import numpy as np
import integrate_utils as IU


#================================================================
#                       Functions
#================================================================
def ft(t):
    return 3*t**2*np.exp(t**3)

def int_ft(t):
    return np.exp(t**3)

#================================================================
#                       Calcs
#================================================================

exact_sol = int_ft(1) - int_ft(0)

trap = IU.trapezoidal(ft, 0, 1, 1000)
mid  = IU.midpoint(ft, 0, 1, 1000)

#================================================================
#                       Results
#================================================================

print 'Exact solution:', exact_sol
print 'Trapezoidal method:', trap
print '     difference', exact_sol-trap
print 'Midpoint method:', mid
print '     difference', exact_sol-mid
Esempio n. 2
0
def g(y):
    return 2 * y * np.exp(y**2)


#================================================
#          compute mean value
#================================================
x = np.linspace(0, np.pi + (np.pi / 1000), 1000)
y = np.linspace(0, 1 + 1 / 1000, 1000)

print np.sum(x) / 1000, np.sum(y) / 1000

#================================================
#          compute integral
#================================================
#using trapezoidal method
f_int = int_utils.trapezoidal(f, 0, np.pi, 1000)
g_int = int_utils.trapezoidal(g, 0, 1, 1000)

print f_int, g_int

#================================================
#            plotting
#================================================
plt.figure(1)
ax = plt.subplot(111)
ax.plot(x, f(x), 'r-', lw=1, label='f(x)')
ax.plot(y, g(y), 'b-', lw=1, label='g(y)')

#mean values are notably lower than values obtained through numerical integration
    return np.exp(t**3)

#=====================
# imports
#=====================

import numpy as np
import integrate_utils as iu


#=====================
#computations
#=====================

# integrate fct_t using trapezoid, midpoint methods
trap_val = iu.trapezoidal(fct_t, 0, 1, 100)
mid_val = iu.midpoint(fct_t, 0, 1, 100)

# the exact integral solution
exact_val = integral_fct_t(1) - integral_fct_t(0)

#=====================
#print results
#=====================

print('The integration of f(t) using the trapezoidal method is: ' + str(trap_val))
print('The integration of f(t) using the midpoint method is: ' + str(mid_val))
print('The exact integration of f(t) is: ' + str(exact_val))


1. Compute the integral of the following function within the given domain.
Use both midpoint and trapezoidal methods! Compare your results to the exact 
solution of the definite integral

a.) f(t) = 3t**2*e**t**3 
"""

import numpy as np
import integrate_utils as iu


def ft(t):
    return 3 * (t**2) * np.exp(t**3)


def integration_ft(t):
    return np.exp(t**3)


sol = integration_ft(1) - integration_ft(0)

trapazoidal = iu.trapezoidal(ft, 0, 1, 100)
midpoint = iu.midpoint(ft, 0, 1, 100)

print 'solution: ', sol
print 'Trapezoidal method: ', trapazoidal
print 'Difference', sol - trapazoidal
print 'Midpoint method: ', midpoint
print 'Difference ', (sol - midpoint)
Esempio n. 5
0
    return 3*(t**2) * (e**(t**3))

a = f_t(1)
print(a)

def int_f_t(t):
    return (e**(t**3))

b = int_f_t(0)
print(b)

#============================exact solution====================================
    
ex_sol = int_f_t(1) - int_f_t(0)

#===================Apply trapezoidal and midpoint methods ====================

trap_result = int_u.trapezoidal(f_t, 0, 1, 10)

midpoint_result = int_u.midpoint(f_t, 0, 1, 10)

#==results(when using %10.2f, 10 is number of spaces, 2 is nuber of decimals)==
print("Trapezoidal rule results: %.20f" %trap_result)
print("Midpoint method results: %.20f" %midpoint_result)

"""
Trapezoidal rule results: 1.75204264178808499786
Midpoint method results: 1.70148276900918782317

