def test_it_moves(self):
origin_pointer = Pointer(self.dictionary)
pointer = origin_pointer.move('result').move('items').move(0).move('id')
self.assertEqual(pointer.path(), '#.result.items[0].id')
self.assertEqual(pointer.value(), self.dictionary['result']['items'][0]['id'])
self.assertEqual(origin_pointer.path(), '#')
self.assertEqual(origin_pointer.value(), self.dictionary)
def test_it_moves(self):
origin_pointer = Pointer(self.dictionary)
pointer = origin_pointer.move('result').move('items').move(0).move(
'id')
self.assertEqual(pointer.path(), '#.result.items[0].id')
self.assertEqual(pointer.value(),
self.dictionary['result']['items'][0]['id'])
self.assertEqual(origin_pointer.path(), '#')
self.assertEqual(origin_pointer.value(), self.dictionary)
def test_it_returns_path(self):
pointer = Pointer(self.dictionary)
self.assertEqual(pointer.path(), '#')
pointer = Pointer(self.dictionary, ['result'])
self.assertEqual(pointer.path(), '#.result')
pointer = Pointer(self.dictionary, ['result', 'total'])
self.assertEqual(pointer.path(), '#.result.total')
pointer = Pointer(self.dictionary, ['result', 'items'])
self.assertEqual(pointer.path(), '#.result.items')
pointer = Pointer(self.dictionary, ['result', 'items', 0])
self.assertEqual(pointer.path(), '#.result.items[0]')
pointer = Pointer(self.dictionary, ['result', 'items', 0, 'id'])
self.assertEqual(pointer.path(), '#.result.items[0].id')
def test_it_returns_path(self):
pointer = Pointer(self.dictionary)
self.assertEqual(pointer.path(), '#')
pointer = Pointer(self.dictionary, ['result'])
self.assertEqual(pointer.path(), '#.result')
pointer = Pointer(self.dictionary, ['result', 'total'])
self.assertEqual(pointer.path(), '#.result.total')
pointer = Pointer(self.dictionary, ['result', 'items'])
self.assertEqual(pointer.path(), '#.result.items')
pointer = Pointer(self.dictionary, ['result', 'items', 0])
self.assertEqual(pointer.path(), '#.result.items[0]')
pointer = Pointer(self.dictionary, ['result', 'items', 0, 'id'])
self.assertEqual(pointer.path(), '#.result.items[0].id')