Esempio n. 1
0
    What is the first term in the Fibonacci sequence to contain 1000 digits?

Notes:
    Generator written and saved in projecteuler. Super easy deal.

    For large fib vals,

    F(n) = round(phi**n / sqrt(5))

    phi**n / sqrt(5)            >   10**999
    n * log(phi) - .5 * log(5)  >   999 * log(10)

"""

from math import log
from projecteuler import fibonacci

if __name__ == '__main__':

    # Generator way
    for (i, f) in enumerate(fibonacci()):
        if f / 10**999:
            break

    print 'the {}-th term is\n\n{}\n'.format(i + 1, f)

    # Math way
    phi = 1.6180
    n = (999. * log(10.) + .5 * log(5)) / log(phi)
    print 'By Great Maths we have i = {}'.format(n)
Esempio n. 2
0
from projecteuler import fibonacci
L = 30  # Limit is expressed as 2^L

print "Project Euler 301 Solution =", fibonacci(L + 2)
Esempio n. 3
0
Notes:
    Generator written and saved in projecteuler. Super easy deal.

    For large fib vals,

    F(n) = round(phi**n / sqrt(5))

    phi**n / sqrt(5)            >   10**999
    n * log(phi) - .5 * log(5)  >   999 * log(10)

"""

from math import log
from projecteuler import fibonacci


if __name__ == '__main__':

    # Generator way
    for (i, f) in enumerate(fibonacci()):
        if f / 10**999:
            break

    print 'the {}-th term is\n\n{}\n'.format(i + 1, f)

    # Math way
    phi = 1.6180
    n = (999. * log(10.) + .5 * log(5)) / log(phi)
    print 'By Great Maths we have i = {}'.format(n)
Esempio n. 4
0
from projecteuler import fibonacci
L = 30    # Limit is expressed as 2^L

print "Project Euler 301 Solution =", fibonacci(L+2)