コード例 #1
0
 def try_parsing(self, parser: ParserPython, text_to_parse: str):
     # noinspection PyBroadException
     try:
         parser.parse(text_to_parse)
     except:
         self.fail("Could not parse {0} using the {1} parser!".format(
             text_to_parse, parser.__class__))
コード例 #2
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def convert_trog(inf: str, outf: TextIO) -> None:
    pp = ParserPython(trogfile, skipws=False)
    try:
        tree = pp.parse_file(inf)
        print(tree)
    except Exception as e:
        print(e)
コード例 #3
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def test_memoization_nomatch(capsys):
    '''
    Test that already failed match is found in the cache on
    subsequent matches.
    '''
    def grammar():
        return [(rule1, ruleb), [rule1, rulec]]

    def rule1():
        return rulea, ruleb

    def rulea():
        return "a"

    def ruleb():
        return "b"

    def rulec():
        return "c"

    parser = ParserPython(grammar, memoization=True, debug=True)
    parse_tree = parser.parse("c")

    assert "Cache hit for [rule1=Sequence, 0] = '0'" in capsys.readouterr()[0]
    assert parser.cache_hits == 1
    assert parser.cache_misses == 4
コード例 #4
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    def test_with_some_words_2(self):

        parser = ParserPython(document, skipws=False)

        text = f"{self.words1}\n\n"

        parsed = parser.parse(text)
        # print('\n: parsed') ; pp(parsed)

        expect = NonTerminal(document(), [
            NonTerminal(body(), [
                NonTerminal(element(), [
                    Terminal(words(), 0, self.words1),
                ]),
                NonTerminal(element(), [
                    Terminal(newline(), 0, '\n'),
                ]),
                NonTerminal(element(), [
                    Terminal(blank_line(), 0, '\n'),
                ]),
            ]),
            Terminal(EOF(), 0, ''),
        ])
        # print('\n: expect') ; pp(expect)

        assert parsed == expect, (
            f"text = '{text}' :\n"
            f"[expect]\n{pp_str(expect)}\n[parsed]\n{pp_str(parsed)}")
コード例 #5
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def test_direct_rule_call():
    '''
    Test regression where in direct rule call semantic action is
    erroneously attached to both caller and callee.
    '''

    def grammar():  return rule1, rule2
    def rule1():    return "a"
    def rule2():    return rule1

    call_count = [0]

    class DummySemAction(SemanticAction):
        def first_pass(self, parser, node, nodes):
            call_count[0] += 1
            return SemanticAction.first_pass(self, parser, node, nodes)

    # Sem action is attached to rule2 only but
    # this bug will attach it to rule1 also resulting in
    # wrong call count.
    rule2.sem = DummySemAction()

    parser = ParserPython(grammar)
    parse_tree = parser.parse("aa")
    parser.getASG()

    assert call_count[0] == 1, "Semantic action should be called once!"
コード例 #6
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    def test_02_text_line_pair (self) :
        def body():
            return OneOrMore ( [ text_line ], rule_name='body' )
        def document():
            return Sequence( ( body, EOF ), rule_name='document' )
        # print('\n: document') ; pp(document())
        parser = ParserPython( document, skipws=False )

        text = self.line1 + self.line2
        parsed = parser.parse(text)
        # print('\n: parsed') ; pp(parsed)
        #
        # print('\n: flatten') ; pp(flatten(parsed))

        p_newline	= Terminal(newline(), 0, '\n')
        p_l1_words	= Terminal(words(), 0, self.line1[:-1])
        p_l1_text_line	= NonTerminal(text_line(), [ p_l1_words, p_newline ])
        p_l2_words	= Terminal(words(), 0, self.line2[:-1])
        p_l2_text_line	= NonTerminal(text_line(), [ p_l2_words, p_newline ])
        p_body		= NonTerminal(body(), [ p_l1_text_line, p_l2_text_line ])
        p_eof		= Terminal(EOF(), 0, '')
        expect		= NonTerminal(document(), [p_body, p_eof] )
        # print('\n: expect') ; pp(expect)

