コード例 #1
0
def resolve_by_name(func, name, *args):
    """
    Helper to resolve a "name" a'la foo.com to it's ID by using REST api's
    query support and filtering on name.
    """
    if uuidutils.is_uuid_like(name):
        return name

    results = func(criterion={"name": "%s" % name}, *args)
    length = len(results)

    if length == 1:
        return results[0]["id"]
    elif length == 0:
        raise exceptions.NotFound("Name %s didn't resolve" % name)
    else:
        msg = "Multiple matches found for %s, please use ID instead." % name
        raise exceptions.NoUniqueMatch(msg)
コード例 #2
0
def find_resourceid_by_name_or_id(resource_client, name_or_id):
    """Find resource id from its id or name."""
    try:
        # Try to return an uuid
        return str(uuid.UUID(name_or_id))
    except ValueError:
        # Not an uuid => assume it is resource name
        pass

    resources = resource_client.list()
    candidate_ids = [r['id'] for r in resources if r.get('name') == name_or_id]
    if not candidate_ids:
        raise exceptions.ResourceNotFound(
            'Could not find resource with name "%s"' % name_or_id)
    elif len(candidate_ids) > 1:
        str_ids = ','.join(candidate_ids)
        raise exceptions.NoUniqueMatch(
            'Multiple resources with name "%s": %s' % (name_or_id, str_ids))
    return candidate_ids[0]