"""
#==============================================================================
def f(x):
    return np.sin(x)


def g(x):
    return 2 * x * np.exp(x**2)


def meanvalue(fct, x0, xn):
    """
    Computes the mean value of a function by averaging 1000 sampled values of the function
    Input: fct - function to find mean value of
           x0 - left bound
           xn - right bound
    """
    xvals = np.linspace(x0, xn, 1000)
    return fct(xvals).sum() / len(xvals)


#==============================================================================
#computations
#==============================================================================

fintegral = integrate_utils.trapezoidal(f, 0, np.pi, 1000)
print('Function f(x), integral is', fintegral, 'mean value is',
      meanvalue(f, 0, np.pi))

gintegral = integrate_utils.trapezoidal(g, 0, 1, 1000)
print('Function g(x), integral is', gintegral, 'mean value is',
      meanvalue(g, 0, 1))
# =========================2=============================
#                      Parameters
# =======================================================
xmin = 0
xmax = 1
N = 10

# =========================3=============================
#                  Numerical Integration
# =======================================================
# exact solution
f_IntExact = fct_F(xmax) - fct_F(xmin)

# numerical approx
f_IntTrap = int_utils.trapezoidal(fct_f, xmin, xmax, N)
f_IntMid = int_utils.midpoint(fct_f, xmin, xmax, N)

# compare exact and numerical
print('Exact Integral:', f_IntExact)
print('Numerical Approximation (Trapezoidal):', f_IntTrap)
print('Numerical Approximation (Midpoint):', f_IntMid, '\n')

for curr_n in range(10, 1000, 200):
    f_IntTrap = int_utils.trapezoidal(fct_f, xmin, xmax, curr_n)
    f_IntMid = int_utils.midpoint(fct_f, xmin, xmax, curr_n)
    print('Increment dx:', float(xmax - xmin) / curr_n)
    print('Exact Integral:', f_IntExact)
    print('Numerical Approximation (Trapezoidal):', f_IntTrap)
    print('Numerical Approximation (Midpoint):', f_IntMid, '\n')

def f_t (t):
    return (3*t**2)*np.exp(t**3)

def if_t(t):
    return np.exp(t**3)

#========= Trapezoidal and Midpoint Evaluation ================================

x0 = 0
xn = 1

time_intervals = np.arange(0, 1, 100)

trapf_t = integrate.trapezoidal( f_t, x0, xn, 100)  #trapezoidal method
midf_t = integrate.midpoint( f_t, x0, xn, 100)   #midpoint method

#real value of definite integral
realValue = if_t(xn) - if_t(x0)

print ('Integral using trapezoidal method: ', trapf_t)
print ('Integral using midpoint method: ', midf_t)
print ('Exact value of integral: ', realValue)

#=============== Error calc for both methods ==========

def errorCalc(real, approxValue):
    return (np.absolute(approxValue - real)/real)*100

trapError = np.round_(errorCalc(realValue, trapf_t), 2)
Esempio n. 9
0
r3 = np.linspace(0, 2, N)
theta3 = np.linspace(0, np.pi, N)
sol_exact3a = F3(r3[N - 1], theta3[N - 1]) - F3(r3[0], theta3[0])
x3 = np.linspace(0, 2, N)
y3 = np.linspace(0, 1.5, N)
sol_exact3b = W3(x3[N - 1], y3[N - 1]) - W3(x3[0], y3[0])

# =============================================================================
#                             Integration
# =============================================================================

# For part 1.

num_sol_1_midpoint = int_utils.midpoint(f1, t1[0], t1[N - 1], N)
num_sol_1_trapezoid = int_utils.trapezoidal(f1, t1[0], t1[N - 1], N)

# For part 2.

# For part 3.

num_sol3a = int_utils.monteCarlo(w3, g3, -2, 2, -2, 2, N2)
num_sol3b = int_utils.monteCarlo(f3, g3, -1, 3, -1, 2.5, N2)

# =============================================================================
#                                 Comparisons
# =============================================================================

