Python Chain.countの例

コード例 #1

    def testCount(self):
        chain = Chain(self.a[:])
        num_a = chain.data.count(Hetero('a'))
        self.assertEqual(chain.count('a'), num_a)

        chain = Chain(self.b[:])
        num_a = chain.data.count(Hetero('t'))
        self.assertEqual(chain.count('t'), num_a)

        chain = Chain(self.c[:])
        num_a = chain.data.count(Hetero('leu'))
        self.assertEqual(chain.count('leu'), num_a)

        chain = Chain(self.c[:])
        num_a = chain.data.count(Hetero('cys'))
        self.assertEqual(chain.count('cys'), num_a)

コード例 #2

ファイル: test_Crystal.py プロジェクト: AkiOhtani/biopython

    def testCount(self):
        chain = Chain(self.a[:])
        num_a = chain.data.count(Hetero('a'))
        self.assertEqual(chain.count('a'), num_a)

        chain = Chain(self.b[:])
        num_a = chain.data.count(Hetero('t'))
        self.assertEqual(chain.count('t'), num_a)

        chain = Chain(self.c[:])
        num_a = chain.data.count(Hetero('leu'))
        self.assertEqual(chain.count('leu'), num_a)

        chain = Chain(self.c[:])
        num_a = chain.data.count(Hetero('cys'))
        self.assertEqual(chain.count('cys'), num_a)

コード例 #3

ファイル: test_Crystal.py プロジェクト: zyha/biopython

    def testCount(self):
        chain = Chain(self.a[:])
        num_a = chain.data.count(Hetero("a"))
        self.assertEqual(chain.count("a"), num_a)

        chain = Chain(self.b[:])
        num_a = chain.data.count(Hetero("t"))
        self.assertEqual(chain.count("t"), num_a)

        chain = Chain(self.c[:])
        num_a = chain.data.count(Hetero("leu"))
        self.assertEqual(chain.count("leu"), num_a)

        chain = Chain(self.c[:])
        num_a = chain.data.count(Hetero("cys"))
        self.assertEqual(chain.count("cys"), num_a)