コード例 #1
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 def test_add_multiple_nodes_left(self):
     new_tree = bst(20)
     smaller_node = bst(19)
     even_smaller_node = bst(18)
     new_tree.add(smaller_node)
     new_tree.add(even_smaller_node)
     self.assertTrue(new_tree.get_left_child().get_left_child().value == even_smaller_node.value)
コード例 #2
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 def __call__(self, x, train):
     h = bst.bst(self.b0(self.conv0(x)))
     h = bst.bst(self.b1(self.conv1(h)))
     h = bst.bst(self.b2(self.conv2(h)))
     h = F.average_pooling_2d(h, 48)
     h = self.b3(self.fc0(h))
     return h
コード例 #3
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 def test_add_multiple_nodes_right(self):
     new_tree = bst(20)
     larger_node = bst(21)
     even_larger_node = bst(22)
     new_tree.add(larger_node)
     new_tree.add(even_larger_node)
     self.assertTrue(new_tree.get_right_child().get_right_child().value == even_larger_node.value)
コード例 #4
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ファイル: 24.34.py プロジェクト: frrad/interview-prep
def huffman(freq_table):

    # should use min-heap for pool
    pool = [bst.bst((freq_table[key], key)) for key in freq_table.keys()]

    while len(pool) > 1:
        pool.sort(key=lambda x: -x.data[0])
        a, b = pool.pop(), pool.pop()
        weight = a.data[0] + b.data[0]
        c = bst.bst((weight, ''))
        c.left, c.right = a, b
        pool.append(c)

    return pool[0]
コード例 #5
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 def __call__(self, x, train, batch_size):
     h = self.b_conv0(da.dst(self.conv0(x)))
     h = self.block0(h, train)
     h = bst.bst(self.b_conv1(self.conv1(h)))
     h = self.block1(h, train)
     h = bst.bst(self.b_conv2(self.conv2(h)))
     h = self.block2(h, train)
     h = bst.bst(self.b_conv3(self.conv3(h)))
     h = self.block3(h, train)
     h = bst.bst(self.b_conv4(self.conv4(h)))
     h = F.max_pooling_2d(h, 2, 2)
     h = F.average_pooling_2d(h, 2, 2, 1)
     h = Variable(cupy.reshape(h.data, [batch_size, -1]),
                  volatile=not train)
     h = self.b_dense0(self.fc0(h))
     return h
コード例 #6
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 def setUp(self):
     self.tree = bst()
     self.tree.insert(9)
     self.tree.insert(6)
     self.tree.insert(12)
     self.tree.insert(3)
     self.tree.insert(8)
     self.tree.insert(10)
     self.tree.insert(15)
     self.tree.insert(7)
     self.tree.insert(18)
コード例 #7
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ファイル: depth_sum.py プロジェクト: Danawill/algorithms
 def setUp(self):
     self.tree = bst()
     self.tree.insert(9)
     self.tree.insert(6)
     self.tree.insert(12)
     self.tree.insert(3)
     self.tree.insert(8)
     self.tree.insert(10)
     self.tree.insert(15)
     self.tree.insert(7)
     self.tree.insert(18)
コード例 #8
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ファイル: filelist.py プロジェクト: cristicalin/setwall
 def _reconcile(self):
   if self.NEED_RECONCILE:
     self.suspend_watch()
     temp = get_file_list(self.DIR_PATH, self.SETTINGS.get_wallpaper_recursive())
     temp_tree = bst.bst(temp)
     for my_file in self.LOCAL_FILE_LIST:
       if temp_tree.extract(my_file) != my_file: 
         self.list_remove(my_file)
     temp_list = temp_tree.as_list()
     if len(temp_list) > 0:
       self.LOCAL_FILE_LIST += temp_tree.as_list()
     self.NEED_SAVE = True
     self.instate_watch()
   self.NEED_RECONCILE = False
コード例 #9
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ファイル: test_bst.py プロジェクト: plash3/Sketch
def main():
    bst_tree = bst()
    # vals = [round(random.random()*100) for i in xrange(15)]

    vals = [myString('(')]
    bst_tree.add_val( vals[0] )
    for i in xrange(5):
        nvals = []
        while vals:
            v = vals.pop()
            nvals.append( myString(v + '(') )
            bst_tree.add_val( nvals[-1] )
            nvals.append( myString(v + ')') )
            bst_tree.add_val( nvals[-1] )
        vals = nvals

