コード例 #1
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ファイル: question002.py プロジェクト: fxleyu/python-nest
    def addTwoNumbers(self, l1, l2):
        """
        :type l1: ListNode
        :type l2: ListNode
        :rtype: ListNode
        """
        carryNum = 0
        work1 = l1
        work2 = l2
        preResult = ListNode(0)
        temp =  preResult
        while work1 != None or work2 != None:
            if work1 != None :
                carryNum += work1.val
                work1 = work1.next
            if work2 != None :
                carryNum += work2.val
                work2 = work2.next
            temp.next = ListNode(carryNum % 10)
            temp = temp.next
            if carryNum > 9 :
                carryNum = 1
            else :
                carryNum = 0

        if carryNum > 0 :
            temp.next = ListNode(1)

        return preResult.next
コード例 #2
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def list2linked(nums: List[int]) -> ListNode:
    head = ListNode(nums[0])
    curr = head
    for i in range(1, len(nums)):
        curr.next = ListNode(nums[i])
        curr = curr.next
    return head
コード例 #3
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 def add(self, value):
     tmp_node = ListNode(value)
     if self._head_node is None:
         self._head_node = tmp_node
     else:
         tmp_node.set_next_node(self._head_node)
         self._head_node = tmp_node
コード例 #4
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ファイル: reverseList.py プロジェクト: zcg741/leetcode
 def reverseList(self, head: ListNode) -> ListNode:
     tmpNode = head
     newNode = None
     while tmpNode != None:
         newFlagListNode = ListNode(tmpNode.val)
         newFlagListNode.next = newNode
         newNode = newFlagListNode
         tmpNode = tmpNode.next
     return newNode
コード例 #5
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def num2linked(num: int) -> ListNode:
    if not num:
        return ListNode(0)
    curr = None
    while num:
        node = ListNode(num % 10)
        if curr is not None:
            node.next = curr
        curr = node
        num //= 10
    return curr
コード例 #6
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def removeNthFromEnd2(head: ListNode, n: int) -> ListNode:
    dummy = ListNode(-1)
    dummy.next = head
    node, i, dictionary = dummy, 0, {}
    while node is not None:
        dictionary[i] = node
        i = i + 1
        node = node.next
    # print(i)
    prev = dictionary[i - 1 - n]
    prev.next = prev.next.next
    return dummy.next  # cannot return head as it can be removed
コード例 #7
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def test(n1: List[int], n2: List[int], s1: int, s2: int) -> None:
    h1 = ListNode.make(n1[: s1])
    t1 = h1
    while t1.next is not None:
        t1 = t1.next
    h2 = ListNode.make(n2[: s2])
    t2 = h2
    while t2.next is not None:
        t2 = t2.next
    h3 = ListNode.make(n1[s1:])
    t1.next = t2.next = h3
    # print(h1, h2)
    print(getIntersectionNode(h1, h2))
コード例 #8
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def removeNthFromEnd(head: ListNode, n: int) -> ListNode:
    dummy = ListNode(-1)
    dummy.next = head
    node, i = dummy, 0
    while node is not None:
        i = i + 1
        node = node.next
    n = i - n - 1  # convert to nth from head
    node = dummy
    for i in range(n):
        node = node.next
    node.next = node.next.next
    return dummy.next  # cannot return head as it can be removed
コード例 #9
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ファイル: ex0141_cycledLinked.py プロジェクト: sunxiaoou/py
def get_linked(nums: List[int], pos: int) -> ListNode:
    n, dummy = len(nums), ListNode(-1)
    curr = dummy
    temp = tail = None
    for i in range(n):
        curr.next = ListNode(nums[i])
        curr = curr.next
        if pos == i:
            temp = curr
        if i == n - 1:
            tail = curr
    if pos >= 0:
        tail.next = temp
    return dummy.next
コード例 #10
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ファイル: removeElements.py プロジェクト: zcg741/leetcode
 def removeElements(self, head: ListNode, val: int) -> ListNode:
     newNode = ListNode(head.val)
     newTmpNode = newNode
     tmpNode = head
     while tmpNode.next != None:
         if tmpNode.val != val:
             newTmpNode.next = ListNode(tmpNode.val)
             newTmpNode = newTmpNode.next
         tmpNode = tmpNode.next
     if tmpNode.val != val:
         if tmpNode.val != val:
             newTmpNode.next = ListNode(tmpNode.val)
             newTmpNode = newTmpNode.next
     if val == newNode.val: return newNode.next
     return newNode.next
コード例 #11
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ファイル: No2AddTwoNumbers.py プロジェクト: Qiujm/MyPython
 def addTwoNumbers2(self,l1,l2):
     carry = 0
     root = n = ListNode(0)
     while l1 or l2 or carry:
         v1 = v2 = 0
         if l1:
             v1 = l1.val
             l1 = l1.next
         if l2:
             v2 = l2.val
             l2 = l2.next
         carry, val = divmod(v1 + v2 + carry, 10)
         n.next = ListNode(val)
         n = n.next
     return root.next
コード例 #12
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def mergeTwoLists2(l1: ListNode, l2: ListNode) -> ListNode:
    nums = []
    for head in [l1, l2]:
        while head is not None:
            insort(nums, head.val)
            head = head.next
    return ListNode.make(nums)
コード例 #13
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ファイル: ex0023_mergeKLists.py プロジェクト: sunxiaoou/py
def mergeKLists(lists: List[ListNode]) -> ListNode:
    nums = []
    for head in lists:
        while head is not None:
            insort(nums, head.val)
            head = head.next
    return ListNode.make(nums)
コード例 #14
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def test(nums: List[int], val: int) -> None:
    head = ListNode.make(nums)
    node = head
    while node is not None:
        if node.val == val:
            break
        node = node.next
    else:
        return
    deleteNode(node)
    print(head)
コード例 #15
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 def addTwoNumbers(self, l1: ListNode, l2: ListNode) -> ListNode:
   # Baseline t o(n), s o(n)
   summation = ListNode(0)
   head = summation
   carry = 0
   while (l1 is not None or l2 is not None):
     n1 = 0
     if (l1 is not None):
       n1 = l1.value()
       l1 = l1.next()
     n2 = 0  
     if (l2 is not None):
       n2 = l2.value()
       l2 = l2.next()
     summation.next = ListNode((n1 + n2 + carry) % 10)
     carry = (n1 + n2) // 10
     summation = summation.next
   if (carry > 0):
     summation.next = ListNode(carry)
   return (head.next)
コード例 #16
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def addTwoNumbers(l1, l2):
    """
    :type l1: ListNode
    :type l2: ListNode
    :rtype: ListNode
    """
    dummy = ListNode(0)
    pivot = dummy
    carry = 0
    while l1 or l2:
        v1 = l1.val if l1 else 0
        v2 = l2.val if l2 else 0
        carry, val = divmod(v1 + v2 + carry, 10)
        pivot.next = ListNode(val)
        pivot = pivot.next
        l1 = l1.next if l1 else None
        l2 = l2.next if l2 else None
    if carry:
        pivot.next = ListNode(carry)
    return dummy.next
コード例 #17
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ファイル: lc_23_mergeKLists.py プロジェクト: hyt0617/leetcode
def mergeKLists(lists):
    """
    :type lists: List[ListNode]
    :rtype: ListNode
    """
    import heapq
    my_queue = []
    for sll in lists:
        head = sll
        while head:
            heapq.heappush(my_queue, head.val)
            head = head.next
    my_queue.sort()
    if my_queue:
        head = ListNode(my_queue[0])
        cur = head
        for i in range(1, len(my_queue)):
            tmp = ListNode(my_queue[i])
            cur.next = tmp
            cur = tmp
        return head
コード例 #18
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def reverseBetween(head, m, n):
    if not head:
        return head
    dummy = ListNode(-1)
    dummy.next = head

