コード例 #1
0
ファイル: orangesRotting.py プロジェクト: Yigang0622/LeetCode
    def orangesRotting(self, grid: List[List[int]]) -> int:
        q = collections.deque()
        Array.print2DArray(grid)
        h = len(grid)
        w = len(grid[0])
        for i in range(h):
            for j in range(w):
                if grid[i][j] == 2:
                    q.append((i, j))

        time = 0
        while (q):
            print(q)
            for _ in range(len(q)):
                i, j = q.popleft()
                grid[i][j] = 2
                for i_next, j_next in [(i + 1, j), (i - 1, j), (i, j + 1),
                                       (i, j - 1)]:
                    if 0 <= i_next < h and 0 <= j_next < w and grid[i_next][
                            j_next] == 1:
                        grid[i_next][j_next] = -1
                        q.append((i_next, j_next))

            time += 1
            Array.print2DArray(grid)
            print()

        for i in range(h):
            for j in range(w):
                if grid[i][j] == 1:
                    return -1
        if time == 0:
            return 0
        else:
            return time - 11
コード例 #2
0
ファイル: canPartition.py プロジェクト: Yigang0622/LeetCode
    def canPartition(self, nums: List[int]) -> bool:
        if len(nums) < 2:
            return False

        sum_of_nums = sum(nums)
        max_of_nums = max(nums)
        if sum_of_nums % 2 != 0:
            return False

        target = sum_of_nums // 2
        if max_of_nums > target:
            return False

        dp = [[0] * (int(target) + 1) for _ in range(len(nums))]

        for each in dp:
            each[0] = 1

        dp[0][nums[0]] = 1

        for i in range(1, len(nums)):
            for j in range(1, int(target) + 1):
                if j < nums[i]:
                    dp[i][j] = dp[i - 1][j]
                else:
                    dp[i][j] = dp[i - 1][j] or dp[i - 1][j - nums[i]]

        array.print2DArray(dp)
        return dp[-1][-1] == 1
コード例 #3
0
ファイル: pathInMatrix.py プロジェクト: Yigang0622/LeetCode
    def exist(self, board: List[List[str]], word: str) -> bool:
        Array.print2DArray(board)

        rows = len(board)
        w = len(board[0])

        visited = [[0] * w for _ in range(rows)]
        for i in range(rows):
            for j in range(w):
                if not self.solved:
                    self.search(board, visited, w, rows, i, j, word)
        return self.solved
コード例 #4
0
        dirs = [(-1, -1), (1, 1), (1, -1), (-1, 1)]

        for direction in dirs:
            if self.canHitDiagonal(board, n, i, j, direction):
                return False

        return True

    def canHitDiagonal(self, board, n, i, j, direction) -> bool:
        v, h = direction
        next_i = i + v
        next_j = j + h

        if next_i < 0 or next_i >= n or next_j < 0 or next_j >= n:
            return False
        if board[next_i][next_j] == 'Q':
            return True

        return self.canHitDiagonal(board, n, next_i, next_j, direction)

    def renderResult(self, board):
        result = [''.join(x) for x in board]
        return result


r = Solution().solveNQueens(4)
for i, each in enumerate(r):
    print('solution {}'.format(i + 1))
    Array.print2DArray(each)
    print()
コード例 #5
0
                    i += 1
                elif direction == 'd':
                    direction = 'l'
                    i -= 1
                    j -= 1
                elif direction == 'l':
                    direction = 'u'
                    j += 1
                    i -= 1
                elif direction == 'u':
                    direction = 'r'
                    j += 1
                    i += 1

            visited[i][j] = 1
            m[i][j] = count
            count += 1
            if direction == 'r':
                j += 1
            elif direction == 'd':
                i += 1
            elif direction == 'l':
                j -= 1
            elif direction == 'u':
                i -= 1
        return m