    bst_tree.print_bfs()
    print "BALANCED LEAVES:", bst_tree.get_blncd_leaves()
コード例 #10
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 def test_check_if_value_doesnt_exist(self):
     new_tree = bst(20)
     node1 = bst(10)
     node2 = bst(25)
     node3 = bst(30)
     node4 = bst(4)
     node5 = bst(89)
     new_tree.add(node1)
     new_tree.add(node2)
     new_tree.add(node3)
     new_tree.add(node4)
     new_tree.add(node5)
     self.assertFalse(new_tree.find(200))
コード例 #11
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def test():
    # 1
    print '#'
    print 'problme 1: please refer to the tree.pdf file to see the tree as a graph'
    print '#'
    # node list for construct binary search tree
    nd_list = [
        65, 28, 22, 46, 35, 32, 40, 48, 47, 55, 83, 78, 89, 85, 86, 91, 93
    ]
    print 'tree node list'
    print nd_list
    bt = bst()
    for i in range(len(nd_list)):
        bt.bst_insert(bt.root, nd_list[i])

    print 'original tree, in order traversal'
    bt.bst_in_trav(bt.root)
    bt1 = copy.deepcopy(bt)
    bt2 = copy.deepcopy(bt)
    print
    print 'delete a leaf: (86), in order traversal'
    bt.delete_value(bt.root, 86)
    bt.bst_in_trav(bt.root)
    print
    print 'delete (91), its successor is (93), (93) is a leaf, in order traversal'
    bt1.delete_value(bt1.root, 91)
    bt1.bst_in_trav(bt1.root)
    print
    print 'delete (83), its successor is (85), (85) is not a leaf, in order traversal'
    bt2.delete_value(bt2.root, 83)
    bt2.bst_in_trav(bt2.root)
    print

    print '#'
    # 2
    # bubble sort
    print 'problem 2: bubble sort'
    print '#'
    print 'original list: '
    t_list = [32, 7, 45, 13, 64, 9, 3, 11, 9, 18, 69, 23, 33, 99, 76, 86]
    print t_list
    print 'bubble sort passes'
    bbsort(t_list)
コード例 #12
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ファイル: net.py プロジェクト: eri-utokyo/eri
 def __call__(self, x):
     h1 = bst.bst(self.b1(self.c1(x), test=not self.train))
     h2 = bst.bst(self.b2(self.c2(h1), test=not self.train))
     h3 = bst.bst(self.b3(self.c3(h2), test=not self.train))
     h4 = bst.bst(self.b4(self.l1(h3), test=not self.train))
     return self.b5(self.l2(h4), test=not self.train)
コード例 #13
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ファイル: net.py プロジェクト: eri-utokyo/eri
 def __call__(self, x):
     h1 = bst.bst(self.b1(self.l1(x), test=not self.train))
     h2 = bst.bst(self.b2(self.l2(h1), test=not self.train))
     return self.b3(self.l3(h2), test=not self.train)
コード例 #14
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 def test_for_parent_when_empty(self):
     new_tree = bst()
     self.assertTrue(new_tree.parent == None)
コード例 #15
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 def test_if_root(self):
     new_tree = bst()
     self.assertTrue(new_tree.is_root())
コード例 #16
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 def test_parent_of_left(self):
     new_tree = bst(20)
     smaller_node = bst(19)
     new_tree.add(smaller_node)
     self.assertTrue(new_tree.get_left_child().get_parent().value == new_tree.value)
コード例 #17
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 def __call__(self, x):
     x = x * 256
     h1 = bst(self.b1(self.l1(x), test=not self.train))
     h2 = bst(self.b2(self.l2(h1), test=not self.train))
     return self.b3(self.l3(h2), test=not self.train)
コード例 #18
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 def test_for_left_when_empty(self):
     new_tree = bst()
     self.assertFalse(new_tree.has_left_child())
コード例 #19
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 def test_for_both_when_empty(self):
     new_tree = bst()
     self.assertFalse(new_tree.has_both_children())
コード例 #20
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 def test_new_bst_with_value(self):
     new_tree = bst(20)
     self.assertTrue(new_tree.value != None)
コード例 #21
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 def test_add_node_when_larger(self):
     new_tree = bst(20)
     larger_node = bst(21)
     new_tree.add(larger_node)
     self.assertTrue(new_tree.get_right_child().value == larger_node.value)
コード例 #22
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 def test_parent_of_right(self):
     new_tree = bst(20)
     larger_node = bst(21)
     new_tree.add(larger_node)
     self.assertTrue(new_tree.get_right_child().get_parent().value == new_tree.value)
コード例 #23
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prt = prtree()


def printree(node):
    dot = prt.dot(node)
    dot.view()
    prt.dots.append(dot)
    # print(dot.source)
    # dot.render(
    # filename=None, directory=None, view=False, cleanup=False, format='png')


if __name__ == "__main__":
    # dots清理等
    prt.dots.clear()
    t_bst = bst()
    t_llrbt = llrbt()
    t_sc = scht()
    t_lp = lpht()
    # 取数据集
    d = randoms.dict_int(n=100)
    keys = [key for key in d]
    minkey = min(keys)
    maxkey = max(keys)
    # 插入
    for k, v in d.items():
        t_bst.insert(k, k)
        t_llrbt.insert(k, k)
        t_sc.insert(k, k)

