コード例 #1
0
def find_well_distr(s):
    def find_distrib(s):
        if s == "":
            return [dict()]
        l = []
        for dictio in find_distrib(s[1:]):
            if s[0] in dictio:
                l.append(dictio)
            else:
                for i in range(10):
                    if i not in dictio.values():
                        d = dictio.copy()
                        d[s[0]] = i
                        l.append(d)
        return l

    ll = find_distrib(s)
    l_well = []
    for dictio in ll:
        if dictio[s[0]] == 0:
            continue
        l = [str(dictio[lettre]) for lettre in s]
        nb = int("".join(l))
        if is_square(nb):
            l_well.append(dictio)
    return l_well
コード例 #2
0
def c_b(k, b0=0):
    b = b0 + 1
    while not is_square(4 * k + 5 * b**2):
        b += 1
        if b >= (k / 5)**0.5:
            return None
    return b, int((4 * k + 5 * b**2)**0.5)
コード例 #3
0
def problem_44():
    def pent(n):
        return (n * (3 * n - 1)) // 2

    a = 1
    while True:
        d = pent(a)
        a += 1
        dd = 2 * d
        i = 1
        ok = False
        while i * (3 * (i + 2) - 1) <= dd:
            if dd % i == 0:
                j = dd // i
                if j % 3 != 2:
                    i += 1
                    continue
                i2 = (j + 1) // 3
                if i2 < i:
                    i += 1
                    continue
                if (i + i2) % 2 != 0:
                    i += 1
                    continue
                k = (i + i2) // 2
                s = 3 * k**2 - k - d
                delta = 1 + 24 * s
                if is_square(delta) and int(delta**0.5 + 1) % 3 == 0:
                    ok = True
                    print(d)
                    break
            i += 1
        if ok:
            break
コード例 #4
0
def problem_66():
    def a_b(D):
        h1, k1 = 1, 0
        a_i = int(D ** 0.5)
        r = 1, 1, -a_i, 1
        h2, k2 = a_i, 1
        while h2 ** 2 - D * k2 ** 2 != 1:
            a, b, c, d = r
            a2, b2 = a * b * d ** 2, a ** 2 * d ** 2 * D - c ** 2 * b ** 2
            c2, d2 = -c * b ** 2 * d, a ** 2 * d ** 2 * D - c ** 2 * b ** 2
            a, b, c, d = a2, b2, c2, d2
            d1 = gcd(abs(a), abs(b))
            a //= d1
            b //= d1
            a_i = int(a * (D ** 0.5) / b + c / d)
            c -= a_i * d
            d2 = gcd(abs(c), abs(d))
            c //= d2
            d //= d2
            r = a, b, c, d
            h1, h2 = h2, a_i * h2 + h1
            k1, k2 = k2, a_i * k2 + k1

        return h2, k2

    x_max = 9
    D_max = 5
    for D in range(10, 1001):
        if not is_square(D):
            x = a_b(D)[0]
            if x > x_max:
                D_max = D
                x_max = x
    print(D_max)
コード例 #5
0
def problem_64():
    def period(D):
        h1, k1 = 1, 0
        a_i = int(D ** 0.5)
        r = 1, 1, -a_i, 1
        h2, k2 = a_i, 1
        L = []
        while r not in L:
            L.append(r)
            a, b, c, d = r
            a2, b2 = a * b * d ** 2, a ** 2 * d ** 2 * D - c ** 2 * b ** 2
            c2, d2 = -c * b ** 2 * d, a ** 2 * d ** 2 * D - c ** 2 * b ** 2
            a, b, c, d = a2, b2, c2, d2
            d1 = gcd(abs(a), abs(b))
            a //= d1
            b //= d1
            a_i = int(a * (D ** 0.5) / b + c / d)
            c -= a_i * d
            d2 = gcd(abs(c), abs(d))
            c //= d2
            d //= d2
            r = a, b, c, d
            h1, h2 = h2, a_i * h2 + h1
            k1, k2 = k2, a_i * k2 + k1
        return len(L) - L.index(r)

    c = 0
    for N in range(2, 10001):
        if not is_square(N) and period(N) % 2 == 1:
            c += 1
    print(c)
コード例 #6
0
def f(n):
    nb = 0
    for x in range(n // 2 + 1, int((n/2)*(1+2**0.5))+1):
        c_2 = n ** 2 - 4 * x ** 2 + 4 * n * x
        if is_square(c_2):
            nb += 1
        if nb > 105:
            return 500
    return nb * 4
コード例 #7
0
ファイル: Problem_140.py プロジェクト: Darkduv/Project-Euler
def next1(b):
    from Tools import is_square
    while not is_square(1 + 5 * b**2):
        b += 1
    return int(sqrt(1 + 5 * b**2) + 0.05), b
コード例 #8
0
ファイル: Problem_233.py プロジェクト: Darkduv/Project-Euler
def next_x(n, x=0):
    x += 1
    while not is_square(2 * n**2 - (2 * x - n)**2) and x <= n:
        x += 1
    return x if x <= n else 0
コード例 #9
0
def nb(a, b, c, d):
    s = 0
    s += dic[(a, b)]
    s += dic[(b, c)]
    s += dic[(c, d)]
    s += dic[(d, a)]
    s += a + b + c + d - 3
    return s


ll = []
for aa in range(1, m + 1):
    for bb in range(aa + 1, m + 1):
        for cc in range(aa + 1, m + 1):
            for dd in range(bb, m + 1):
                if is_square(nb(aa, bb, cc, dd)):
                    ll.append((aa, bb, cc, dd))

n_tot = 0
for aa, bb, cc, dd in ll:
    if bb == dd:
        n_tot += 1
        # print(aa, bb, cc, dd, "ll", 1)
    else:
        n_tot += 2
        # print(aa, bb, cc, dd, "ll", 2)
n_tot *= 4

ll2 = []
for aa in range(1, m + 1):
    bb = aa
コード例 #10
0
ファイル: Problem_141.py プロジェクト: Darkduv/Project-Euler
# %% Problem 141

from Tools import is_square

s = set()
for b in range(1, 10**6):
    for p in range(1, 10**6):
        if p**2 * b >= 10**6:
            break
        a = p + 1
        c = a**3 * b**2 * p + p**2 * b
        while c <= 10**12:
            if is_square(c):
                s.add(c)
            a += 1
            c = a**3 * b**2 * p + p**2 * b

print(sum(s))  # sol = 878454337159
# Todo: Too long ?
コード例 #11
0
    if abs(nb_ - nn) < mm:
        mini = m, n
        mm = abs(nb_ - nn)
print(mini[0] * mini[1])  # sol = 2772

# %% Problem 86

from math import sqrt
from Tools import is_square

c = 0
n = 0
while n < 10**6:
    c += 1
    for d in range(c + 1, int(c * 5**0.5 + 0.1) + 1):
        if is_square(d**2 - c**2):
            m = int((d**2 - c**2)**0.5 + 0.1)
            if m <= c + 1:
                n += m // 2
            else:
                n += (2 * c - m) // 2 + 1

# %% Problem 87

from Tools import numpy_sieve

l = [False for i in range(50000000)]

l_pp = list(numpy_sieve(7070))
for i in l_pp:
    for j in l_pp: