def sol():
sol = ('''let ''' + n1 + ''' has ''' + latex('x') + ''' litres of ''' +
i + '''.
<br/>Since, ''' + n2 + ''' has ''' + (r10_latex) + ''' times the ''' + i +
''' that ''' + n1 + ''' has
<br/>Therefore, ''' + n2 + ''' will have (''' + r10_latex + ''')* ''' +
latex('x') + ''' litres of ''' + i + '''.
<br/>Since, ''' + n1 + ''' and ''' + n2 + ''' have a total of ''' +
latex(str(r1)) + ''' litres of ''' + i + '''
<br/>=>''' + latex('''x+(''') + r10_latex +
latex(''')*x=''' + str(r1)) + '''
<br/>Taking ''' + latex('x') +
''' common from both the terms in L.H.S :-
<br/>=> ''' + latex('''(1+''') + r10_latex +
latex(''')*x=''' + str(r1))) + "\n"
sol = sol + (" <br/> => " +
latex("(" + to_frac(str(r2 + r9), str(r9)) + ")* x =" +
str(r1))) + "\n"
a = r10 + 1
sol = sol + ("<br/>Dividing both the sides by " +
latex(to_frac(str(r2 + r9), str(r9)))) + "\n"
sol = sol + (" <br/> => " +
latex("x=" + to_frac(str(r1), str(a)))) + "\n"
sol = sol + (" <br/> => " + latex("x=" + str(r1 / a))) + "\n"
b = Fraction((r2 + r9), (r9))
sol = sol + (" <br/> => " + latex("(") + r10_latex +
latex(")*x = (") + r10_latex +
latex(")*(" + to_frac(str(r1), str(b)) + ")=" + str(
(r1 / a) * r10))) + "\n"
sol = sol + ('<br/>Hence, ' + n1 + ' has ' + latex(str(
(r1 / a))) + ' litres of ' + i + ' and ' + n2 + ' has ' +
latex(str(
((r1 / a) * r10))) + ' litres of ' + i + ' ') + "\n"
return sol
def sol():
sol1 = latex(str(r1) + r2 + " = " + str(r3)) + "\n"
sol1 = sol1 + latex(
to_frac(str(r1) + r2, str(r1)) + " = " + to_frac(str(r3), str(r1))
) + " (Dividing " + str(r1) + " on both sides)" + "\n"
sol1 = sol1 + latex(r2 + " = " + to_frac(str(r3), str(r1))) + "\n"
sol1 = sol1 + latex(r2 + " = " + str(r3 / r1))
return sol1
def sol():
sol = ('''let ''' + n1 + ''' has ''' + latex('x') + ''' ''' + i + '''.
<br/>Since, ''' + n2 + ''' has ''' + latex(str(r2)) + ''' less ''' + i +
''' than ''' + n1 + '''
<br/>Therefore, ''' + n2 + ''' will have ''' + latex('x') + '''-''' +
latex(str(r2)) + ''' ''' + i + '''.
<br/>Since, ''' + n1 + ''' and ''' + n2 + ''' have a total of ''' +
str(r1) + ''' ''' + i + '''
<br/>=> ''' + latex('''x+(x-''' + str(r2) + ''')=''' + str(r1)) + '''
<br/>=> ''' + latex('''x+x-''' + str(r2) + '''=''' + str(r1)) + '''
<br/>=> ''' + latex('''2x-''' + str(r2) + '''=''' + str(r1)))
sol = sol + ("<br/>=> " +
latex("2x=" + str(r1) + "+" + str(r2))) + "\n"
a = r1 + r2
sol = sol + ("<br/>Dividing both the sides by 2") + "\n"
sol = sol + ("<br/>=> " + latex("x=" + to_frac(str(a), "2"))) + "\n"
sol = sol + ("<br/>=> " + latex("x=" + str(int(a / 2)))) + "\n"
sol = sol + ("<br/>=> " +
latex("x-" + str(r2) + "=" + str(int(a / 2)) + "-" +
str(r2) + "=" + str(int((a / 2 - r2))))) + "\n"
sol = sol + ('<br/>Hence, ' + n1 + ' has ' + latex(str(int(a / 2))) +
' ' + i + ' and ' + n2 + ' has ' +
latex(str(int((a / 2 - r2)))) + ' ' + i + ' ')
return sol
def sol():
sol = ('''let us assume ''' + n1 + ''' has ''' + latex('x') + ''' ''' +
i + '''.
