コード例 #1
0
ファイル: test_node.py プロジェクト: sly2j/PyRDF
    def test_dfs_graph_with_computed_values_pruning(self):
        """
        """

        # Head node
        node = Node(None, None)

        # Graph nodes
        n1 = node.Define()
        n2 = node.Filter()
        n3 = n2.Filter()
        n4 = n3.Count()
        n5 = n1.Filter()
        n6 = n5.Count()
        n7 = node.Filter()

        # This is to make sure action nodes with
        # already computed values are pruned.
        n6.action_node.value = 1
        # This is to make sure that transformation
        # leaf nodes with value (possibly set intentionally)
        # don't get pruned.
        n7.value = 1

        obtained_order = DfsTest.traverse(node=node.get_head())

        # The node 'n6' will be pruned. Hence,
        # there's only one '3' in this list.
        reqd_order = [1, 2, 2, 2, 3, 2]

        self.assertEqual(obtained_order, reqd_order)
コード例 #2
0
ファイル: test_node.py プロジェクト: sly2j/PyRDF
    def test_dfs_graph_with_recursive_pruning(self):
        """
        Test case to check that nodes in a PyRDF
        graph with no user references and no children
        get pruned recursively.

        """

        # Head node
        node = Node(None, None)

        # Graph nodes
        n1 = node.Define()
        n2 = node.Filter()
        n3 = n2.Filter()
        n4 = n3.Count()
        n5 = n1.Filter()
        n6 = node.Filter()

        # Remove references from n4 and it's parent nodes
        n4 = n3 = n2 = None

        obtained_order = DfsTest.traverse(node=node.get_head())

        reqd_order = [1, 2, 2]

        self.assertEqual(obtained_order, reqd_order)
コード例 #3
0
ファイル: test_node.py プロジェクト: sly2j/PyRDF
    def test_dfs_graph_with_parent_pruning(self):
        """
        Test case to check that parent nodes with
        no user references don't get pruned.

        """

        # Head node
        node = Node(None, None)

        # Graph nodes
        n1 = node.Define()
        n2 = node.Filter()
        n3 = n2.Filter()
        n4 = n3.Count()
        n5 = n1.Filter()
        n6 = node.Filter()

        # Remove references from n2 (which shouldn't affect the graph)
        n2 = None

        obtained_order = DfsTest.traverse(node=node.get_head())

        reqd_order = [1, 2, 2, 2, 3, 2]
        # Removing references from n2 will not prune any node
        # because n2 still has children

        self.assertEqual(obtained_order, reqd_order)
コード例 #4
0
ファイル: test_node.py プロジェクト: sly2j/PyRDF
    def test_dfs_graph_with_pruning_transformations(self):
        """
        Test case to check that transformation nodes with
        no children and no user references get pruned.

        """

        # Head node
        node = Node(None, None)

        # Graph nodes
        n1 = node.Define()
        n2 = node.Filter()
        n3 = n2.Filter()
        n4 = n3.Count()
        n5 = n1.Filter()
        n6 = node.Filter()

        # Transformation pruning
        n5 = n1.Count()  # n5 was earlier a transformation node

        obtained_order = DfsTest.traverse(node=node.get_head())

        reqd_order = [1, 3, 2, 2, 3, 2]

        self.assertEqual(obtained_order, reqd_order)
コード例 #5
0
ファイル: test_node.py プロジェクト: sly2j/PyRDF
    def test_dfs_graph_without_pruning(self):
        """
        Test case to check that node pruning does not
        occur if every node either has children or some
        user references.

        """

        # Head node
        node = Node(None, None)

        # Graph nodes
        n1 = node.Define()
        n2 = node.Filter()
        n3 = n2.Filter()
        n4 = n3.Count()
        n5 = n1.Count()
        n6 = node.Filter()

        obtained_order = DfsTest.traverse(node=node.get_head())

        reqd_order = [1, 3, 2, 2, 3, 2]

        self.assertEqual(obtained_order, reqd_order)