custom_print_fn=rprint,
theta=theta)
labels = runner.DO_PHASE_I(index)
labels_ph1[index] = labels
rprint("Finished period=%d (index %d). Freeing memory" %
(period, index))
runner = None # free up the memory
# Now, combine all those results on the root node
for index, period in enumerate(periods):
owner = index % nproc
if rank == 0:
# ROOT process receives
if owner != 0:
comm.Recv(labels_ph1[index], source=owner)
elif owner == rank:
# Other processes send only their computations
comm.Send(labels_ph1[index], dest=0)
labels_ph1[index] = None
# now, we do phase 2
# Want to find the best period from all possible periods (`periods` array)
# The cost of selecting a given period is the cost of using that period and
# the associated start time with that period at that pixel
if rank == 0:
runner = Runner(vid_color, periods, args, True, rprint, theta=theta)
runner.provide_all_p1_labels(labels_ph1)
runner.DO_PHASE_II()
rprint("process exiting at", datetime.now())
from prelude import *
from runner import Runner
r = Runner(vid_color, periods, args, theta=theta)
for index, period in enumerate(periods):
print("-" * 15, "Starting period", period, "-" * 15)
r.DO_PHASE_I(index)
if len(periods) > 1:
r.DO_PHASE_II()
else:
print("Skipping Phase II since there was only 1 period")
