Esempio n. 1
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 def y_from_x(cls, x):
     """ Returns one of the two possible values for y from x.
         Used for point decompression.
     """
     a = cls.a; b = cls.b; p = cls.p
     y_squared = ((x*x+ a)*x + b ) % p
     # it might be y or p - y
     y = square_root_mod_prime( y_squared, p )
     return y
Esempio n. 2
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 def y_from_x(cls, x):
     """ Returns one of the two possible values for y from x.
         Used for point decompression.
     """
     a = cls.a
     b = cls.b
     p = cls.p
     y_squared = ((x * x + a) * x + b) % p
     # it might be y or p - y
     y = square_root_mod_prime(y_squared, p)
     return y
Esempio n. 3
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 def from_x(cls, x):
     """
     y^2 = ((a * x^2) / (d * x^2 - 1)) - (1 / (d * x^2 - 1))
     For every x coordinate, there are two possible points: (x, y) and (x, -y)
     """
     assert isinstance(x, FQ)
     xsq = x * x
     ax2 = JUBJUB_A * xsq
     dxsqm1 = prime_field_inv(JUBJUB_D * xsq - 1, JUBJUB_Q)
     ysq = dxsqm1 * (ax2 - 1)
     y = FQ(square_root_mod_prime(int(ysq), JUBJUB_Q))
     return cls(x, y)
Esempio n. 4
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def map_to_curve(x, P=curve.p()):
    x -= 1
    y = 0
    found = False

    while not found:
        x += 1
        f_x = (x * x * x + 7) % P

        try:
            y = numbertheory.square_root_mod_prime(f_x, P)
            found = True
        except Exception as e:
            pass

    return Point(curve.p(), curve.a(), curve.b(), x, y)
Esempio n. 5
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 def from_y(cls, y, sign=None):
     """
     x^2 = (y^2 - 1) / (d * y^2 - a)
     """
     assert isinstance(y, FQ)
     ysq = y * y
     lhs = ysq - 1
     rhs = JUBJUB_D * ysq - JUBJUB_A
     xsq = lhs / rhs
     x = FQ(square_root_mod_prime(int(xsq), JUBJUB_Q))
     if sign is not None:
         # Used for compress & decompress
         if (x.n & 1) != sign:
             x = -x
     else:
         if is_negative(x):
             x = -x
     return cls(x, y)
Esempio n. 6
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 def uncompress(self, xR):
     """ Return a new point R from just x-coordinate xR
         Note - this is not ANSI or SEC format 'x' with
                leading 2 bits holding (2 + yR mod 2)
         yR will be incorrect for 50% of runs,
         but ECDH will still have correct answer
     """
     a = self.a
     b = self.b
     p = self.p
     #t0 = ( xR*xR*xR + a*xR + b ) % p
     t0 = ((xR*xR + a)*xR + b ) % p
     t1 = square_root_mod_prime( t0, p )
     yR = t1   # it might also be yR = p - t1
     R = self.point( xR, yR )
     if self.contains_point(R):
         return R
     yR = p - t1
     R = self.point( xR, yR )
     if self.contains_point(R):
         return R
     else:
         EllipticCurveError( "uncompress failed")
Esempio n. 7
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 def uncompress(self, xR):
     """ Return a new point R from just x-coordinate xR
         Note - this is not ANSI or SEC format 'x' with
                leading 2 bits holding (2 + yR mod 2)
         yR will be incorrect for 50% of runs,
         but ECDH will still have correct answer
     """
     a = self.a
     b = self.b
     p = self.p
     #t0 = ( xR*xR*xR + a*xR + b ) % p
     t0 = ((xR * xR + a) * xR + b) % p
     t1 = square_root_mod_prime(t0, p)
     yR = t1  # it might also be yR = p - t1
     R = self.point(xR, yR)
     if self.contains_point(R):
         return R
     yR = p - t1
     R = self.point(xR, yR)
     if self.contains_point(R):
         return R
     else:
         EllipticCurveError("uncompress failed")