        assert parsed == expect, ( f"text		= '{text}' :\n"
                                   f"[expect]\n{pp_str(expect)}\n[parsed]\n{pp_str(parsed)}" )
コード例 #7
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    def test_05_paragraph_multiple (self) :
        def body():
            return OneOrMore ( OrderedChoice( [ paragraph, newline ] ), rule_name='body' )
        def document():
            return Sequence( ( body, EOF ), rule_name='document' )
        # print('\n: document') ; pp(document())
        parser = ParserPython( document, skipws=False )

        text = self.line1 + self.line2 + '\n'
        text = text * 3
        parsed = parser.parse(text)
        # print('\n: parsed') ; pp(parsed)

        p_newline	= Terminal(newline(), 0, '\n')
        p_l1_words	= Terminal(words(), 0, self.line1[:-1])
        p_l1_text_line	= NonTerminal(text_line(), [ p_l1_words, p_newline ])
        p_l2_words	= Terminal(words(), 0, self.line2[:-1])
        p_l2_text_line	= NonTerminal(text_line(), [ p_l2_words, p_newline ])
        p_paragraph	= NonTerminal(paragraph(), [ p_l1_text_line, p_l2_text_line ])
        p_body 		= NonTerminal(body(), [
            p_paragraph, p_newline,
            p_paragraph, p_newline,
            p_paragraph, p_newline,
        ])
        p_eof		= Terminal(EOF(), 0, '')
        expect		= NonTerminal(document(), [ p_body, p_eof ] )
        # print('\n: expect') ; pp(expect)

        assert parsed == expect, ( f"text = '{text}' :\n"
                                   f"[expect]\n{pp_str(expect)}\n[parsed]\n{pp_str(parsed)}" )
コード例 #8
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def test_memoization_positive(capsys):
    '''
    Test that already matched rule is found in the cache on
    subsequent matches.
    Args:
        capsys - pytest fixture for output capture
    '''

    def grammar():  return [(rule1, ruleb), (rule1, rulec)]
    def rule1():    return rulea, ruleb
    def rulea():    return "a"
    def ruleb():    return "b"
    def rulec():    return "c"

    parser = ParserPython(grammar, memoization=True, debug=True)

    # Parse input where a rule1 will match but ruleb will fail
    # Second sequence will try rule1 again on the same location
    # and result should be found in the cache.
    parse_tree = parser.parse("a   b   c")

    # Assert that cached result is used
    assert  "Cache hit" in capsys.readouterr()[0]
    assert parser.cache_hits == 1
    assert parser.cache_misses == 4
コード例 #9
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def test_memoization_positive(capsys):
    '''
    Test that already matched rule is found in the cache on
    subsequent matches.
    Args:
        capsys - pytest fixture for output capture
    '''
    def grammar():
        return [(rule1, ruleb), (rule1, rulec)]

    def rule1():
        return rulea, ruleb

    def rulea():
        return "a"

    def ruleb():
        return "b"

    def rulec():
        return "c"

    parser = ParserPython(grammar, memoization=True, debug=True)

    # Parse input where a rule1 will match but ruleb will fail
    # Second sequence will try rule1 again on the same location
    # and result should be found in the cache.
    parse_tree = parser.parse("a   b   c")

    # Assert that cached result is used
    assert "Cache hit" in capsys.readouterr()[0]
    assert parser.cache_hits == 1
    assert parser.cache_misses == 4
コード例 #10
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ファイル: parsefile.py プロジェクト: revarbat/pymuv
 def parse_string(self, src, grammar=program, filename=None):
     oldsrcs = self.input_sources
     self.context.optimization_level = self.optimization_level
     self.input_sources = src
     parser = ParserPython(
         grammar,
         comment_def=comment,
         skipws=True,
         reduce_tree=False,
         memoization=True,
         debug=False,
     )
     self.context.parsers.append(parser)
     self.context.filenames.append(filename)
     try:
         parse_tree = parser.parse(self.input_sources)
         visitor = MuvVisitor(debug=False)
         visitor.muvparser = self
         parse_tree = visit_parse_tree(parse_tree, visitor)
         out = parse_tree.generate_code(self.context)
         if self.error_found:
             return False
         if len(self.context.filenames) == 1:
             if self.context.filenames[-1]:
                 filetext = " from {0}".format(
                     self.context.filenames[-1]
                 )
             else:
                 filetext = ''
             self.output = (
                 "( Generated{0} by the MUV compiler. )\n"
                 "(   https://github.com/revarbat/pymuv )\n"
                 "{1}\n"
             ).format(filetext, self.output)
         self.output += out
         if not self.error_found and len(self.context.filenames) == 1:
             if self.wrapper_program:
                 self.output = (
                     "@program {0}\n"
                     "1 99999 d\n"
                     "1 i\n"
                     "{1}\n"
                     ".\n"
                     "c\n"
                     "q\n"
                 ).format(self.wrapper_program, self.output)
         return True
     except MuvError as e:
         line, col = parser.pos_to_linecol(e.position)
         self.print_error(filename, line, col, str(e))
         return False
     except NoMatch as e:
         line, col = parser.pos_to_linecol(e.position)
         expected = self.simplify_parse_error(e)
         self.print_error(filename, line, col, "Expected %s" % expected)
         return False
     finally:
         self.input_sources = oldsrcs
         self.context.parsers.pop()
         self.context.filenames.pop()
コード例 #11
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def parse_tree():
    def grammar():
        return ("first", "second", "third")

