Esempio n. 1
0
def infix_to_postfix(infix_expr):
    precedence = {}
    precedence["*"] = 3
    precedence["/"] = 3
    precedence["+"] = 2
    precedence["-"] = 2
    precedence["("] = 1
    op_stack = Stack()
    postfix_list = []
    token_list = infix_expr.split()

    for token in token_list:
        if token in "ABCDEFGHIJKLLMNOPQRSTUVWXYZ" or token in "0123456789":
            postfix_list.append(token)
        elif token == '(':
            op_stack.push(token)
        elif token == ')':
            top_token = op_stack.pop()
            while top_token != '(':
                postfix_list.append(top_token)
                top_token = op_stack.pop()
        else:
            while (not op_stack.is_empty()) and (precedence[op_stack.peek()] >= precedence[token]):
                postfix_list.append(op_stack.pop())
            op_stack.push(token)

    while not op_stack.is_empty():
        postfix_list.append(op_stack.pop())
    return "".join(postfix_list)
Esempio n. 2
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def postfix_eval(postfix_expr):
    operand_stack = Stack()
    token_list = postfix_expr.split()

    for token in token_list:
        if token in "0123456789":
            operand_stack.push(token)
        else:
            operand2 = operand_stack.pop()
            operand1 = operand_stack.pop()
            result = do_math(token, int(operand1), int(operand2))
            operand_stack.push(result)
    return operand_stack.pop()
Esempio n. 3
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def par_checker(symbol_string):
    s = Stack()
    balanced = True
    index = 0
    while index < len(symbol_string) and balanced:
        symbol = symbol_string[index]
        if symbol == '(':
            s.push(symbol)
        else:
            if s.is_empty():
                balanced = False
            else:
                s.pop()

        index += 1

    return balanced and s.is_empty()
Esempio n. 4
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def divide_by_2(dec_number):
    rem_stack = Stack()

    while dec_number > 0:
        rem = dec_number % 2
        rem_stack.push(rem)
        dec_number //= 2  # // integer division

    bin_string = ""
    while not rem_stack.is_empty():
        bin_string += str(rem_stack.pop())

    return bin_string
Esempio n. 5
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def base_converter(dec_number, base):
    rem_stack = Stack()

    while dec_number > 0:
        rem = dec_number % base
        rem_stack.push(rem)
        dec_number //= base  # // integer division

    base_string = ""
    while not rem_stack.is_empty():
        base_string += str(rem_stack.pop())

    return base_string
Esempio n. 6
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def build_parse_tree(mathexp):
    tokens = mathexp.split()
    p_stack = Stack()
    e_tree = BinaryTree('')
    p_stack.push(e_tree)
    curr = e_tree
    for t in tokens:
        if t == '(':
            curr.insert_left('')
            p_stack.push(curr)
            curr = curr.get_left_child()
        elif t not in ['+', '-', '*', '/', ')']:
            curr.set_root_val(int(t))
            curr = p_stack.pop()
        elif t in ['+', '-', '*', '/']:
            curr.set_root_val(t)
            curr.insert_right('')
            p_stack.push(curr)
            curr = curr.get_right_child()
        elif t == ')':
            curr = p_stack.pop()
        else:
            raise ValueError
    return e_tree
Esempio n. 7
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def par_checker(symbol_string):
    s = Stack()
    balanced = True
    index = 0
    while index < len(symbol_string) and balanced:
        symbol = symbol_string[index]
        if symbol in '([{':
            s.push(symbol)
        else:
            if s.is_empty():
                balanced = False
            else:
                top = s.pop()
                if not matches(top, symbol):
                    balanced = False
        index += 1
    return balanced and s.is_empty()
Esempio n. 8
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def aStarSearch(prob):  # A* search
    pq = PriorityQueue()  # hang doi uu tien
    occ = {}  # dung de kiem tra xem mot state co duoc expand chua
    dist = {}  # so luong step can de di tu start den cac node
    traverse = {}  # dung de truy vet
    startState = prob.getStartState()  # trang thai ban dau
    start = startState.getPacmanPosition(
    )  # vi tri ban dau cua pacman, cung la vi tri cua S
    dist[start] = 0  # so luong step can de di tu start den goal la 0
    pq.push(start, prob.getScore(start))
    top = 0  # khai bao bien lay top cua priority queue
    while pq.isEmpty() is False:  # lap cho den khi goal node duoc expand
        top = pq.pop()
        if prob.isGoalState(
                top):  # kiem tra xem co phai la trang thai ket thuc
            break
        if occ.get(top, 0) != 0:  # kiem tra mot trang thai co duoc expand chua
            continue
        occ[top] = 1
        successors = prob.getChilds(top)
        for s in successors:
            # Neu TH1) trang thai hien tai chua tung duoc explore ,
            # hay TH2) duoc explore roi nhung chua duoc expand va so step moi
            # nho hon so step cu de di duoc den trang thai nay
            if (dist.get(s, -1) == -1) or (occ.get(s, 0) == 0
                                           and dist[s] > dist[top] + 1):
                dist[s] = dist[top] + 1
                traverse[s] = top
                pq.push(s, dist[s] + prob.getScore(s))
    if prob.isGoalState(top) is False:
        return -1
    q = Stack(
    )  # Tu day cho den het function nay la de lay list cac step de di tu S den G
    node = top
    while traverse.get(node, -1) != -1:
        q.push(node)
        node = traverse[node]
    q.push(node)
    path = []
    while q.isEmpty() is False:
        top = q.pop()
        path.append(top)
    return path