コード例 #1
0
ファイル: 20120507b.py プロジェクト: argriffing/xgcode
 def __call__(self):
     """
     Look for a counterexample.
     """
     # Sample a rate matrix.
     # Use a trick by Robert Kern to left and right multiply by diagonals.
     # http://mail.scipy.org/pipermail/numpy-discussion/2007-March/
     # 026809.html
     S = MatrixUtil.sample_pos_sym_matrix(self.nstates)
     v = mrate.sample_distn(self.nstates)
     R = (v**-0.5)[:,np.newaxis] * S * (v**0.5)
     R -= np.diag(np.sum(R, axis=1))
     # Construct a parent-independent process
     # with the same max rate and stationary distribution
     # as the sampled process.
     #max_rate = max(-np.diag(R))
     #expected_rate = np.dot(v, -np.diag(R))
     #logical_entropy = np.dot(v, 1-v)
     #randomization_rate = expected_rate / logical_entropy
     Q = self.simplification(R)
     #Q = np.outer(np.ones(self.nstates), v)
     #Q -= np.diag(np.sum(Q, axis=1))
     #Q *= max(np.diag(R) / np.diag(Q))
     # sample a random time
     t = random.expovariate(1)
     # Check that the mutual information of the
     # parent independent process is smaller.
     mi_R = ctmcmi.get_expected_ll_ratio(R, t)
     mi_Q = ctmcmi.get_expected_ll_ratio(Q, t)
     if np.allclose(mi_R, mi_Q):
         self.n_too_close += 1
         return False
     if mi_R < mi_Q:
         out = StringIO()
         print >> out, 'found a counterexample'
         print >> out
         print >> out, 'sampled symmetric matrix S:'
         print >> out, S
         print >> out
         print >> out, 'sampled stationary distribution v:'
         print >> out, v
         print >> out
         print >> out, 'implied rate matrix R:'
         print >> out, R
         print >> out
         print >> out, 'parent independent process Q:'
         print >> out, Q
         print >> out
         print >> out, 'sampled time t:', t
         print >> out
         print >> out, 'mutual information of sampled process:', mi_R
         print >> out, 'mutual information of p.i. process:', mi_Q
         print >> out
         self.counterexample = out.getvalue().rstrip()
         return True
コード例 #2
0
 def __call__(self):
     """
     Look for a counterexample.
     """
     # Sample a rate matrix.
     # Use a trick by Robert Kern to left and right multiply by diagonals.
     # http://mail.scipy.org/pipermail/numpy-discussion/2007-March/
     # 026809.html
     S = MatrixUtil.sample_pos_sym_matrix(self.nstates)
     v = mrate.sample_distn(self.nstates)
     R = (v**-0.5)[:, np.newaxis] * S * (v**0.5)
     R -= np.diag(np.sum(R, axis=1))
     # Construct a parent-independent process
     # with the same max rate and stationary distribution
     # as the sampled process.
     #max_rate = max(-np.diag(R))
     #expected_rate = np.dot(v, -np.diag(R))
     #logical_entropy = np.dot(v, 1-v)
     #randomization_rate = expected_rate / logical_entropy
     Q = self.simplification(R)
     #Q = np.outer(np.ones(self.nstates), v)
     #Q -= np.diag(np.sum(Q, axis=1))
     #Q *= max(np.diag(R) / np.diag(Q))
     # sample a random time
     t = random.expovariate(1)