<br/>Since, ''' + n2 + ''' has ''' + latex(str(r2)) + ''' times the ''' +
i + ''' that ''' + n1 + ''' has
<br/>Therefore, ''' + n2 + ''' will have ''' + latex(str(r2) + '''*x ''') +
" " + i + '''.
<br/>Since, ''' + n1 + ''' and ''' + n2 + ''' have a total of ''' +
latex(str(r1)) + ''' ''' + i + '''
<br/> => ''' + latex(''' x+(''' + str(r2) + '''*x)=''' + str(r1)) + '''
<br/> => ''' + latex(''' x + ''' + str(r2) + '''x =''' + str(r1)))
sol = sol + ("<br/>=> " +
latex(" (" + str(r2 + 1) + ")* x=" + str(r1))) + "\n"
a = r2 + 1
sol = sol + ("<br/>Dividing both the sides by " + latex(str(a))) + "\n"
sol = sol + ("<br/>=> " +
latex("x=" + to_frac(str(r1), str(a)))) + "\n"
sol = sol + ("<br/>=> " + latex("x=" + str(int(r1 / a)))) + "\n"
sol = sol + ("<br/>=> " + latex("(" + str(r2) + ")*x=(" + str(r2) +
")*" + str(int(r1 / a)) + "=" +
str(int((r1 / a) * r2)))) + "\n"
sol = sol + ('<br/>Hence, ' + n1 + ' has ' + latex(str(int(r1 / a))) +
' ' + i + ' and ' + n2 + ' has ' +
latex(str(int((r1 / a) * r2))) + ' ' + i + ' ')
return sol
def sol():
sol = ("solution: \n")
sol = sol + (latex(str(r1) + "x - " + str(r2) + " = " +
str(r3))) + "\n"
sol = sol + str(
latex(str(r1) + "x = " + str(r3) + " + " + str(r2)) +
" (adding " + str(r2) + " to both sides)") + "\n"
sol = sol + str(latex(str(r1) + "x = " + str(y))) + "\n"
sol = sol + str(
latex("x = " + to_frac(str(y), str(r1))) + " (dividing by " +
str(r1) + " in both sides)") + "\n"
sol = sol + str(latex("x = " + str(x))) + "\n"
return sol
def main_function():
n1 = randomMarathi()
n2 = randomMarathi()
r2 = random.randint(1, 5)
r9 = random.randint(2, 7)
if r2 % r9 == 0:
r9 = r9 + 1
if r2 > r9:
r2, r9 = r9, r2
r10_latex = latex(to_frac(str(r2), str(r9)))
r10 = Fraction(r2, r9)
r1 = random.randint(10, 60)
#option 4
c = (r1) / (r10 + 1)
d = c * r10
#option 1
r3 = random.randint(10, 30)
#options should not be same
if r3 == c or r3 == d:
r3 = r3 + 1
r4 = abs(r1 - r3)
if r3 == r1:
r3 = r3 - 15
r4 = 15
#option 2
r5 = random.randint(10, 30)
#options should not be same
if r5 == c:
r5 = r5 + 1
r6 = r10 * r5
#option 3
r7 = d
r8 = c
items = [
'Lemonade', 'Tea', 'Coffee', 'Milk', 'Orange juice', 'Mango juice',
'water', 'Soup', 'Soft drink', 'Oil', 'Apple juice'
]
i = random.choice(items)
temp1 = n1 + ' and ' + n2 + ' have a total of ' + str(
r1) + ' litres of ' + i + '. '
r = random.randint(1, 5)
if r > 3:
n1, n2 = n2, n1
temp2 = 'If ' + n2 + ' has ' + str(
r10_latex