    parser = ParserPython(grammar)

    return parser.parse("   first \n\n  second   third")
コード例 #12
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def parse(file, enc):
    with codecs.open(file, "r", encoding=enc) as opened_file:
        opened_file_content = opened_file.read()
    parser = ParserPython(segnetics_file, reduce_tree=True)
    parse_tree = visit_parse_tree(parser.parse(opened_file_content),
                                  SegneticsVisitor())
    return parse_tree
コード例 #13
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def parse_tree():

    def grammar(): return ("first", "second", "third")

    parser = ParserPython(grammar)

    return parser.parse("   first \n\n  second   third")
コード例 #14
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    def setUp(self):

        # first get defaults, should all be False for boolean flags
        super().setUp()

        global parse_debug, record, analyzing

        self.parse_debug = parse_debug
        self.record = record
        self.analyzing = analyzing

        # quiet, no parse trees displayeda
        # self.debug = False

        # show parse tree for pass >= self.debug
        # self.debug = 2

        # Show text being parsed
        # self.show = True

        # and again, to apply behavior per altered settings
        super().setUp()

        self.grammar = document

        self.parser = ParserPython ( language_def = self.grammar,
                                     reduce_tree = False,
                                     debug = self.parse_debug, )

        if self.record :
            write_scratch ( _clean = True )
コード例 #15
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def main(text):

    from arpeggio import Optional, ZeroOrMore, OneOrMore, EOF
    from arpeggio import RegExMatch as _

    def number():
        return _(r'\d*\.\d*|\d+')

    def factor():
        return Optional(["+", "-"]), [number, ("(", expression, ")")]

    def term():
        return factor, ZeroOrMore(["*", "/"], factor)

    def expression():
        return term, ZeroOrMore(["+", "-"], term)

    def calc():
        return OneOrMore(expression), EOF

    from arpeggio import ParserPython
    parser = ParserPython(calc)  # calc is the root rule of your grammar
    # Use param debug=True for verbose debugging
    # messages and grammar and parse tree visualization
    # using graphviz and dot

    parse_tree = parser.parse(text)
    pass
コード例 #16
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ファイル: test_memoization.py プロジェクト: bitranox/Arpeggio
def test_memoization_nomatch(capsys: FixtureRequest) -> None:
    """
    Test that already failed match is found in the cache on
    subsequent matches.
    """
    def grammar() -> List[Any]:
        return [(rule1, ruleb), [rule1, rulec]]

    def rule1() -> Tuple[Any, ...]:
        return rulea, ruleb

    def rulea() -> str:
        return "a"

    def ruleb() -> str:
        return "b"

    def rulec() -> str:
        return "c"

    parser = ParserPython(grammar, memoization=True, debug=True)
    parse_tree = parser.parse("c")

    assert "Cache hit for [rule1=Sequence, 0] = '0'" in capsys.readouterr()[0]
    assert parser.cache_hits == 1
    assert parser.cache_misses == 4
コード例 #17
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def test_combine_python():

    # This will result in NonTerminal node
    def root():
        return my_rule(), "."

    # This will result in Terminal node
    def my_rule():
        return Combine(ZeroOrMore("a"), OneOrMore("b"))

    parser = ParserPython(root)

    input1 = "abbb."