# For part 1.

print(
xmin = 0.
xmax_f = np.pi
xmax_g = 1
x_f = np.linspace(xmin, xmax_f, N)
x_g = np.linspace(xmin, xmax_g, N)


def f(x_f):
    return sin(x_f)


def g(x_g):
    return 2 * (x_g) * (e**((x_g)**2))


ia_fx = inte.trapezoidal(f, xmin, xmax_f, N)
ia_gx = inte.trapezoidal(g, 0, 1, 1000)

iact_fx = -cos(x_f)
iact_gx = (e**(x_g)**2)
print ia_fx
print iact_fx[999]
print ia_gx
print iact_gx[999]
plt.figure(1)
ax1 = plt.subplot(211)
plt.plot(x_f, iact_fx, 'b')
plt.plot(x_f, f(x_f), 'r')
ax2 = plt.subplot(212)
plt.plot(x_g, iact_gx, 'k')
plt.plot(x_g, g(x_g), 'g')
# -*- coding: utf-8 -*-
#python 2.7
"""
Extra Credit Problem 1
Compute the integral of 3t^2e^(t^3) from 0 to 1 analytically and then using midpoint and trapezoidal method
"""

import numpy as np
import integrate_utils

#==============================================================================
#function definitions
#==============================================================================
def fct(t):
    return 3 * t**2 * np.exp(t**3) 

def antideriv(t):
    return np.exp(t**3)

#==============================================================================
#computations
#==============================================================================
#using midpoint method
print('The solution, using midpoint method, is ' + str(integrate_utils.midpoint(fct, 0, 1, 1000)))

#using trapezoid method
print('The solution, using trapzeoid method, is ' + str(integrate_utils.trapezoidal(fct, 0, 1, 1000)))

#exact solution
print('The exact solution is ' + str(antideriv(1) - antideriv(0)))
import numpy as np
import matplotlib.pyplot as plt
import integrate_utils as utils


def fct_t(t):
    return 3 * t**2 * (np.e)**t**3


t_trap = utils.trapezoidal(fct_t, 0, 1, 1000)

t_mid = utils.midpoint(fct_t, 0, 1, 1000)

print('Trapezoidal: ', t_trap)

print('Midpoint: ', t_mid)

#def trapezoidal(  fct_t, t0, tn, N):
#    """
#            Composite Trapezoidal Method, eq. 3.17 page 60 in Linge & Langtangen
#    :param fct_x:  - function whose integral is in question
#    :param x1:     - integration bounds
#    :param x2:     - integration bounds
#    :param N:      - number of trapezoids, chose high number for high accuracy
#    :return:   - integral of fct_x between x0 and xn
#    """
#    t0 = 0
#    tn = 1
#    N = 1000
#    dt = float(tn-t0)/N
#    # compute intergral: eq. 3.17 page 60 in Linge & Langtangen
Esempio n. 13
0

def a_fct(x):
    return np.sin(x)


def b_fct(x):
    return 2 * x * np.exp(x**2)


#======
# computations
#======

# numerical integrations of the part a and part b functions
integral_a = iu.trapezoidal(a_fct, 0, np.pi, 1000)
integral_b = iu.trapezoidal(b_fct, 0, 1, 1000)

# estimated means for these functions
mean_a = get_mean(a_fct, 0, np.pi)
mean_b = get_mean(b_fct, 0, 1)

#======
# print results
#======

print('Part a.)')
print('The calculated mean of f(x) using 1000 points is: ' + str(mean_a))
print('And the numerical integral is: ' + str(integral_a))
print('Part b.)')
print('The calculated mean of g(x) using 1000 points is: ' + str(mean_b))
        YPP = (fct_2[i - 1] - 2 * fct_2[i] + fct_2[i + 1]) / h**2
        YP = (fct_2[i + 1] - fct_2[i - 1]) / (2 * h)
        res[i] = YPP - Ypp_2(x, fct_2[i], YP)

    res[-1] = fct_2[-1] - B
    return res


# we need an initial guess
iniT = (B - alpha) / (x3 - x4) * X2

Y_2 = fsolve(residuals, iniT)
print(Y_2)
#############################     Mean Value   ################################
dataset_1 = Y
x = np.mean(dataset_1)
print('Mean Value 1 ', x)

dataset_2 = Y_2
x_2 = np.mean(dataset_2)
print('Mean Value 2 ', x_2)

for n in np.arange(100, 1200, 200):
    fInt = int_utils.trapezoidal(fct_1, x1 - 1, x2 + 1, n)
    print('no. of random points', n, "num integral", round(fInt, 4), 'exact',
          round(2. / 3, 2))
for n in np.arange(100, 1200, 200):
    fInt = int_utils.trapezoidal(fct_2, x3 - 1, x4 + 1, n)
    print('no. of random points', n, "num integral", round(fInt, 4), 'exact',
          round(2. / 3, 2))
Esempio n. 15
0
@author: Brady Lobmeyer
Extra Credit assignment #1