     # Check that the mutual information of the
     # parent independent process is smaller.
     mi_R = ctmcmi.get_expected_ll_ratio(R, t)
     mi_Q = ctmcmi.get_expected_ll_ratio(Q, t)
     if np.allclose(mi_R, mi_Q):
         self.n_too_close += 1
         return False
     if mi_R < mi_Q:
         out = StringIO()
         print >> out, 'found a counterexample'
         print >> out
         print >> out, 'sampled symmetric matrix S:'
         print >> out, S
         print >> out
         print >> out, 'sampled stationary distribution v:'
         print >> out, v
         print >> out
         print >> out, 'implied rate matrix R:'
         print >> out, R
         print >> out
         print >> out, 'parent independent process Q:'
         print >> out, Q
         print >> out
         print >> out, 'sampled time t:', t
         print >> out
         print >> out, 'mutual information of sampled process:', mi_R
         print >> out, 'mutual information of p.i. process:', mi_Q
         print >> out
         self.counterexample = out.getvalue().rstrip()
         return True
コード例 #3
0
ファイル: 20120522a.py プロジェクト: argriffing/xgcode
 def __call__(self):
     """
     Look for a counterexample.
     """
     # Sample a rate matrix.
     # Use a trick by Robert Kern to left and right multiply by diagonals.
     # http://mail.scipy.org/pipermail/numpy-discussion/2007-March/
     # 026809.html
     S = MatrixUtil.sample_pos_sym_matrix(self.nstates)
     v = mrate.sample_distn(self.nstates)
     R = (v**-0.5)[:,np.newaxis] * S * (v**0.5)
     R -= np.diag(np.sum(R, axis=1))
     # sample a random time
     rate = 1.0 / self.etime
     t = random.expovariate(rate)
     # sample one side of the bipartition and get the mutual information
     k = random.randrange(1, self.nstates)
     A = random.sample(range(self.nstates), k)
     mi_non_markov = get_mutual_information(R, A, t)
     # get summary statistics of the non-markov process
     Q = msimpl.get_fast_two_state(R, A)
     mi_markov = ctmcmi.get_expected_ll_ratio(Q, t)
     # check if the mutual informations are indistinguishable
     if np.allclose(mi_non_markov, mi_markov):
         self.n_too_close += 1
         return False
     if mi_non_markov < mi_markov:
         out = StringIO()
         print >> out, 'found a counterexample'
         print >> out
         print >> out, 'sampled symmetric matrix S:'
         print >> out, S
         print >> out
         print >> out, 'sampled stationary distribution v:'
         print >> out, v
         print >> out
         print >> out, 'implied rate matrix R:'
         print >> out, R
         print >> out
         print >> out, 'reduced rate matrix Q'
         print >> out, Q
         print >> out
         print >> out, 'sampled time t:', t
         print >> out
         print >> out, 'non-markov mutual information:', mi_non_markov
         print >> out, 'markov mutual information:', mi_markov
         print >> out
         self.counterexample = out.getvalue().rstrip()
         return True
コード例 #4
0
ファイル: 20120522a.py プロジェクト: BIGtigr/xgcode
 def __call__(self):
     """
     Look for a counterexample.
     """
     # Sample a rate matrix.
     # Use a trick by Robert Kern to left and right multiply by diagonals.
     # http://mail.scipy.org/pipermail/numpy-discussion/2007-March/
     # 026809.html
     S = MatrixUtil.sample_pos_sym_matrix(self.nstates)
     v = mrate.sample_distn(self.nstates)
     R = (v**-0.5)[:, np.newaxis] * S * (v**0.5)
     R -= np.diag(np.sum(R, axis=1))
     # sample a random time
     rate = 1.0 / self.etime
     t = random.expovariate(rate)
     # sample one side of the bipartition and get the mutual information
     k = random.randrange(1, self.nstates)
     A = random.sample(range(self.nstates), k)
     mi_non_markov = get_mutual_information(R, A, t)
     # get summary statistics of the non-markov process
     Q = msimpl.get_fast_two_state(R, A)
     mi_markov = ctmcmi.get_expected_ll_ratio(Q, t)
     # check if the mutual informations are indistinguishable
     if np.allclose(mi_non_markov, mi_markov):
         self.n_too_close += 1
         return False
     if mi_non_markov < mi_markov:
         out = StringIO()
         print >> out, 'found a counterexample'
         print >> out
         print >> out, 'sampled symmetric matrix S:'
         print >> out, S
         print >> out
         print >> out, 'sampled stationary distribution v:'
         print >> out, v
         print >> out
         print >> out, 'implied rate matrix R:'
         print >> out, R
         print >> out
         print >> out, 'reduced rate matrix Q'
         print >> out, Q
         print >> out
         print >> out, 'sampled time t:', t
         print >> out
         print >> out, 'non-markov mutual information:', mi_non_markov
         print >> out, 'markov mutual information:', mi_markov
         print >> out
         self.counterexample = out.getvalue().rstrip()
         return True
コード例 #5
0
ファイル: 20111202a.py プロジェクト: BIGtigr/xgcode
def make_table(args, distn_modes):
    """
    Make outputs to pass to RUtil.get_table_string.