    # Whitespaces are preserved in lexical rules so the following input
    # should not be recognized.
    input2 = "a b bb."

    ptree1 = parser.parse(input1)

    with pytest.raises(NoMatch):
        parser.parse(input2)

    assert isinstance(ptree1, NonTerminal)
    assert isinstance(ptree1[0], Terminal)
    assert ptree1[0].value == "abbb"
コード例 #18
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def test_direct_rule_call() -> None:
    """
    Test regression where in direct rule call semantic action is
    erroneously attached to both caller and callee.
    """

    def grammar():  return rule1, rule2
    def rule1():    return "a"
    def rule2():    return rule1

    call_count = [0]

    class DummySemAction(SemanticAction):
        def first_pass(self, parser, node, nodes):
            call_count[0] += 1
            return SemanticAction.first_pass(self, parser, node, nodes)

    # Sem action is attached to rule2 only but
    # this bug will attach it to rule1 also resulting in
    # wrong call count.
    rule2.sem = DummySemAction()        # type: ignore

    parser = ParserPython(grammar)
    parse_tree = parser.parse("aa")
    parser.getASG()

    assert call_count[0] == 1, "Semantic action should be called once!"
コード例 #19
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    def parse(content: str) -> 'Atom':
        from foil.language.grammar import atom
        from foil.language.grammar import comment

        parser = ParserPython(atom, comment_def=comment)
        parse_tree = parser.parse(content)
        return visit_parse_tree(parse_tree, FoilVisitor())
コード例 #20
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    def parse(content: str) -> 'Literal':
        from foil.language.grammar import literal
        from foil.language.grammar import comment

        parser = ParserPython(literal, comment_def=comment)
        parse_tree = parser.parse(content)
        return visit_parse_tree(parse_tree, FoilVisitor())
コード例 #21
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def test_nondeterministic_unordered_group():
    def root():
        return 'word1', UnorderedGroup(some_rule, 'word2', some_rule), EOF

    def some_rule():
        return Optional('word2'), Optional('word3')

    content = '''word1 word2 '''

    # If the 'word2' from unordered group in the `root` rule matches first
    # the input parses, else it fails.
    # We repeat parser construction and parsing many times to check
    # if it fails every time. The current fix will iterate in order from left
    # to right and repeat matching until all rules in a unordered group
    # succeeds.
    fail = 0
    success = 0
    for _ in range(100):
        try:
            parser = ParserPython(root)
            parser.parse(content)
            success += 1
        except NoMatch:
            fail += 1

    assert fail == 100
コード例 #22
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def test_reduce_tree():

    input = "34 a 3 3 b 3 b"

    parser = ParserPython(grammar, reduce_tree=False)
    result = parser.parse(input)

#    PTDOTExporter().exportFile(result, 'test_reduce_tree_pt.dot')

    assert result[0].rule_name == 'first'
    assert isinstance(result[0], NonTerminal)
    assert result[3].rule_name == 'first'
    assert result[0][0].rule_name == 'fourth'
    # Check reduction for direct OrderedChoice
    assert result[2][0].rule_name == 'third'

    parser = ParserPython(grammar, reduce_tree=True)
    result = parser.parse(input)

    # PTDOTExporter().exportFile(result, 'test_reduce_tree_pt.dot')

    assert result[0].rule_name == 'fourth'
    assert isinstance(result[0], Terminal)
    assert result[3].rule_name == 'fourth'
    # Check reduction for direct OrderedChoice
    assert result[2][0].rule_name == 'third_str'
コード例 #23
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def main(argv):
    # Parsing
    #different alg relation next to each other i.e a*|b require brackets (a*)|b
    parser = ParserPython(formula)  #, debug=True) #, reduce_tree = True)
    parse_tree = parser.parse(argv)
    result = visit_parse_tree(parse_tree, formVisitor())
    result.tostr()
    return result
コード例 #24
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ファイル: builders.py プロジェクト: stefano-bragaglia/Grapple
    def load_from_str(self, content: str) -> 'Builder':
        parser = ParserPython(cypher, comment_def=comment)
        parsed = parser.parse(content)
        visited = visit_parse_tree(parsed, KnowledgeVisitor())
        base = RuleBase(visited['data'])
        self.load_from_base(base)

        return self
コード例 #25
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def language_from_str(language_def, metamodel):
    """
    Constructs parser and initializes metamodel from language description
    given in textX language.