"""

import numpy as np
import matplotlib.pyplot as plt
import integrate_utils as inte
e= np.e
sin = np.sin
cos = np.cos

def f(t):
    return 3*(t**2)*(e**(t**3)) 
t= inte.trapezoidal(f, 0, 1, 100)
print t

x= inte.midpoint(f, 0, 1, 100)
print x
print (e**(1**3))-(e**(0**3))
#=====================
# #2
#=======================

N= 1000
xmin = 0
xmax_f= np.pi
xmax_g= 1
x_f= np.linspace(xmin, xmax_f, N)
x_g= np.linspace(xmin, xmax_g, N)
Esempio n. 16
0
import integrate_utils as int_utils


#==============================================================================
#                                 fct definition
#==============================================================================
def fct_t(t):  # function defined
    return 3 * t**2 * np.exp(t**3)


def int_f(t):  # integrated function
    return np.exp(t**3)


#==============================================================================
#                                 paramters
#==============================================================================
tmin, tmax = 0, 1  # initlal time value and final time value respectively
N = 100  # can increase this value for increased accuracy

#==============================================================================
#                                 compute integral
#==============================================================================
f_trapint = int_utils.trapezoidal(fct_t, tmin, tmax, N)  # integrals
f_midint = int_utils.midpoint(fct_t, tmin, tmax, N)
f_exact = int_f(tmax) - int_f(tmin)  # exact solution

print('Trapezoidal Integral:   ', f_trapint)
print('Midpoint Integral:   ', f_midint)
print('Exact solution:    ', f_exact)
Esempio n. 17
0
#================================================================
#                       Parameters
#================================================================
a_min = 0
a_max = np.pi

b_min = 0
b_max = 1

a_x = np.linspace(a_min, a_max, 1000)
b_x = np.linspace(b_min, b_max, 1000)
#================================================================
#                       Calcs
#================================================================
a_mean = np.mean(fx(a_x))
b_mean = np.mean(gx(b_x))

a_int = IU.trapezoidal(fx, a_min, a_max, 1000)
b_int = IU.trapezoidal(gx, b_min, b_max, 1000)
#================================================================
#                       Results
#================================================================
print 'a)'
print 'Mean value:', a_mean
print 'Integral value:', a_int
print 'Difference:', a_int - a_mean

print 'b)'
print 'Mean value:', b_mean
print 'Integral value:', b_int
print 'Difference:', b_int - b_mean
Esempio n. 18
0

#==============================================================================
#                                 parameters
#==============================================================================
xminf, xmaxf = 0, np.pi  # initial and final x values for f_x
xming, xmaxg = 0, 1  # initial and final x values for g_x
N = 1000

# function values for each x for both functions
a_fx = np.linspace(xminf, xmaxf, N)
a_gx = np.linspace(xming, xmaxg, N)

#==============================================================================
#                                 compute integrals
#==============================================================================
# integrations using trapezoial method
f_int = int_utils.trapezoidal(f_x, xminf, xmaxf, N)
g_int = int_utils.trapezoidal(g_x, xming, xmaxg, N)

#==============================================================================
#                                 compute means
#==============================================================================
# averages/means calculated
f_mean = np.mean(f_x(a_fx))
g_mean = np.mean(g_x(a_gx))

print('mean value of f:   ', f_mean, 'integral value of f:   ', f_int)
print('mean value of g:   ', g_mean, 'integral value of g:   ', g_int)
# note that the mean of f is 2/pi since the x domain was over pi while the integral was 2.