    @param args: user args
    @param distn_modes: ordered distribution modes
    @return: matrix, headers
    """
    # define some variables
    t_low = args.t_low
    t_high = args.t_high
    if t_high <= t_low:
        raise ValueError('low time must be smaller than high time')
    ntimes = 100
    incr = (t_high - t_low) / (ntimes - 1)
    n = args.nstates
    # define some tables
    distn_mode_to_f = {
            UNIFORM : get_distn_uniform,
            ONE_INC : get_distn_one_inc,
            TWO_INC : get_distn_two_inc,
            ONE_DEC : get_distn_one_dec,
            TWO_DEC : get_distn_two_dec}
    selection_mode_to_f = {
            BALANCED : mrate.to_gtr_balanced,
            HALPERN_BRUNO : mrate.to_gtr_halpern_bruno}
    # define the selection modes and calculators
    selection_f = selection_mode_to_f[args.selection]
    distn_fs = [distn_mode_to_f[m] for m in distn_modes]
    # define the headers
    headers = ['t'] + [s.replace('_', '.') for s in distn_modes]
    # define the numbers in the table
    S = np.ones((n, n), dtype=float)
    S -= np.diag(np.sum(S, axis=1))
    arr = []
    for i in range(ntimes):
        t = t_low + i * incr
        row = [t]
        for distn_f in distn_fs:
            v = distn_f(n, args.sel_surr)
            R = selection_f(S, v)
            expected_log_ll_ratio = ctmcmi.get_expected_ll_ratio(R, t)
            row.append(expected_log_ll_ratio)
        arr.append(row)
    return np.array(arr), headers
コード例 #6
0
ファイル: 20111202a.py プロジェクト: argriffing/xgcode
def make_table(args, distn_modes):
    """
    Make outputs to pass to RUtil.get_table_string.
    @param args: user args
    @param distn_modes: ordered distribution modes
    @return: matrix, headers
    """
    # define some variables
    t_low = args.t_low
    t_high = args.t_high
    if t_high <= t_low:
        raise ValueError("low time must be smaller than high time")
    ntimes = 100
    incr = (t_high - t_low) / (ntimes - 1)
    n = args.nstates
    # define some tables
    distn_mode_to_f = {
        UNIFORM: get_distn_uniform,
        ONE_INC: get_distn_one_inc,
        TWO_INC: get_distn_two_inc,
        ONE_DEC: get_distn_one_dec,
        TWO_DEC: get_distn_two_dec,
    }
    selection_mode_to_f = {BALANCED: mrate.to_gtr_balanced, HALPERN_BRUNO: mrate.to_gtr_halpern_bruno}
    # define the selection modes and calculators
    selection_f = selection_mode_to_f[args.selection]
    distn_fs = [distn_mode_to_f[m] for m in distn_modes]
    # define the headers
    headers = ["t"] + [s.replace("_", ".") for s in distn_modes]
    # define the numbers in the table
    S = np.ones((n, n), dtype=float)
    S -= np.diag(np.sum(S, axis=1))
    arr = []
    for i in range(ntimes):
        t = t_low + i * incr
        row = [t]
        for distn_f in distn_fs:
            v = distn_f(n, args.sel_surr)
            R = selection_f(S, v)
            expected_log_ll_ratio = ctmcmi.get_expected_ll_ratio(R, t)
            row.append(expected_log_ll_ratio)
        arr.append(row)
    return np.array(arr), headers
コード例 #7
0
def get_response_content(fs):