    Args:
        language_def (str): A language description in textX.
        metamodel (TextXMetaModel): A metamodel to initialize.

    Returns:
        Parser for the new language.
    """

    if metamodel.debug:
        metamodel.dprint("*** PARSING LANGUAGE DEFINITION ***")

    # Check the cache for already conctructed textX parser
    if metamodel.debug in textX_parsers:
        parser = textX_parsers[metamodel.debug]
    else:
        # Create parser for TextX grammars using
        # the arpeggio grammar specified in this module
        parser = ParserPython(textx_model,
                              comment_def=comment,
                              ignore_case=False,
                              reduce_tree=False,
                              memoization=metamodel.memoization,
                              debug=metamodel.debug,
                              file=metamodel.file)

        # Cache it for subsequent calls
        textX_parsers[metamodel.debug] = parser

    # Parse language description with textX parser
    try:
        parse_tree = parser.parse(language_def)
    except NoMatch as e:
        line, col = parser.pos_to_linecol(e.position)
        raise TextXSyntaxError(text(e), line, col)

    # Construct new parser and meta-model based on the given language
    # description.
    lang_parser = visit_parse_tree(parse_tree, TextXVisitor(parser, metamodel))

    # Meta-model is constructed. Validate its semantics.
    metamodel.validate()

    # Here we connect meta-model and language parser for convenience.
    lang_parser.metamodel = metamodel
    metamodel._parser_blueprint = lang_parser

    if metamodel.debug:
        # Create dot file for debuging purposes
        PMDOTExporter().exportFile(
            lang_parser.parser_model,
            "{}_parser_model.dot".format(metamodel.rootcls.__name__))

    return lang_parser
コード例 #26
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def parse(text):
    parser = ParserPython(mspaText,
                          debug=False,
                          reduce_tree=False,
                          skipws=False,
                          ws="\t ",
                          memoization=True)

    return parser.parse(text)
コード例 #27
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ファイル: solver.py プロジェクト: tud-ccc/mocasin
 def __init__(self, graph, platform, cfg, mappingDict={}, debug=False):
     self.__graph = graph
     self.__platform = platform
     self.__mappingDict = mappingDict
     self.__parser = ParserPython(
         Grammar.logicLanguage, reduce_tree=True, debug=debug
     )
     self.__debug = debug
     self.__cfg = cfg
def test_parse_input():

    parser = ParserPython(calc)
    input = "4+5*7/3.45*-45*(2.56+32)/-56*(2-1.34)"
    result = parser.parse(input)

    assert isinstance(result, NonTerminal)
    assert str(result) == "4 | + | 5 | * | 7 | / | 3.45 | * | - | 45 | * | ( | 2.56 | + | 32 | ) | / | - | 56 | * | ( | 2 | - | 1.34 | ) | "
    assert repr(result) == "[ [ [ [ number '4' [0] ] ],  '+' [1], [ [ number '5' [2] ],  '*' [3], [ number '7' [4] ],  '/' [5], [ number '3.45' [6] ],  '*' [10], [  '-' [11], number '45' [12] ],  '*' [14], [  '(' [15], [ [ [ number '2.56' [16] ] ],  '+' [20], [ [ number '32' [21] ] ] ],  ')' [23] ],  '/' [24], [  '-' [25], number '56' [26] ],  '*' [28], [  '(' [29], [ [ [ number '2' [30] ] ],  '-' [31], [ [ number '1.34' [32] ] ] ],  ')' [36] ] ] ], EOF [37] ]"
コード例 #29
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def test_parse_input():

    parser = ParserPython(calc)
    input = "4+5*7/3.45*-45*(2.56+32)/-56*(2-1.34)"
    result = parser.parse(input)