    # test
コード例 #24
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f.close()

f = open('names_2.txt', 'r')
names_2 = f.read().split("\n")  # List containing 10000 names
f.close()

duplicates = []  # Return the list of duplicates in this data structure

# STRETCH STARTS
# set_1 = set(names_1)
# set_2 = set(names_2)
# duplicates = list(set_1.intersection(set_2))
# STRETCH ENDS

# create new tree and set the root value
tree = bst(names_1[0])

# loop over names_1 list and insert names to tree
# so I could utilise bst contains method on it
for name in names_1:
    tree.insert(name)
# loop over names_2 list and pass each name to contains method
# of tree in order to find duplicates
# append to duplicates list if found
for name in names_2:
    if tree.contains(name):
        duplicates.append(name)

end_time = time.time()
print(f"{len(duplicates)} duplicates:\n\n{', '.join(duplicates)}\n\n")
print(f"runtime: {end_time - start_time} seconds")
コード例 #25
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 def test_empty_instantiation(self):
     new_tree = bst()
     self.assertTrue(new_tree != None)
コード例 #26
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    #   bn2_z = bn2(y.data[0,:], model.predictor.b1)
    #   f.writelines([str(val)+"\n" for val in bn2_z.tolist()])
    return z


argvs = sys.argv
unit = 1000
model = L.Classifier(BinaryMLP(784, unit, 10))

if len(argvs) > 1:
    chainer.serializers.load_npz(argvs[1], model)

    x = np.ones((1, 784), dtype=np.float32) * 128
    y1 = forward_linear(model.predictor.l1, x, "tmp/output_y.txt")
    z1 = forward_bn(model.predictor.b1, y1, "tmp/output_bn.txt")
    h1 = bst(z1)

    y2 = forward_linear(model.predictor.l2, h1, "tmp/output_y2.txt")
    z2 = forward_bn(model.predictor.b2, y2, "tmp/output_bn2.txt")
    h2 = bst(z2)

    y3 = forward_linear(model.predictor.l3, h2, "tmp/output_y3.txt")
    z3 = forward_bn(model.predictor.b3, y3, "tmp/output_bn3.txt")

#
# chainer.serializers.load_npz(argvs[1], model)
# train, test = chainer.datasets.get_mnist()
# row = train[0]
# data, teacher = row
# model.predictor(data.reshape(1, 784))
#
コード例 #27
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 def __call__(self, x):
     h1 = bst.bst(self.b1(self.c1(x), test=not self.train))
     h2 = bst.bst(self.b2(self.c2(h1), test=not self.train))
     h3 = bst.bst(self.b3(self.c3(h2), test=not self.train))
     h4 = bst.bst(self.b4(self.l1(h3), test=not self.train))
     return self.b5(self.l2(h4), test=not self.train)
コード例 #28
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 def test_add_node_when_smaller(self):
     new_tree = bst(20)
     smaller_node = bst(19)
     new_tree.add(smaller_node)
     self.assertTrue(new_tree.get_left_child().value == smaller_node.value)
コード例 #29
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def check_tree(tree, lower_bound=None, upper_bound=None):
    '''return true if tree is BST'''
    if lower_bound and tree.data <= lower_bound:
        return False
    if upper_bound and tree.data >= upper_bound:
        return False

    new_upper = min(upper_bound, tree.data) if upper_bound else tree.data
    if tree.left and not check_tree(tree.left, lower_bound, new_upper):
        return False

    new_lower = max(lower_bound, tree.data) if lower_bound else tree.data
    if tree.right and not check_tree(tree.right, new_lower, upper_bound):
        return False

    return True


tree = bst.bst(19)
tree.insert_list([7, 43, 3, 111, 23, 47, 2, 5, 17, 37, 53, 13, 29, 41, 31])

print tree
print check_tree(tree)
tree.left.data = 20
print tree
print check_tree(tree)
tree.left.data = 7
tree.left.right.data = 20
print tree
print check_tree(tree)
コード例 #30
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start_time = time.time()

f = open('names_1.txt', 'r')
names_1 = f.read().split("\n")  # List containing 10000 names
f.close()

f = open('names_2.txt', 'r')
names_2 = f.read().split("\n")  # List containing 10000 names
f.close()

duplicates = []  # Return the list of duplicates in this data structure

# Replace the nested for loops below with your improvements
# iterate over list 1
new_bst = bst(names_1[0])
for el in names_1:
    new_bst.insert(el)

# see if any elements in names_2 are also in new_bst, if so add them to the duplicates array
for el in names_2:
    if new_bst.contains(el):
        duplicates.append(el)

end_time = time.time()
print(f"{len(duplicates)} duplicates:\n\n{', '.join(duplicates)}\n\n")
print(f"runtime: {end_time - start_time} seconds")

# ---------- Stretch Goal -----------
# Python has built-in tools that allow for a very efficient approach to this problem
# What's the best time you can accomplish?  Thare are no restrictions on techniques or data