    np.set_printoptions(linewidth=200)
    out = StringIO()
    R_jc = get_jc_rate_matrix()
    t = 0.1
    x = 1.6
    w = 0.5 * log(x)
    v = x_to_distn(x)
    R_hb_easy = mrate.to_gtr_halpern_bruno(R_jc, v)
    y, z, = mrate.x_to_halpern_bruno_yz(x)
    yz_ratio = y / z
    R_hb_tedious = get_mut_sel_rate_matrix(y, z)
    P_hb_easy = get_trans_mat_expm(R_hb_easy, t)
    P_hb_tedious = get_trans_mat_tediously(y, z, t)
    P_hb_tedious_c = get_trans_mat_tediously_c(y, z, t)
    P_hb_from_x = get_trans_mat_from_x(x, t)
    e_ll_jc = ctmcmi.get_expected_ll_ratio(R_jc, t)
    e_ll_jc_tedious = get_jc_e_ll(t)
    e_ll_hb = ctmcmi.get_expected_ll_ratio(R_hb_easy, t)
    e_ll_hb_from_x = get_e_ll_from_x(x, t)
    e_ll_hb_from_x_b = get_e_ll_from_x_b(x, t)
    e_ll_hb_from_x_htrig = get_e_ll_from_x_htrig(x, t)
    # print some values
    print >> out, 'Jukes-Cantor mutation matrix:'
    print >> out, R_jc
    print >> out
    print >> out, 'ratio of common to uncommon probabilities:'
    print >> out, x
    print >> out
    print >> out, '1/2 log ratio:'
    print >> out, w
    print >> out
    print >> out, 'fast rate:'
    print >> out, y
    print >> out
    print >> out, 'slow rate:'
    print >> out, z
    print >> out
    print >> out, 'reciprocal of fast rate:'
    print >> out, 1.0 / y
    print >> out
    print >> out, 'ratio of fast to slow rates (should be x):'
    print >> out, yz_ratio
    print >> out
    print >> out, 'mutation-selection rate matrix (easy):'
    print >> out, R_hb_easy
    print >> out
    print >> out, 'mutation-selection rate matrix (tedious):'
    print >> out, R_hb_tedious
    print >> out
    print >> out, 'time:'
    print >> out, t
    print >> out
    print >> out, 'mutation-selection transition matrix (easy):'
    print >> out, P_hb_easy
    print >> out
    print >> out, 'mutation-selection transition matrix (tedious):'
    print >> out, P_hb_tedious
    print >> out
    print >> out, 'mutation-selection transition matrix (tedious c):'
    print >> out, P_hb_tedious_c
    print >> out
    print >> out, 'mutation-selection transition matrix (from x):'
    print >> out, P_hb_from_x
    print >> out
    print >> out, 'expected Jukes-Cantor log likelihood ratio:'
    print >> out, e_ll_jc
    print >> out
    print >> out, 'expected Jukes-Cantor log likelihood ratio (tedious):'
    print >> out, e_ll_jc_tedious
    print >> out
    print >> out, 'expected mutation-selection log likelihood ratio:'
    print >> out, e_ll_hb
    print >> out
    print >> out, 'expected mutation-selection ll ratio from x:'
    print >> out, e_ll_hb_from_x
    print >> out
    print >> out, 'expected mutation-selection ll ratio from x (impl b):'
    print >> out, e_ll_hb_from_x_b
    print >> out
    print >> out, 'expected mutation-selection ll ratio from x (htrig):'
    print >> out, e_ll_hb_from_x_htrig
    print >> out
    # check some invariants
    if np.allclose(R_hb_easy, R_hb_tedious):
        print >> out, 'halpern-bruno rate matrices are equal as expected'
    else:
        print >> out, '*** halpern-bruno rate matrices are not equal!'