) + ' times the ' + i + ' that ' + n1 + ' has, how many litres of ' + i + ' does each one have?\n'
question = temp1 + temp2
print(question)
op = ["", "", "", ""]
sq = [0, 1, 2, 3]
#option variables
o1 = n1 + ''' has ''' + latex(str((
r3))) + ''' litres of ''' + i + ''' and ''' + n2 + ''' has ''' + latex(
str((r4))) + ''' litres of ''' + i
o2 = n1 + ''' has ''' + latex(str((
r5))) + ''' litres of ''' + i + ''' and ''' + n2 + ''' has ''' + latex(
str((r6))) + ''' litres of ''' + i
o3 = n1 + ''' has ''' + latex(str(
(c))) + ''' litres of ''' + i + ''' and ''' + n2 + ''' has ''' + latex(
str((d))) + ''' litres of ''' + i
o4 = n1 + ''' has ''' + latex(str((
r7))) + ''' litres of ''' + i + ''' and ''' + n2 + ''' has ''' + latex(
str((r8))) + ''' litres of ''' + i
ra = random.randint(0, 3)
op[ra] = o3
sq.remove(ra)
op[sq[0]] = o1
op[sq[1]] = o2
op[sq[2]] = o4
#PRINTING OPTIONS
for z in range(1, 5):
print("Option", z, ":", op[z - 1])
print("")
value = 3 #int(input("Enter the option number : "))
#solution function
def sol():
sol = ('''let ''' + n1 + ''' has ''' + latex('x') + ''' litres of ''' +
i + '''.
<br/>Since, ''' + n2 + ''' has ''' + (r10_latex) + ''' times the ''' + i +
''' that ''' + n1 + ''' has
<br/>Therefore, ''' + n2 + ''' will have (''' + r10_latex + ''')* ''' +
latex('x') + ''' litres of ''' + i + '''.
<br/>Since, ''' + n1 + ''' and ''' + n2 + ''' have a total of ''' +
latex(str(r1)) + ''' litres of ''' + i + '''
<br/>=>''' + latex('''x+(''') + r10_latex +
latex(''')*x=''' + str(r1)) + '''
<br/>Taking ''' + latex('x') +
''' common from both the terms in L.H.S :-
<br/>=> ''' + latex('''(1+''') + r10_latex +
latex(''')*x=''' + str(r1))) + "\n"
sol = sol + (" <br/> => " +
latex("(" + to_frac(str(r2 + r9), str(r9)) + ")* x =" +
str(r1))) + "\n"
a = r10 + 1
sol = sol + ("<br/>Dividing both the sides by " +
latex(to_frac(str(r2 + r9), str(r9)))) + "\n"
sol = sol + (" <br/> => " +
latex("x=" + to_frac(str(r1), str(a)))) + "\n"
sol = sol + (" <br/> => " + latex("x=" + str(r1 / a))) + "\n"
b = Fraction((r2 + r9), (r9))
sol = sol + (" <br/> => " + latex("(") + r10_latex +
latex(")*x = (") + r10_latex +
latex(")*(" + to_frac(str(r1), str(b)) + ")=" + str(
(r1 / a) * r10))) + "\n"
sol = sol + ('<br/>Hence, ' + n1 + ' has ' + latex(str(
(r1 / a))) + ' litres of ' + i + ' and ' + n2 + ' has ' +
latex(str(
((r1 / a) * r10))) + ' litres of ' + i + ' ') + "\n"
return sol
if value == ra + 1:
print("\nYour answer is Correct!")
