpand import hyperexpand
from sympy.functions.special.bessel import BesselBase
from sympy import Sum, Product
if not isinstance(expr, Basic) or not expr.args: # XXX: temporary hack
return expr
if not isinstance(expr, (Add, Mul, Pow, ExpBase)):
if isinstance(expr, Function) and hasattr(expr, "inverse"):
if len(expr.args) == 1 and len(expr.args[0].args) == 1 and \
isinstance(expr.args[0], expr.inverse(argindex=1)):
return simplify(expr.args[0].args[0], ratio=ratio,
measure=measure, rational=rational)
return expr.func(*[simplify(x, ratio=ratio, measure=measure, rational=rational)
for x in expr.args])
# TODO: Apply different strategies, considering expression pattern:
# is it a purely rational function? Is there any trigonometric function?...
# See also https://github.com/sympy/sympy/pull/185.
def shorter(*choices):
'''Return the choice that has the fewest ops. In case of a tie,
the expression listed first is selected.'''
if not has_variety(choices):
return choices[0]
return min(choices, key=measure)
# rationalize Floats
floats = False
if rational is not False and expr.has(Float):
floats = True
expr = nsimplify(expr, rational=True)
expr = bottom_up(expr, lambda w: w.normal())
expr = Mul(*powsimp(expr).as_content_primitive())
_e = cancel(expr)
expr1 = shorter(_e, _mexpand(_e).cancel()) # issue 6829
expr2 = shorter(together(expr, deep=True), together(expr1, deep=True))
if ratio is S.Infinity:
expr = expr2
else:
expr = shorter(expr2, expr1, expr)
if not isinstance(expr, Basic): # XXX: temporary hack
return expr
expr = factor_terms(expr, sign=False)
# hyperexpand automatically only works on hypergeometric terms
expr = hyperexpand(expr)
expr = piecewise_fold(expr)
if expr.has(BesselBase):
expr = besselsimp(expr)
if expr.has(TrigonometricFunction, HyperbolicFunction):
expr = trigsimp(expr, deep=True)
if expr.has(log):
expr = shorter(expand_log(expr, deep=True), logcombine(expr))
if expr.has(CombinatorialFunction, gamma):
# expression with gamma functions or non-integer arguments is
# automatically passed to gammasimp
expr = combsimp(expr)
if expr.has(Sum):
expr = sum_simplify(expr)
if expr.has(Product):
expr = product_simplify(expr)
short = shorter(powsimp(expr, combine='exp', deep=True), powsimp(expr), expr)
short = shorter(short, cancel(short))
short = shorter(short, factor_terms(short), expand_power_exp(expand_mul(short)))
if short.has(TrigonometricFunction, HyperbolicFunction, ExpBase):
short = exptrigsimp(short)
# get rid of hollow 2-arg Mul factorization
hollow_mul = Transform(
lambda x: Mul(*x.args),
lambda x:
x.is_Mul and
len(x.args) == 2 and
x.args[0].is_Number and
x.args[1].is_Add and
x.is_commutative)
expr = short.xreplace(hollow_mul)
numer, denom = expr.as_numer_denom()
if denom.is_Add:
n, d = fraction(radsimp(1/denom, symbolic=False, max_terms=1))
if n is not S.One:
expr = (numer*n).expand()/d
if expr.could_extract_minus_sign():
n, d = fraction(expr)
if d != 0:
expr = signsimp(-n/(-d))
if measure(expr) > ratio*measure(original_expr):
expr = original_expr
# restore floats
if floats and rational is None:
expr = nfloat(expr, exponent=False)
return expr