    if np.allclose(P_hb_easy, P_hb_tedious):
        print >> out, 'halpern-bruno transition matrices are equal as expected'
    else:
        print >> out, '*** halpern-bruno transition matrices are not equal!'
    if np.allclose(P_hb_easy, P_hb_tedious_c):
        print >> out, 'halpern-bruno transition matrices are equal as expected'
    else:
        print >> out, '*** halpern-bruno transition matrices are not equal!'
    if np.allclose(P_hb_easy, P_hb_from_x):
        print >> out, 'halpern-bruno transition matrices are equal as expected'
    else:
        print >> out, '*** halpern-bruno trans. mat. from x is not equal!'
    # return the results
    return out.getvalue()
コード例 #8
0
ファイル: 20120507c.py プロジェクト: BIGtigr/xgcode
def process(fs):
    nstates = fs.nstates
    np.set_printoptions(linewidth=200)
    t = fs.t
    ### sample a random time
    ##time_mu = 0.01
    ##t = random.expovariate(1 / time_mu)
    # Sample a rate matrix.
    # Use a trick by Robert Kern to left and right multiply by diagonals.
    # http://mail.scipy.org/pipermail/numpy-discussion/2007-March/
    # 026809.html
    S = MatrixUtil.sample_pos_sym_matrix(nstates)
    v = mrate.sample_distn(nstates)
    R = (v**-0.5)[:,np.newaxis] * S * (v**0.5)
    R -= np.diag(np.sum(R, axis=1))
    # Construct a parent-independent process
    # with the same max rate and stationary distribution
    # as the sampled process.
    if fs.parent_indep:
        Q = np.outer(np.ones(nstates), v)
        Q -= np.diag(np.sum(Q, axis=1))
        pi_rescaling_factor = max(np.diag(R) / np.diag(Q))
        Q *= pi_rescaling_factor
        Z = msimpl.get_fast_meta_f81_autobarrier(Q)
    # Construct a child-independent process
    # with the same expected rate
    # as the sampled process
    if fs.child_indep:
        C = np.outer(1/v, np.ones(nstates))
        C -= np.diag(np.sum(C, axis=1))
        ci_rescaling_factor = np.max(R / C)
        #expected_rate = -ndot(np.diag(R), v)
        #ci_rescaling_factor = expected_rate / (nstates*(nstates-1))
        #ci_rescaling_factor = expected_rate / (nstates*nstates)
        C *= ci_rescaling_factor
        Q = C
    if fs.bipartitioned:
        Q = msimpl.get_fast_meta_f81_autobarrier(R)
    # Check that the mutual information of the
    # parent independent process is smaller.
    out = StringIO()
    print >> out, 'sampled symmetric part of the rate matrix S:'
    print >> out, S
    print >> out
    print >> out, 'sampled stationary distribution v:'
    print >> out, v
    print >> out
    print >> out, 'shannon entropy of stationary distribution v:'
    print >> out, -np.dot(np.log(v), v)
    print >> out
    print >> out, 'sqrt stationary distribution:'
    print >> out, np.sqrt(v)
    print >> out
    print >> out, 'implied rate matrix R:'
    print >> out, R
    print >> out
    print >> out, 'eigenvalues of R:', scipy.linalg.eigvals(R)
    print >> out
    print >> out, 'relaxation rate of R:',
    print >> out, sorted(np.abs(scipy.linalg.eigvals(R)))[1]
    print >> out
    print >> out, 'expected rate of R:', mrate.Q_to_expected_rate(R)
    print >> out
    print >> out, 'cheeger bounds of R:', get_cheeger_bounds(R, v)
    print >> out
    print >> out, 'randomization rate of R:', get_randomization_rate(R, v)
    print >> out
    candidates = [get_randomization_candidate(R, v, i) for i in range(nstates)]
    if np.allclose(get_randomization_rate(R, v), candidates):
        print >> out, 'all candidates are equal to this rate'