print(">------------- SOLUTION -------------<")
print(sol())
elif value != ra + 1 and value < 5 and value > 0:
print("\nYour answer is incorrect!")
print(">------------- SOLUTION --------------<")
print(sol())
else:
print("invalid choice")
database_dict = database_fn(Answer_Type='1',
Topic_Number='030203',
Variation='v3_12',
Question=question,
Correct_Answer_1=o3,
Wrong_Answer_1=o1,
Wrong_Answer_2=o2,
Wrong_Answer_3=o4,
ContributorMail='*****@*****.**',
Solution_text=sol())
return database_dict
def sol4():
sol4=("Since, it is given that the weights of "+n1+", "+n2+", "+n3+" and "+n4+"\nare "+latex(str(r1))+", "+latex(str(r2))+", "+latex(str(r3))+" and "+latex(str(r4))+" respectively")+"\n"
if r1/r2==r3/r4:
a="{:.2f}".format(r1/r2)
b="{:.2f}".format(r3/r4)
sol4=sol4+("Now, "+latex(to_frac(str(r1),str(r2))+" = "+str(a)))+"\n"
sol4=sol4+("Also, "+latex(to_frac(str(r3),str(r4))+" = "+str(b)))+"\n"
sol4=sol4+("=> "+latex(to_frac(str(r1),str(r2))+" = "+to_frac(str(r3),str(r4))))+"\n"
sol4=sol4+("=> L.H.S = R.H.S")+"\n"
sol4=sol4+("As we know that,\nAn Equation is a mathematical statement consisting of an equal symbol between two expressions having the same value.")+"\n"
sol4=sol4+("Therefore, according to the question,\nThe two pairs which will form an equation are : "+n1+" and "+n2+" , "+n3+" and "+n4)+"\n"
elif r2/r1==r4/r3:
a="{:.2f}".format(r2/r1)
b="{:.2f}".format(r4/r3)
sol4=sol4+("Now, "+latex(to_frac(str(r2),str(r1))+" = "+str(a)))+"\n"
sol4=sol4+("Also, "+latex(to_frac(str(r4),str(r3))+" = "+str(b)))+"\n"
sol4=sol4+("=> "+latex(to_frac(str(r2),str(r1))+" = "+to_frac(str(r4),str(r3))))+"\n"
sol4=sol4+("=> L.H.S = R.H.S")+"\n"
sol4=sol4+("As we know that,\nAn Equation is a mathematical statement consisting of an equal symbol between two expressions having the same value.")+"\n"
sol4=sol4+("Therefore, according to the question,\nThe two pairs which will form an equation are : "+n1+" and "+n2+" , "+n3+" and "+n4)+"\n"
elif r1/r2==r4/r3:
a="{:.2f}".format(r1/r2)
b="{:.2f}".format(r4/r3)
sol4=sol4+("Now, "+latex(to_frac(str(r1),str(r2))+" = "+str(a)))+"\n"
sol4=sol4+("Also, "+latex(to_frac(str(r4),str(r3))+" = "+str(b)))+"\n"
sol4=sol4+("=> "+latex(to_frac(str(r1),str(r2))+" = "+to_frac(str(r4),str(r3))))+"\n"
sol4=sol4+("=> L.H.S = R.H.S")+"\n"
sol4=sol4+("As we know that,\nAn Equation is a mathematical statement consisting of an equal symbol between two expressions having the same value.")+"\n"
sol4=sol4+("Therefore, according to the question,\nThe two pairs which will form an equation are : "+n1+" and "+n2+" , "+n3+" and "+n4)+"\n"
elif r2/r1==r3/r4:
a="{:.2f}".format(r2/r1)
b="{:.2f}".format(r3/r4)
sol4=sol4+("Now, "+latex(to_frac(str(r2),str(r1))+" = "+str(a)))+"\n"
