def four_of_a_kind(p1, p2) -> int:
if get_keys_of_value(Card.numbers_count(p1), 4) > get_keys_of_value(Card.numbers_count(p2), 4):
return 1
elif get_keys_of_value(Card.numbers_count(p1), 4) < get_keys_of_value(Card.numbers_count(p2), 4):
return 2
# else, tie in four, check the 5th card
return high_card(p1, p2)
def three_of_a_kind(p1, p2) -> int:
if get_keys_of_value(Card.numbers_count(p1), 3) > get_keys_of_value(Card.numbers_count(p2), 3):
return 1
elif get_keys_of_value(Card.numbers_count(p1), 3) < get_keys_of_value(Card.numbers_count(p2), 3):
return 2
# else, three is tied
return high_card(p1, p2)
def two_pair(p1, p2) -> int:
if get_keys_of_value(Card.numbers_count(p1), 2) > get_keys_of_value(Card.numbers_count(p2), 2):
return 1
elif get_keys_of_value(Card.numbers_count(p1), 2) < get_keys_of_value(Card.numbers_count(p2), 2):
return 2
# else, tie in both pairs
return high_card(p1, p2)
def pair(p1, p2) -> int:
if get_keys_of_value(Card.numbers_count(p1), 2) > get_keys_of_value(Card.numbers_count(p2), 2):
return 1
elif get_keys_of_value(Card.numbers_count(p1), 2) < get_keys_of_value(Card.numbers_count(p2), 2):
return 2
# else, pair is tied
return high_card(p1, p2)
def full_house(p1, p2) -> int:
if get_keys_of_value(Card.numbers_count(p1), 3) > get_keys_of_value(Card.numbers_count(p2), 3):
return 1
elif get_keys_of_value(Card.numbers_count(p1), 3) < get_keys_of_value(Card.numbers_count(p2), 3):
return 2
# else, tie in threes, check pairs
if get_keys_of_value(Card.numbers_count(p1), 2) > get_keys_of_value(Card.numbers_count(p2), 2):
return 1
elif get_keys_of_value(Card.numbers_count(p1), 2) < get_keys_of_value(Card.numbers_count(p2), 2):
return 2
# else, complete tie
return 0
def pair(cards) -> bool:
return max(Card.numbers_count(cards).values()) == 2
def two_pair(cards) -> bool:
n = list(Card.numbers_count(cards).values())
return n == [2, 2, 1] or n == [2, 1, 2] or n == [1, 2, 2]
def three_of_a_kind(cards) -> bool:
return max(Card.numbers_count(cards).values()) == 3
def full_house(cards) -> bool:
n = Card.numbers_count(cards)
if len(n.keys()) == 2:
values = set(n.values())
return len(values.difference({2, 3})) == 0