    assert isinstance(result, NonTerminal)
    assert str(result) == "4 | + | 5 | * | 7 | / | 3.45 | * | - | 45 | * | ( | 2.56 | + | 32 | ) | / | - | 56 | * | ( | 2 | - | 1.34 | ) | "
    assert repr(result) == "[ [ [ [ number '4' [0] ] ],  '+' [1], [ [ number '5' [2] ],  '*' [3], [ number '7' [4] ],  '/' [5], [ number '3.45' [6] ],  '*' [10], [  '-' [11], number '45' [12] ],  '*' [14], [  '(' [15], [ [ [ number '2.56' [16] ] ],  '+' [20], [ [ number '32' [21] ] ] ],  ')' [23] ],  '/' [24], [  '-' [25], number '56' [26] ],  '*' [28], [  '(' [29], [ [ [ number '2' [30] ] ],  '-' [31], [ [ number '1.34' [32] ] ] ],  ')' [36] ] ] ], EOF [37] ]"
コード例 #30
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def test_sequence_suppress():
    """
    """
    def grammar():
        return Sequence("one", "two", "three", suppress=True), "four"

    parser = ParserPython(grammar)

    result = parser.parse("one two three four")
    assert result[0] == "four"
コード例 #31
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ファイル: peg.py プロジェクト: igordejanovic/Arpeggio
    def _from_peg(self, language_def):
        parser = ParserPython(peggrammar, comment, reduce_tree=False,
                              debug=self.debug)
        parser.root_rule_name = self.root_rule_name
        parse_tree = parser.parse(language_def)

        return visit_parse_tree(parse_tree, PEGVisitor(self.root_rule_name,
                                                       self.comment_rule_name,
                                                       self.ignore_case,
                                                       debug=self.debug))
コード例 #32
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def test_sequence():
    def grammar():
        return ("a", "b", "c")

    parser = ParserPython(grammar)

    parsed = parser.parse("a b c")

    assert str(parsed) == "a | b | c"
    assert repr(parsed) == "[  'a' [0],  'b' [2],  'c' [4] ]"
コード例 #33
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def test_zeroormore_with_separator():
    def grammar():
        return ZeroOrMore(['a', 'b'], sep=','), EOF

    parser = ParserPython(grammar, reduce_tree=False)
    result = parser.parse('a, b, b, b, a')
    assert result

    with pytest.raises(NoMatch):
        parser.parse('a, b a')
コード例 #34
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ファイル: test_suppression.py プロジェクト: Amper/Arpeggio
def test_sequence_suppress():
    """
    """

    def grammar():     return Sequence("one", "two", "three", suppress=True), "four"

    parser = ParserPython(grammar)

    result = parser.parse("one two three four")
    assert result[0] == "four"
コード例 #35
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    def _from_peg(self, language_def):
        parser = ParserPython(peggrammar, comment, reduce_tree=False,
                              debug=self.debug)
        parser.root_rule_name = self.root_rule_name
        parse_tree = parser.parse(language_def)

        return visit_parse_tree(parse_tree, PEGVisitor(self.root_rule_name,
                                                       self.comment_rule_name,
                                                       self.ignore_case,
                                                       debug=self.debug))
コード例 #36
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ファイル: main.py プロジェクト: GustafBratt/javaparser
def main():
    parser = ParserPython(calc)  # calc is the root rule of your grammar
    # Use param debug=True for verbose debugging
    # messages and grammar and parse tree visualization
    # using graphviz and dot

    parse_tree = parser.parse("-(4-1)*5+(2+4.67)+5.89/(.2+7)")
    print(parse_tree)
    result = visit_parse_tree(parse_tree, CalcVisitor(debug=False))
    print(result)
コード例 #37
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def test_sequence():
    def grammar():
        return ("a", "b", "c")

    parser = ParserPython(grammar)

    parsed = parser.parse("a b c")

    assert str(parsed) == "a | b | c"
    assert repr(parsed) == "[  'a' [0],  'b' [2],  'c' [4] ]"
コード例 #38
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ファイル: test_rrel.py プロジェクト: textX/textX
def test_rrel_basic_parser1():
    parser = ParserPython(rrel_standalone)
    parse_tree = parser.parse("^pkg*.cls")
    assert len(parse_tree) == 2  # always true (one path, one EOF)

    parse_tree = parser.parse("obj.ref.~extension *.methods")
    assert len(parse_tree) == 2  # always true (one path, one EOF)

    parse_tree = parser.parse("instance.(type.vals)*")
    assert len(parse_tree) == 2  # always true (one path, one EOF)
コード例 #39
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    def parse(content: str) -> 'Literal':
        from arpeggio import ParserPython
        from arpeggio import visit_parse_tree
        from depysible.language.grammar import literal, comment
        from depysible.language.visitor import DefeasibleVisitor