sol4=sol4+("Also, "+latex(to_frac(str(r3),str(r4))+" = "+str(b)))+"\n"
sol4=sol4+("=> "+latex(to_frac(str(r2),str(r1))+" = "+to_frac(str(r3),str(r4))))+"\n"
sol4=sol4+("=> L.H.S = R.H.S")+"\n"
sol4=sol4+("As we know that,\nAn Equation is a mathematical statement consisting of an equal symbol between two expressions having the same value.")+"\n"
sol4=sol4+("Therefore, according to the question,\nThe two pairs which will form an equation are : "+n1+" and "+n2+" , "+n3+" and "+n4)+"\n"
elif r1/r3==r2/r4:
a="{:.2f}".format(r1/r3)
b="{:.2f}".format(r2/r4)
sol4=sol4+("Now, "+latex(to_frac(str(r1),str(r3))+" = "+str(a)))+"\n"
sol4=sol4+("Also, "+latex(to_frac(str(r2),str(r4))+" = "+str(b)))+"\n"
sol4=sol4+("=> "+latex(to_frac(str(r1),str(r3))+" = "+to_frac(str(r2),str(r4))))+"\n"
sol4=sol4+("=> L.H.S = R.H.S")+"\n"
sol4=sol4+("As we know that,\nAn Equation is a mathematical statement consisting of an equal symbol between two expressions having the same value.")+"\n"
sol4=sol4+("Therefore, according to the question,\nThe two pairs which will form an equation are : "+n1+" and "+n3+" , "+n2+" and "+n4)+"\n"
elif r3/r1==r4/r2:
a="{:.2f}".format(r3/r1)
b="{:.2f}".format(r4/r2)
sol4=sol4+("Now, "+latex(to_frac(str(r3),str(r1))+" = "+str(a)))+"\n"
sol4=sol4+("Also, "+latex(to_frac(str(r4),str(r2))+" = "+str(b)))+"\n"
sol4=sol4+("=> "+latex(to_frac(str(r3),str(r1))+" = "+to_frac(str(r4),str(r2))))+"\n"
sol4=sol4+("=> L.H.S = R.H.S")+"\n"
sol4=sol4+("As we know that,\nAn Equation is a mathematical statement consisting of an equal symbol between two expressions having the same value.")+"\n"
sol4=sol4+("Therefore, according to the question,\nThe two pairs which will form an equation are : "+n1+" and "+n3+" , "+n2+" and "+n4)+"\n"
elif r1/r3==r4/r2:
a="{:.2f}".format(r1/r3)
b="{:.2f}".format(r4/r2)
sol4=sol4+("Now, "+latex(to_frac(str(r1),str(r3))+" = "+str(a)))+"\n"
sol4=sol4+("Also, "+latex(to_frac(str(r4),str(r2))+" = "+str(b)))+"\n"
sol4=sol4+("=> "+latex(to_frac(str(r1),str(r3))+" = "+to_frac(str(r4),str(r2))))+"\n"
sol4=sol4+("=> L.H.S = R.H.S")+"\n"
sol4=sol4+("As we know that,\nAn Equation is a mathematical statement consisting of an equal symbol between two expressions having the same value.")+"\n"
sol4=sol4+("Therefore, according to the question,\nThe two pairs which will form an equation are : "+n1+" and "+n3+" , "+n2+" and "+n4)+"\n"
elif r3/r1==r2/r4:
a="{:.2f}".format(r3/r1)+"\n"
b="{:.2f}".format(r2/r4)+"\n"
sol4=sol4+("Now, "+latex(to_frac(str(r3),str(r1))+" = "+str(a)))+"\n"
sol4=sol4+("Also,"+latex(to_frac(str(r2),str(r4))+" = "+str(b)))+"\n"
sol4=sol4+("=> "+latex(to_frac(str(r3),str(r1))+" = "+to_frac(str(r2),str(r4))))+"\n"
sol4=sol4+("=> L.H.S = R.H.S")+"\n"
