def intword(value):
"""
Convert a large integer to a friendly text representation. Works best
for numbers over 1 million. For example, 1000000 becomes '1.0 million',
1200000 becomes '1.2 million' and '1200000000' becomes '1.2 billion'.
"""
try:
value = int(value)
except (TypeError, ValueError):
return value
abs_value = abs(value)
if abs_value < 1000000:
return value
def _check_for_i18n(value, float_formatted, string_formatted):
"""
Use the i18n enabled defaultfilters.floatformat if possible
"""
if settings.USE_L10N:
value = defaultfilters.floatformat(value, 1)
template = string_formatted
else:
template = float_formatted
return template % {"value": value}
for exponent, converters in intword_converters:
large_number = 10 ** exponent
if abs_value < large_number * 1000:
new_value = value / large_number
rounded_value = round_away_from_one(new_value)
return _check_for_i18n(new_value, *converters(abs(rounded_value)))
return value
def intword(value):
"""
Convert a large integer to a friendly text representation. Works best
for numbers over 1 million. For example, 1000000 becomes '1.0 million',
1200000 becomes '1.2 million' and '1200000000' becomes '1.2 billion'.
"""
try:
value = int(value)
except (TypeError, ValueError):
return value
abs_value = abs(value)
if abs_value < 1000000:
return value
for exponent, converter in intword_converters:
large_number = 10**exponent
if abs_value < large_number * 1000:
new_value = value / large_number
rounded_value = round_away_from_one(new_value)
return converter(abs(rounded_value)) % {
"value": defaultfilters.floatformat(new_value, 1),
}
return value
