コード例 #1
0
def main():
    depth = 3  # depth of tree
    mean_ins = 6  # mean length of insertions
    var_ins = 4  # variance for length of insertions
    p_mutation = 0.001  # prob of a mutation (per base)
    p_del = 0.05  # prob of deletion
    mean_del = 4  # mean length of deletion
    var_del = 2  #variance for length of deletion
    #tree = gen_tree.generate_tree(depth, mean_ins, var_ins, p_mutation, p_del, mean_del, var_del)
    #leaves = tree[-1]
    #ai.entropy_leaves(leaves)
    # for leaf in leaves:
    # 	print gen_tree.stringify(leaf)
    # gen_tree.print_tree(tree)

    # try to generate multiple trees and figure out the mean/var of the entropies at each position.
    N = 100  # generate 100 trees.
    entropies = [[] for i in range(100)]
    max_length = 0
    for i in range(N):
        print 'generating tree %s/%s' % (i, N)
        tree = gen_tree.generate_tree(depth, mean_ins, var_ins, p_mutation,
                                      p_del, mean_del, var_del)
        _, entropy, length, _ = ai.entropy_leaves(tree[-1])
        for base_position in range(length):
            entropies[base_position].append(entropy[base_position])
        max_length = max(max_length, length)
コード例 #2
0
def main():
    # should be able to cPickle this.

    depth = 5  # depth of tree
    mean_ins = 6  # mean length of insertions
    var_ins = 2  # variance for length of insertions
    p_mutation = 0.0  # prob of a mutation (per base)
    p_del = 0.0  # prob of deletion
    mean_del = 4  # mean length of deletion
    var_del = 2  #variance for length of deletion

    parser = OptionParser()
    parser.add_option('-f', dest='fname', help='name of pkl file')
    (options, args) = parser.parse_args()

    tree = gen_tree.generate_tree(depth, mean_ins, var_ins, p_mutation, p_del,
                                  mean_del, var_del)
    f = open(options.fname, 'wb')

    cPickle.dump(tree, f)
    f.close()
コード例 #3
0
ファイル: 1530.py プロジェクト: lindo-zy/leetcode
class Solution:
    def countPairs(self, root: TreeNode) -> int:
        res = []

        def dfs(root, path, counter):
            if root:
                if counter <= 0:
                    res.append(path)
                    return

                if not root.left and not root.right:
                    res.append(path)
                    return
                else:
                    dfs(root.left, path + [root.val], counter - root.val)
                    dfs(root.right, path + [root.val], counter - root.val)

        dfs(root, [], 4)
        return res


if __name__ == '__main__':
    s = Solution()
    # root = [1, None, 2, None, 3, None, 4, None, 5,]
    root = [1, 2, 3, 4, None, None, 5]
    from gen_tree import generate_tree

    tree = generate_tree(root)
    print(s.countPairs(tree))
コード例 #4
0
ファイル: t4.py プロジェクト: lindo-zy/leetcode

class Solution:
    def increasingBST(self, root):
        self.res = []
        self.inOrder(root)
        if not self.res:
            return
        dummy = TreeNode(-1)
        cur = dummy
        for node in self.res:
            node.left = node.right = None
            cur.right = node
            cur = cur.right
        return dummy.right

    def inOrder(self, root):
        if not root:
            return
        self.inOrder(root.left)
        self.res.append(root)
        self.inOrder(root.right)


if __name__ == '__main__':
    s = Solution()
    root = [5, 3, 6, 2, 4, None, 8, 1, None, None, None, 7, 9]
    from gen_tree import generate_tree

    print(s.increasingBST(generate_tree(root)))
コード例 #5
0
ファイル: t1.py プロジェクト: lindo-zy/leetcode
        self.val = val
        self.left = left
        self.right = right


class Solution:
    def __init__(self):
        self.ans_left = []
        self.ans_right = []

