def test_approver_iscript_case(self):
'''流程审批人for_iscript形式'''
menu1 = '流程'
menu2 = '审批人设置' # 主页打开菜单时使用
menu3 = ''
name = "流程审批人设置_通过iscript形式"
#time.sleep(0.5)
comp = ProcessApproverPage(self.driver)
# 判断是否要删除记录
lp = ListViewPage(self.driver)
lp.judge_delete(name)
#李玲新建单据
self.lilingnew(name)
#退出当前登录，切换账号并打开菜单记录for视图
comp.logoff_and_openrecord('weiqiang', '123456', menu1, menu2, menu3,
name)
comp.direct_sumit() # 直接提交
#退出切换账号，查看是否有提交按钮
bb = comp.logoff_and_check_submitbtn('zhangqiang', '123456', menu1,
menu2, menu3, name)
self.assertEqual("true", bb, msg=name + "检验不通过")
#time.sleep(0.5)
#表单是否已归档
bool = comp.is_filed_for_aftersumbit(name)
self.assertIsNone(bool, msg=name + "检验不通过")
def test_non_polymerization_case(self):
'''流程非聚合'''
menu1 = '流程'
menu2 = '审批送出设置' # 主页打开菜单时使用
menu3 = '流程非聚合'
name = "流程非聚合"
#time.sleep(0.5)
comp = ProcessApproverPage(self.driver)
# 判断是否要删除记录
lp = ListViewPage(self.driver)
lp.judge_delete(name)
#李玲建单提交
comp.launch_a_flowform(name)
#time.sleep(0.5)
#退出当前登录，切换账号并打开菜单记录
comp.logoff_and_openrecord('weiqiang', '123456', menu1, menu2, menu3,
name)
#time.sleep(0.5)
comp.direct_sumit()
#退出当前登录，切换账号并打开菜单记录for表单
comp.logoff_and_openmenu('zjl01', '123456', menu1, menu2, menu3)
text = comp.openagain_to_getapprover(name)
# 断言
self.assertIn('张强', text, msg=name + "检验不通过")
# 判断总经理此时有无提交按钮
bb = comp.is_elementPresent()
self.assertEqual("true", bb, msg=name + "检验不通过")
#time.sleep(0.5)
#提交后判断流程是否已归档
bool = comp.is_filed_for_aftersumbit(name)
self.assertIsNone(bool, msg=name + "检验不通过")
def init(self):
self.test_non_polymerization_case()
def test_editApprover_case(self):
'''允许编辑当前节点的审批人'''
menu1 = '流程'
menu2 = '基本信息' # 主页打开菜单时使用
menu3 = '允许编辑当前节点的审批人'
name = "允许编辑当前节点的审批人"
#time.sleep(0.5)
comp = ProcessApproverPage(self.driver)
# 判断是否要删除记录
lp = ListViewPage(self.driver)
lp.judge_delete(name)
#李玲建单提交
comp.launch_a_flowform(name)
#退出当前登录，切换账号并打开菜单记录
comp.logoff_and_openrecord("zhangqiang", "123456", menu1, menu2, menu3,
name)
#time.sleep(0.5)
comp.select_approver("测试主管")
#time.sleep(0.5)
bool = comp.is_elementPresent()
self.assertEqual("true", bool, msg=name + "检验不通过")
#time.sleep(0.5)
#退出当前登录，切换账号并打开菜单记录
comp.logoff_and_openrecord("weiqiang", "123456", menu1, menu2, menu3,
name)
#提交后判断流程是否已归档
bool = comp.is_filed_for_aftersumbit(name)
self.assertIsNone(bool, msg=name + "检验不通过")
def init(self):
self.test_editApprover_case()
def test_termination_case(self):
'''允许审批人终止流程'''
menu1 = '流程'
menu2 = '基本信息' # 主页打开菜单时使用
menu3 = '允许审批人终止流程'
name = "允许审批人终止流程"
#time.sleep(0.5)
comp = ProcessApproverPage(self.driver)
# 判断是否要删除记录
lp = ListViewPage(self.driver)
lp.judge_delete(name)
#李玲建单提交
comp.launch_a_flowform(name)
#退出当前登录，切换账号并打开菜单记录for视图
comp.logoff_and_openrecord("zhangqiang", "123456",menu1, menu2, menu3,name)
#time.sleep(0.5)
comp.click_terminationbtn() #点击终止按钮
#time.sleep(0.5)
# 判段是否已归档
bool = comp.is_filed()
self.assertIsNone(bool, msg=name + "检验不通过")
def init(self):
self.test_termination_case()
def test_polymerization_case(self):
'''流程聚合'''
menu1 = '流程'
menu2 = '审批送出设置' # 主页打开菜单时使用
menu3 = '流程聚合'
name = "流程聚合"
#time.sleep(0.5)
comp = ProcessApproverPage(self.driver)
#判断是否要删除记录
lp = ListViewPage(self.driver)
lp.judge_delete(name)
#李玲建单提交
comp.launch_a_flowform(name)
#time.sleep(0.5)
#退出当前登录，切换账号并打开菜单记录for视图
comp.logoff_and_openrecord('weiqiang', '123456', menu1, menu2, menu3,
name)
#time.sleep(0.5)
comp.direct_sumit()
#再次打开记录获取流程状态处理人
text = comp.openagain_to_getapprover(name)
self.assertIn('张强', text, msg=name + "检验不通过")
#退出切换账号，查看是否有提交按钮
bb = comp.logoff_and_check_submitbtn('zjl01', '123456', menu1, menu2,
menu3, name)
self.assertEqual("false", bb, msg=name + "检验不通过")
# 退出当前登录，切换账号并打开菜单记录for视图
comp.logoff_and_openrecord('zhangqiang', '123456', menu1, menu2, menu3,
name)
#time.sleep(0.5)
comp.direct_sumit()
#time.sleep(0.5)
# 退出当前登录，切换账号并打开菜单记录for视图
comp.logoff_and_openrecord('zjl01', '123456', menu1, menu2, menu3,
name)
#time.sleep(0.5)
#表单是否已归档
bool2 = comp.is_filed_for_aftersumbit(name)
self.assertIsNone(bool2, msg=name + "检验不通过")