        parser = ParserPython(literal, comment_def=comment)
        parse_tree = parser.parse(content)

        return visit_parse_tree(parse_tree, DefeasibleVisitor())
コード例 #40
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def test_zeroormore_with_separator():

    def grammar():
        return ZeroOrMore(['a', 'b'], sep=','), EOF

    parser = ParserPython(grammar, reduce_tree=False)
    result = parser.parse('a, b, b, b, a')
    assert result

    with pytest.raises(NoMatch):
        parser.parse('a, b a')
コード例 #41
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ファイル: initial.py プロジェクト: dusanmaric90/WebApp
def main(debug=False):
    
    parser = ParserPython(initial, debug=debug)
    file_input = open("input.txt", 'r')
   
    input_expr = file_input.read()

    
    parse_tree = parser.parse(input_expr)

    result = parser.getASG()
コード例 #42
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ファイル: test_eolterm.py プロジェクト: Avram88/Arpeggio
def test_eolterm():

    # first rule should match only first line
    # so that second rule will match "a" on the new line
    input = """a a b a b b
    a"""

    parser = ParserPython(grammar, reduce_tree=False)
    result = parser.parse(input)

    assert result
コード例 #43
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def test_default_action_disabled():

    parser = ParserPython(grammar)

    parser.parse('(-34) strmatch')

    parser.getASG(defaults=False)

    assert not p_removed
    assert not number_str
    assert parse_tree_node
コード例 #44
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def test_empty_nested_parse():

    def grammar(): return [first]
    def first(): return ZeroOrMore("second")

    parser = ParserPython(grammar)

    # Parse tree will be empty
    # as nothing will be parsed
    tree = parser.parse("something")

    assert not tree
コード例 #45
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def test_not_match_as_alternative():
    """
    Test that Not is not reported if a part of OrderedChoice.
    """

    def grammar():      return ['one', Not('two')], _(r'\w+')

    parser = ParserPython(grammar)

    with pytest.raises(NoMatch) as e:
        parser.parse('   three ident')
    assert "Expected 'one' at " in str(e)
コード例 #46
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ファイル: parser.py プロジェクト: unsftn/bibreport
def parse_bibtex(file_name, debug=False):
    global parser
    if parser is None:
        parser = ParserPython(bibfile, debug=debug)

    with codecs.open(file_name, "r", encoding="utf-8") as bibtexfile:
        bibtexfile_content = bibtexfile.read()

    parse_tree = parser.parse(bibtexfile_content)

    return visit_parse_tree(parse_tree,
                            BibtexVisitor(debug=debug))
コード例 #47
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def test_optional_no_error():
    """
    """
    def grammar():  return Optional('a'), 'b'

    parser = ParserPython(grammar)

    try:
        parser.parse('c')
        assert False

    except NoMatch as e:
        assert "Expected 'b'" in str(e)
コード例 #48
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def test_file_name_reporting():
    """
    Test that if parser has file name set it will be reported.
    """

    def grammar():      return Optional('a'), 'b', EOF

    parser = ParserPython(grammar)

    with pytest.raises(NoMatch) as e:
        parser.parse("\n\n   a c", file_name="test_file.peg")
    assert "Expected 'b' at position test_file.peg:(3, 6)" in str(e)
    assert (e.value.line, e.value.col) == (3, 6)
コード例 #49
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def test_sequence_of_nots():
    """
    Test that sequence of Not rules is handled properly.
    """

    def grammar():
        return Not('one'), Not('two'), _(r'\w+')

    parser = ParserPython(grammar)

    with pytest.raises(NoMatch) as e:
        parser.parse('   two ident')
    assert "Not expected input" in str(e)
コード例 #50
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def test_file_name_reporting():
    """
    Test that if parser has file name set it will be reported.
    """

    def grammar():      return Optional('a'), 'b', EOF

    parser = ParserPython(grammar)

    try:
        parser.parse("\n\n   a c", file_name="test_file.peg")
    except NoMatch as e:
        assert "Expected 'b' at test_file.peg:(3, 6)" in str(e)
コード例 #51
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def test_not_match_at_beginning():
    """
    Test that matching of Not ParsingExpression is not reported in the
    error message.
    """

