def print_python(self, ast, early=False):
self.indent()
code = ast.code.source
if code[0] == '\n':
code = code[1:]
self.write("python")
if early:
self.write(" early")
if ast.hide:
self.write(" hide")
if hasattr(ast, "store") and ast.store != "store":
self.write(" in ")
# Strip prepended "store."
self.write(ast.store[6:])
self.write(":")
self.indent_level += 1
for line in split_logical_lines(code):
self.indent()
self.write(line)
self.indent_level -= 1
else:
self.write("$ %s" % code)
def print_python(self, ast, early=False):
self.indent()
code = ast.code.source
if code[0] == '\n':
code = code[1:]
self.write("python")
if early:
self.write(" early")
if ast.hide:
self.write(" hide")
if hasattr(ast, "store") and ast.store != "store":
self.write(" in ")
# Strip prepended "store."
self.write(ast.store[6:])
self.write(":")
self.indent_level += 1
for line in split_logical_lines(code):
self.indent()
self.write(line)
self.indent_level -= 1
else:
self.write("$ %s" % code)
def print_python(self, ast):
self.indent()
code = ast.code.source
if code[0] == "\n":
self.write("python:")
with self.increase_indent():
self.write_lines(split_logical_lines(code[1:]))
else:
self.write("$ %s" % code)
def print_python(self, ast):
self.indent()
code = ast.code.source
if code[0] == '\n':
self.write("python:")
with self.increase_indent():
self.write_lines(split_logical_lines(code[1:]))
else:
self.write("$ %s" % code)
def print_python(self, header, code):
# This function handles any statement which is a block but couldn't logically be
# Translated to a screen statement.
#
# Ren'Py's line numbers are really, really buggy. Here's a summary:
# If we're not directly under the root screen, and a keyword for our
# parent follows us, then all of our line numbers will be equal to the
# line number of that keyword.
# If we're not directly under the root screen, and no keywords for our
# parent follow us, then header.lineno is the line number of whatever
# it is that preceded us (which is completely useless).
# If we're directly under the root "screen", then header.lineno is the
# line that "$" or "python:" appeared on.
# If we're not a child followed by a keyword, and "$" was used, then
# code[0].lineno is the line that the code actually starts on, but if
# "python:" was used, then all of code's line numbers will be 1 greater
# than the line each one should be.
source = self.to_source(
ast.Module(body=code, lineno=code[0].lineno,
col_offset=0)).rstrip()
lines = source.splitlines()
if len(split_logical_lines(source)) == 1 and (
not self.match_line_numbers or
(not self.is_root and code[0].lineno < self.linenumber + 3)
or header.lineno >= code[0].lineno):
# This is only one logical line, so it's possible that it was $,
# and either it's not in the root (so we don't know what the
# original source used), or it is in the root and we know it used $.
# Also, if we don't know for sure what was used, but we have enough
# room to use a "python" block, then use it instead, since it'll
# result in everything taking up one fewer line (since it'll use
# one more, but start two sooner).
self.advance_to_line(code[0].lineno)
self.indent()
self.write("$ %s" % lines[0])
for line in lines[1:]:
self.indent()
self.write(line)
else:
# Either this is more than one logical line, so it has to be a
# python block, or it was in the root and we can tell that it was
# originally a python block.
if self.is_root:
self.advance_to_line(header.lineno)
self.indent()
self.write("python:")
self.advance_to_line(code[0].lineno - 1)
self.indent_level += 1
for line in lines:
self.indent()
self.write(line)
self.indent_level -= 1
def print_python(self, ast):
self.indent()
# Extract the source code from the slast.SLPython object. If it starts with a
# newline, print it as a python block, else, print it as a $ statement
code = ast.code.source
if code[0] == "\n":
code = code[1:]
self.write("python:")
with self.increase_indent():
self.write_lines(split_logical_lines(code))
else:
self.write("$ %s" % code)
def print_python(self, ast):
self.indent()
# Extract the source code from the slast.SLPython object. If it starts with a
# newline, print it as a python block, else, print it as a $ statement
code = ast.code.source
if code[0] == "\n":
code = code[1:]
self.write("python:")
with self.increase_indent():
self.write_lines(split_logical_lines(code))
else:
self.write("$ %s" % code)
def print_python(self, header, code):
# This function handles any statement which is a block but couldn't logically be
# Translated to a screen statement.
#
# Ren'Py's line numbers are really, really buggy. Here's a summary:
# If we're not directly under the root screen, and a keyword for our
# parent follows us, then all of our line numbers will be equal to the
# line number of that keyword.
# If we're not directly under the root screen, and no keywords for our
# parent follow us, then header.lineno is the line number of whatever
# it is that preceded us (which is completely useless).
# If we're directly under the root "screen", then header.lineno is the
# line that "$" or "python:" appeared on.
# If we're not a child followed by a keyword, and "$" was used, then
# code[0].lineno is the line that the code actually starts on, but if
# "python:" was used, then all of code's line numbers will be 1 greater
# than the line each one should be.
source = self.to_source(ast.Module(body=code,
lineno=code[0].lineno,
col_offset=0)).rstrip()
lines = source.splitlines()
if len(split_logical_lines(source)) == 1 and (not self.match_line_numbers or
(not self.is_root and code[0].lineno < self.linenumber + 3) or
header.lineno >= code[0].lineno):
# This is only one logical line, so it's possible that it was $,
# and either it's not in the root (so we don't know what the
# original source used), or it is in the root and we know it used $.
# Also, if we don't know for sure what was used, but we have enough
# room to use a "python" block, then use it instead, since it'll
# result in everything taking up one fewer line (since it'll use
# one more, but start two sooner).
self.advance_to_line(code[0].lineno)
self.indent()
self.write("$ %s" % lines[0])
for line in lines[1:]:
self.indent()
self.write(line)
else:
# Either this is more than one logical line, so it has to be a
# python block, or it was in the root and we can tell that it was
# originally a python block.
if self.is_root:
self.advance_to_line(header.lineno)
self.indent()
self.write("python:")
self.advance_to_line(code[0].lineno - 1)
self.indent_level += 1
for line in lines:
self.indent()
self.write(line)
self.indent_level -= 1