    def isSameTree(self, p: TreeNode, q: TreeNode) -> bool:
        if not p and not q:
            return True
        if not p or not q:
            return False
        if p.val != q.val:
            return False
        return self.isSameTree(p.left, q.left) and self.isSameTree(
            p.right, q.right)


if __name__ == '__main__':
    from gen_tree import generate_tree

    s = Solution()
    p = [10, 5, 15]
    q = [10, 5, None, None, 15]
    p_tree = generate_tree(p)
    q_tree = generate_tree(q)
    print(s.isSameTree(p_tree, q_tree))
コード例 #6
0
#!/usr/bin/python3
# -*- coding:utf-8 -*-
class TreeNode:
    def __init__(self, val=0, left=None, right=None):
        self.val = val
        self.left = left
        self.right = right


class Solution:
    def isValidBST(self, root: TreeNode) -> bool:
        def dfs(node, min_val, max_val):
            if not node:
                return True
            if not min_val < node.val < max_val:
                return False

            return dfs(node.left, min_val, node.val) and dfs(
                node.right, node.val, max_val)

        return dfs(root, float('-inf'), float('inf'))


if __name__ == '__main__':
    s = Solution()
    root = [5, 1, 4, None, None, 3, 6]
    from gen_tree import generate_tree

    print(s.isValidBST(generate_tree(root)))
コード例 #7
0
ファイル: 1457.py プロジェクト: lindo-zy/leetcode
    def __init__(self, val=0, left=None, right=None):
        self.val = val
        self.left = left
        self.right = right


class Solution:
    def pseudoPalindromicPaths(self, root: TreeNode) -> int:
        self.ans = 0

        def dfs(root, record):
            if root:
                record ^= (1 << root.val)
                # 计算有多少个不同的数字
                if not (root.left or root.right):
                    if bin(record).count("1") < 2:
                        self.ans += 1
                    return
                dfs(root.left, record)
                dfs(root.right, record)

        dfs(root, 0)
        return self.ans


if __name__ == '__main__':
    root = [2, 3, 1, 3, 1, None, 1]
    tree = (generate_tree(root))
    s = Solution()
    print(s.pseudoPalindromicPaths(tree))
コード例 #8
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class TreeNode:
    def __init__(self, val=0, left=None, right=None):
        self.val = val
        self.left = left
        self.right = right


class Solution:
    def __init__(self):
        self.pre = 0

    def convertBST(self, root: TreeNode) -> TreeNode:
        def dfs(root):
            if not root:
                return
            dfs(root.right)
            root.val += self.pre
            self.pre = root.val
            dfs(root.left)

        dfs(root)
        return root


if __name__ == '__main__':
    s = Solution()
    root = [4, 1, 6, 0, 2, 5, 7, None, None, None, 3, None, None, None, 8]
    from gen_tree import generate_tree

    print(s.convertBST(generate_tree(root)))
コード例 #9
0
ファイル: 623.py プロジェクト: lindo-zy/leetcode
        self.right = right


class Solution:
    def addOneRow(self, root: TreeNode, v: int, d: int) -> TreeNode:
        def dfs(root, level, flag):  # flag用来表示当前遍历到的节点是其双亲节点的左孩子节点还是右孩子节点
            if root:  # 不是根节点的状态
                if level == d:  # 到达了指定替换的行了
                    new_root = TreeNode(v)
                    if not flag:
                        new_root.left = root
                    else:
                        new_root.right = root
                    return new_root
                root.left = dfs(root.left, level + 1, 0)
                root.right = dfs(root.right, level + 1, 1)
                return root
            return TreeNode(v) if level == d else None  # 比较特殊 因为最后一行的下一行也可能是指定行

        return dfs(root, 1, 0)


if __name__ == '__main__':
    s = Solution()
    root = [4, 2, 6, 3, 1, 5]
    val = 1
    depth = 2
    from gen_tree import generate_tree