m = Solution().generateMatrix(2)
Array.print2DArray(m)
コード例 #6
0
        w = len(grid[0])
        count = 0
        for i in range(h):
            for j in range(w):
                if grid[i][j] == 1:
                    c = self.dfs(i, j, w, h, grid)
                    if c != 1:
                        count += c
        return count

    def dfs(self, i, j, w, h, grid):
        count = 0
        for y in range(h):
            if grid[y][j] == 1:
                grid[y][j] = 2
                count += 1 + self.dfs(y, j, w, h, grid)
        for x in range(w):
            if grid[i][x] == 1:
                grid[i][x] = 2
                count += 1 + self.dfs(i, x, w, h, grid)
        return count


grid = [[0,0,0,1,0,0,0,0,0,0],[1,0,1,0,0,0,0,0,0,0],[0,0,0,0,0,0,0,0,0,0],[0,1,0,0,0,0,0,1,0,0]]
Array.print2DArray(grid)
r = Solution().countServers(grid)
print()
Array.print2DArray(grid)

print(r)
コード例 #7
0
                virtual_start = (i * N + j) * 4
                if grid[i][j] == '/':
                    union_find.union(virtual_start + 1, virtual_start + 2)
                    union_find.union(virtual_start + 0, virtual_start + 3)

                elif grid[i][j] == '\\':
                    union_find.union(virtual_start + 0, virtual_start + 1)
                    union_find.union(virtual_start + 2, virtual_start + 3)
                else:
                    union_find.union(virtual_start + 1, virtual_start + 0)
                    union_find.union(virtual_start + 2, virtual_start + 1)
                    union_find.union(virtual_start + 3, virtual_start + 2)
                # print(i,j)
                # 不是某行第一个
                if j != 0:
                    # print('union row')
                    union_find.union(virtual_start, virtual_start - 2)

                # 不是某列第一个
                if i != 0:
                    # print('union column')
                    union_find.union(virtual_start + 3,
                                     virtual_start - N * 4 + 1)
        # union_find.print()
        return union_find.num_of_groups


grid = ["//", "/ "]
array.print2DArray(grid)
r = Solution().regionsBySlashes(grid)
print(r)
コード例 #8
0
            if 0 <= i_next < h and 0 <= j_next < w:
                if board[i_next][j_next] == 'M':
                    count += 1
        return count


b = [["E", "E", "E", "E", "E", "E", "E", "E"],
     ["E", "E", "E", "E", "E", "E", "E", "M"],
     ["E", "E", "M", "E", "E", "E", "E", "E"],
     ["M", "E", "E", "E", "E", "E", "E", "E"],
     ["E", "E", "E", "E", "E", "E", "E", "E"],
     ["E", "E", "E", "E", "E", "E", "E", "E"],
     ["E", "E", "E", "E", "E", "E", "E", "E"],
     ["E", "E", "M", "M", "E", "E", "E", "E"]]

click = [0, 0]
Array.print2DArray(b)

r = Solution().updateBoard(board=b, click=click)

Array.print2DArray(b)

print()
Array.print2DArray([["B", "B", "B", "B", "B", "B", "1", "E"],
                    ["B", "1", "1", "1", "B", "B", "1", "M"],
                    ["1", "2", "M", "1", "B", "B", "1", "1"],
                    ["M", "2", "1", "1", "B", "B", "B", "B"],
                    ["1", "1", "B", "B", "B", "B", "B", "B"],
                    ["B", "B", "B", "B", "B", "B", "B", "B"],
                    ["B", "1", "2", "2", "1", "B", "B", "B"],
                    ["B", "1", "M", "M", "1", "B", "B", "B"]])
コード例 #9
0
ファイル: gameOfLife.py プロジェクト: Yigang0622/LeetCode
        for i in range(h):
            for j in range(w):
                cnt = self.numberOfLiveCells(i, j, w, h, board)
                if board[i][j] == 0:  # dead
                    if cnt == 3:
                        next_state[i][j] = 1
                else:  # live:
                    if cnt == 2 or cnt == 3:
                        next_state[i][j] = 1