    def grammar():
        return Not('one'), _(r'\w+')

    parser = ParserPython(grammar)

    with pytest.raises(NoMatch) as e:
        parser.parse('   one ident')
    assert "Not expected input" in str(e)
コード例 #52
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def test_pos_to_linecol():

    def grammar(): return ("a", "b", "c")

    parser = ParserPython(grammar)

    parse_tree = parser.parse("a\n\n\n b\nc")

    a_pos = parse_tree[0].position
    assert parser.pos_to_linecol(a_pos) == (1, 1)
    b_pos = parse_tree[1].position
    assert parser.pos_to_linecol(b_pos) == (4, 2)
    c_pos = parse_tree[2].position
    assert parser.pos_to_linecol(c_pos) == (5, 1)
コード例 #53
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def test_alternative_added():
    """
    Test that matches from alternative branches at the same positiona are
    reported.
    """

    def grammar():      return ['one', 'two'], _(r'\w+')

    parser = ParserPython(grammar)

    with pytest.raises(NoMatch) as e:
        parser.parse('   three ident')
    assert "Expected 'one' or 'two'" in str(e)
    assert (e.value.line, e.value.col) == (1, 4)
コード例 #54
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def test_optional_no_error():
    """
    Test that optional match failure does not show up in the NoMatch errors.
    """
    def grammar():  return Optional('a'), 'b'

    parser = ParserPython(grammar)

    try:
        parser.parse('c')
        assert False

    except NoMatch as e:
        assert "Expected 'b'" in str(e)
コード例 #55
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def test_comment_matching_not_reported():
    """
    Test that matching of comments is not reported.
    """

    def grammar():      return Optional('a'), 'b', EOF
    def comments():     return _('\/\/.*$')

    parser = ParserPython(grammar, comments)

    try:
        parser.parse('\n\n a // This is a comment \n c')
    except NoMatch as e:
        assert "Expected 'b' at position (4, 2)" in str(e)
コード例 #56
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def test_skipws():
    """
    skipws may be defined per Sequence.
    """

    def grammar():     return Sequence("one", "two", "three"), "four"

    parser = ParserPython(grammar)

    # By default, skipws is True and whitespaces will be skipped.
    parser.parse("one two   three  four")


    def grammar():     return Sequence("one", "two", "three",
                                       skipws=False), "four"

    parser = ParserPython(grammar)

    # If we disable skipws for sequence only then whitespace
    # skipping should not be done inside sequence.
    with pytest.raises(NoMatch):
        parser.parse("one two   three  four")

    # But it will be done outside of it
    parser.parse("onetwothree  four")
コード例 #57
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def test_comment_matching_not_reported():
    """
    Test that matching of comments is not reported.
    """

    def grammar():      return Optional('a'), 'b', EOF
    def comments():     return _('\/\/.*$')

    parser = ParserPython(grammar, comments)

    with pytest.raises(NoMatch) as e:
        parser.parse('\n\n a // This is a comment \n c')
    assert "Expected 'b' at position (4, 2)" in str(e)
    assert (e.value.line, e.value.col) == (4, 2)
コード例 #58
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def test_optional_inside_zeroormore():
    """
    Test optional match inside a zero or more.
    Optional should always succeed thus inducing ZeroOrMore
    to try the match again.
    Arpeggio handle this using soft failures.
    """
    def grammar():  return ZeroOrMore(Optional('a'))

    parser = ParserPython(grammar)

    with pytest.raises(NoMatch):
        # This could lead to infinite loop
        parser.parse('b')
コード例 #59
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def test_ws():
    """
    ws consists of chars that will be skipped if skipws is enables.
    By default it consists of space, tab and newline.
    """

    def grammar():
        return ("one", "two", "three")

    parser = ParserPython(grammar)

    # With default ws this should parse without error
    parser.parse("""one
                  two   three""")

    # If we make only a space char to be ws than the
    # same input will raise exception.
    parser = ParserPython(grammar, ws=" ")
    with pytest.raises(NoMatch):
        parser.parse("""one
                  two   three""")

    # But if only spaces are between words than it will
    # parse.
    parser.parse("one two  three")