sol4=sol4+("As we know that,\nAn Equation is a mathematical statement consisting of an equal symbol between two expressions having the same value.")+"\n"
sol4=sol4+("Therefore, according to the question,\nThe two pairs which will form an equation are : "+n1+" and "+n3+" , "+n2+" and "+n4)+"\n"
elif r1/r4==r2/r3:
a="{:.2f}".format(r1/r4)
b="{:.2f}".format(r2/r3)
sol4=sol4+("Now, "+latex(to_frac(str(r1),str(r4))+" = "+str(a)))+"\n"
sol4=sol4+("Also, "+latex(to_frac(str(r2),str(r3))+" = "+str(b)))+"\n"
sol4=sol4+("=> "+latex(to_frac(str(r1),str(r4))+" = "+to_frac(str(r2),str(r3))))+"\n"
sol4=sol4+("=> L.H.S = R.H.S")+"\n"
sol4=sol4+("As we know that,\nAn Equation is a mathematical statement consisting of an equal symbol between two expressions having the same value.")+"\n"
sol4=sol4+("Therefore, according to the question,\nThe two pairs which will form an equation are : "+n1+" and "+n4+" , "+n2+" and "+n3)+"\n"
elif r4/r1==r3/r2:
a="{:.2f}".format(r4/r1)
b="{:.2f}".format(r3/r2)
sol4=sol4+("Now, "+latex(to_frac(str(r4),str(r1))+" = "+str(a)))+"\n"
sol4=sol4+("Also, "+latex(to_frac(str(r3),str(r2))+" = "+str(b)))+"\n"
sol4=sol4+("=> "+latex(to_frac(str(r4),str(r1))+" = "+to_frac(str(r3),str(r2))))+"\n"
sol4=sol4+("=> L.H.S = R.H.S")+"\n"
sol4=sol4+("As we know that,\nAn Equation is a mathematical statement consisting of an equal symbol between two expressions having the same value.")+"\n"
sol4=sol4+("Therefore, according to the question,\nThe two pairs which will form an equation are : "+n1+" and "+n4+" , "+n2+" and "+n3)+"\n"
elif r1/r4==r3/r2:
a="{:.2f}".format(r1/r4)
b="{:.2f}".format(r3/r2)
sol4=sol4+("Now, "+latex(to_frac(str(r1),str(r4))+" = "+str(a)))+"\n"
sol4=sol4+("Also, "+latex(to_frac(str(r3),str(r2))+" = "+str(b)))+"\n"
sol4=sol4+("=> "+latex(to_frac(str(r1),str(r4))+" = "+to_frac(str(r3),str(r2))))+"\n"
sol4=sol4+("=> L.H.S = R.H.S")+"\n"
sol4=sol4+("As we know that,\nAn Equation is a mathematical statement consisting of an equal symbol between two expressions having the same value.")+"\n"
sol4=sol4+("Therefore, according to the question,\nThe two pairs which will form an equation are : "+n1+" and "+n4+" , "+n2+" and "+n3)+"\n"
elif r4/r1==r2/r3:
a="{:.2f}".format(r4/r1)
b="{:.2f}".format(r2/r3)
sol4=sol4+("Now, "+latex(to_frac(str(r4),str(r1))+" = "+str(a)))+"\n"
sol4=sol4+("Also, "+latex(to_frac(str(r2),str(r3))+" = "+str(b)))+"\n"
sol4=sol4+("=> "+latex(to_frac(str(r4),str(r1))+" = "+to_frac(str(r2),str(r3))))+"\n"
sol4=sol4+("=> L.H.S = R.H.S")+"\n"
sol4=sol4+("As we know that,\nAn Equation is a mathematical statement consisting of an equal symbol between two expressions having the same value.")+"\n"
sol4=sol4+("Therefore, according to the question,\nThe two pairs which will form an equation are : "+n1+" and "+n4+" , "+n2+" and "+n3)+"\n"
return sol4