    print(s.addOneRow(generate_tree(root), val, depth))
コード例 #10
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class TreeNode:
    def __init__(self, val=0, left=None, right=None):
        self.val = val
        self.left = left
        self.right = right


class Solution:
    def postorderTraversal(self, root: TreeNode) -> List[int]:
        self.ans = []

        def dfs(root):
            if not root:
                return
            else:
                dfs(root.left)
                dfs(root.right)
                self.ans.append(root.val)

        dfs(root)
        return self.ans


if __name__ == '__main__':
    from gen_tree import generate_tree

    s = Solution()
    root = [1, None, 2, 3]
    print(s.postorderTraversal(generate_tree(root)))
コード例 #11
0
                self.parents[root.right.val] = root
                get_parent(root.right)

        self.res = []
        get_parent(root)

        def dfs(root, node, k):
            if k == 0:
                self.res.append(root.val)
                return
            if root.left and root.left != node:
                dfs(root.left, root, k - 1)
            if root.right and root.right != node:
                dfs(root.right, root, k - 1)
            if root.val in self.parents and self.parents[root.val] != node:
                dfs(self.parents[root.val], root, k - 1)

        dfs(target, None, k)
        return self.res


if __name__ == '__main__':
    s = Solution()
    root = [3, 5, 1, 6, 2, 0, 8, None, None, 7, 4]
    target = 5
    K = 2

    from gen_tree import generate_tree

    print(s.distanceK(generate_tree(root), generate_tree([target]), K))
コード例 #12
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    def __init__(self, val=0, left=None, right=None):
        self.val = val
        self.left = left
        self.right = right


class Solution:
    def findSecondMinimumValue(self, root: TreeNode) -> int:
        self.ans = set()

        def dfs(node):
            if node is not None:
                dfs(node.left)
                self.ans.add(node.val)
                dfs(node.right)

        dfs(root)
        res = sorted(list(self.ans))
        if len(res) > 1:
            return res[1]
        return -1


if __name__ == '__main__':
    s = Solution()
    from gen_tree import generate_tree

    root = [2, 2, 5, None, None, 5, 7]

    print(s.findSecondMinimumValue(generate_tree(root)))
コード例 #13
0
ファイル: t1.py プロジェクト: lindo-zy/leetcode
class TreeNode:
    def __init__(self, val=0, left=None, right=None):
        self.val = val
        self.left = left
        self.right = right


class Solution:
    def averageOfLevels(self, root: TreeNode) -> List[float]:
        cnt, level_sum = [], []

        def dfs(root, depth):
            if root:
                if len(cnt) < depth:
                    cnt.append(0)
                    level_sum.append(0)
                cnt[depth - 1] += 1
                level_sum[depth - 1] += root.val
                dfs(root.left, depth + 1)
                dfs(root.right, depth + 1)

        dfs(root, 1)
        return [s / c for s, c in zip(level_sum, cnt)]


if __name__ == '__main__':
    s = Solution()
    nums = [3, 9, 20, None, None, 15, 7]
    root = generate_tree(nums)
    print(s.averageOfLevels(root))
コード例 #14
0
ファイル: 437.py プロジェクト: lindo-zy/leetcode
from collections import Counter


class Solution:
    def pathSum(self, root: TreeNode, sum: int) -> int:
        def dfs(root, pre, cnt):
            if not root:
                return 0
            cnt += root.val
            ans = pre[cnt - sum]
            pre[cnt] += 1
            if root.left:
                ans += dfs(root.left, pre, cnt)
            if root.right:
                ans += dfs(root.right, pre, cnt)
            pre[cnt] -= 1
            return ans

        return dfs(root, Counter([0]), 0)


if __name__ == '__main__':
    s = Solution()

    from gen_tree import generate_tree

    root = [10, 5, -3, 3, 2, None, 11, 3, -2, None, 1]
    targetSum = 8
    print(s.pathSum(generate_tree(root), targetSum))