    else:
        print >> out, 'not all candidates are equal to this rate'
    print >> out
    print >> out, 'simplified rate matrix Q:'
    print >> out, Q
    print >> out
    qv = mrate.R_to_distn(Q)
    print >> out, 'stationary distribution of Q:'
    print >> out, qv
    print >> out
    print >> out, 'ratio qv/v:'
    print >> out, qv / v
    print >> out
    print >> out, 'shannon entropy of stationary distribution of Q:'
    print >> out, -np.dot(np.log(qv), qv)
    print >> out
    if fs.parent_indep:
        print >> out, 'parent independent rescaling factor:'
        print >> out, pi_rescaling_factor
        print >> out
    if fs.child_indep:
        print >> out, 'child independent rescaling factor:'
        print >> out, ci_rescaling_factor
        print >> out
    print >> out, 'eigenvalues of Q:', scipy.linalg.eigvals(Q)
    print >> out
    print >> out, 'relaxation rate of Q:',
    print >> out, sorted(np.abs(scipy.linalg.eigvals(Q)))[1]
    print >> out
    print >> out, 'expected rate of Q:', mrate.Q_to_expected_rate(Q)
    print >> out
    print >> out, 'cheeger bounds of Q:', get_cheeger_bounds(Q, v)
    print >> out
    print >> out, 'randomization rate of Q:', get_randomization_rate(Q, v)
    print >> out
    candidates = [get_randomization_candidate(Q, v, i) for i in range(nstates)]
    if np.allclose(get_randomization_rate(Q, v), candidates):
        print >> out, 'all candidates are equal to this rate'
    else:
        print >> out, 'warning: not all candidates are equal to this rate'
    print >> out
    print >> out, 'E(rate) of Q divided by logical entropy:',
    print >> out, mrate.Q_to_expected_rate(Q) / ndot(v, 1-v)
    print >> out
    print >> out, 'symmetric matrix similar to Q:'
    S = ndot(np.diag(np.sqrt(v)), Q, np.diag(1/np.sqrt(v)))
    print >> out, S
    print >> out
    print >> out, 'eigendecomposition of the similar matrix:'
    W, V = scipy.linalg.eigh(S)
    print >> out, V
    print >> out, np.diag(W)
    print >> out, V.T
    print >> out
    #
    print >> out, 'time:', t
    print >> out
    print >> out, 'stationary distn logical entropy:', ndot(v, 1-v)
    print >> out
    # 
    P_by_hand = get_pi_transition_matrix(Q, v, t)
    print >> out, 'simplified-process transition matrix computed by hand:'
    print >> out, P_by_hand
    print >> out
    print >> out, 'simplified-process transition matrix computed by expm:'
    print >> out, scipy.linalg.expm(Q*t)
    print >> out
    #
    print >> out, 'simplified-process m.i. by hand:'
    print >> out, get_pi_mi(Q, v, t)
    print >> out
    print >> out, 'simplified-process m.i. by expm:'
    print >> out, ctmcmi.get_expected_ll_ratio(Q, t)
    print >> out
    #
    print >> out, 'original process m.i. by expm:'
    print >> out, ctmcmi.get_expected_ll_ratio(R, t)
    print >> out
    #
    print >> out, 'stationary distn Shannon entropy:'
    print >> out, -ndot(v, np.log(v))
    print >> out
    #
    if fs.parent_indep:
        print >> out, 'approximate simplified process m.i. 2nd order approx:'
        print >> out, get_pi_mi_t2_approx(Q, v, t)
        print >> out
        print >> out, 'approximate simplified process m.i. "better" approx:'
        print >> out, get_pi_mi_t2_diag_approx(Q, v, t)
        print >> out
        print >> out, '"f81-ization plus barrier" of pure f81-ization:'
        print >> out, Z
        print >> out
    #
    return out.getvalue().rstrip()