        for i in range(h):
            for j in range(w):
                board[i][j] = next_state[i][j]

    def numberOfLiveCells(self, i, j, w, h, board):
        start_i = i - 1
        start_j = j - 1
        count = 0
        for i_next in range(start_i, start_i + 3):
            for j_next in range(start_j, start_j + 3):
                if 0 <= i_next < h and 0 <= j_next < w and board[i_next][
                        j_next] == 1 and (i_next, j_next) != (i, j):
                    count += 1
        return count


board = [[0, 1, 0], [0, 0, 1], [1, 1, 1], [0, 0, 0]]
array.print2DArray(board)
print()
s = Solution().gameOfLife(board)
array.print2DArray(board)
コード例 #10
0
        return ans

    def render_line(self, words, words_len, target_len):
        gap_num = len(words) - 1
        if gap_num == 0:  # 这一行可能只有一个单词
            return self.render_last_line(words, target_len)
        spaces_total = target_len - words_len
        spaces = [spaces_total // gap_num] * gap_num
        for i in range(spaces_total % gap_num):
            spaces[i] += 1
        # print(spaces)
        result = ""
        for i in range(len(words)):
            result += words[i]
            if i < len(spaces):
                result += ' ' * spaces[i]
        # print(result)
        return result

    def render_last_line(self, words, target_len):
        result = " ".join(words)
        extra_spaces = target_len - len(result)
        result += " " * extra_spaces
        return result


words = ["What", "must", "be", "acknowledgment", "shall", "be"]
maxWidth = 16
s = Solution().fullJustify(words, maxWidth)
array.print2DArray(s)
コード例 #11
0
        for i in range(h):
            for j in range(w):
                if land[i][j] == 0:
                    a = []
                    self.search(land, w, h, i, j, a)
                    heapq.heappush(result, len(a))
        return heapq.nsmallest(len(result), result)

    def search(self, land, w, h, i, j, ans):
        if i < 0 or i >= h or j < 0 or j >= w:
            return
        if land[i][j] != 0:
            return
        if land[i][j] == 0:
            land[i][j] = 1
            ans.append(0)
            self.search(land, w, h, i + 1, j + 1, ans)
            self.search(land, w, h, i - 1, j - 1, ans)
            self.search(land, w, h, i + 1, j - 1, ans)
            self.search(land, w, h, i - 1, j + 1, ans)
            self.search(land, w, h, i - 1, j, ans)
            self.search(land, w, h, i + 1, j, ans)
            self.search(land, w, h, i, j + 1, ans)
            self.search(land, w, h, i, j - 1, ans)


land = [[0, 2, 1, 0], [0, 1, 0, 1], [1, 1, 0, 1], [0, 1, 0, 1]]
Array.print2DArray(land)
r = Solution().pondSizes(land)
print(r)
コード例 #12
0
ファイル: findCircleNum.py プロジェクト: Yigang0622/LeetCode
class Solution:
    def findCircleNum(self, M: List[List[int]]) -> int:
        n = len(M)
        if n == 0:
            return 0
        count = 0
        visited = [False for _ in range(n)]
        for i in range(n):
            if not visited[i]:
                # Search
                self.search(M, visited, i)
                count += 1
                # print(i)
                # print(visited)

        return count

    def search(self, M, visited, i):
        n = len(M)
        for j in range(n):
            if not visited[j] and M[i][j] == 1:  # 是朋友
                visited[j] = True
                self.search(M, visited, j)  # 找j的朋友


M = [[1, 1, 0, 0, 0, 0], [1, 1, 0, 0, 0, 0], [0, 0, 1, 1, 1, 0],
     [0, 0, 1, 1, 0, 0], [0, 0, 1, 0, 1, 0], [0, 0, 0, 0, 0, 1]]
Array.print2DArray(M)
r = Solution().findCircleNum(M)
print(r)