    m_prev = dummy
    for i in range(m - 1):
        m_prev = m_prev.next

    m_cur = m_prev.next
    rev_head = m_cur
    for i in range(n - m):
        next_ele = m_cur.next
        next_link = next_ele.next
        next_ele.next = rev_head
        rev_head = next_ele
        m_cur.next = next_link

    m_prev.next = rev_head
    return dummy.next
コード例 #19
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ファイル: lc_86.py プロジェクト: hyt0617/leetcode
def partition(head, x):
    """
    :type head: ListNode
    :type x: int
    :rtype: ListNode
    """
    less = ListNode(-1)
    eg = ListNode(-1)
    pivot = head
    less_pivot = less
    eg_pivot = eg
    while pivot:
        if pivot.val < x:
            less_pivot.next = pivot
            less_pivot = less_pivot.next
        if pivot.val >= x:
            eg_pivot.next = pivot
            eg_pivot = eg_pivot.next
        pivot = pivot.next
    eg_pivot.next = None
    less_pivot.next = eg.next
    return less.next
コード例 #20
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ファイル: No2AddTwoNumbers.py プロジェクト: Qiujm/MyPython
 def addTwoNumbers(self, l1, l2):
     """
     :type l1: ListNode
     :type l2: ListNode
     :rtype: ListNode
     """
     head1=l1
     head2=l2
     root =n= ListNode(0)
     carry=0
     while head1 or head2 or carry:
         val1 = val2 = 0
         if head1:
             val1 = head1.val
             head1=head1.next
         if head2:
             val2 = head2.val
             head2=head2.next
         carry,val = divmod(val1+val2+carry,10)
         # n.val = val
         n.next=ListNode(val)
         n=n.next
     return  root.next
コード例 #21
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ファイル: lc_82.py プロジェクト: hyt0617/leetcode
def deleteDuplicates(head):
    """
    :type head: ListNode
    :rtype: ListNode
    """
    dmh = ListNode(-1)
    temp = dmh
    while head:
        if head.next and head.val == head.next.val:
            x = head.val
            while head and head.val == x:
                head = head.next
        else:
            temp.next = head
            head = head.next
            temp = temp.next
    temp.next = None
    return dmh.next
コード例 #22
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def oddEvenList(head: ListNode) -> ListNode:
    if head is None:
        return None
    prev = head
    node = head.next
    h2 = ListNode(-1)
    even = h2
    i = 0
    while node is not None:
        if not i % 2:
            prev.next = node.next
            even.next = node
            even = node
        else:
            prev = node
        node = node.next
        i += 1
    even.next = None
    prev.next = h2.next
    return head
コード例 #23
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ファイル: No19RemoveNthNode.py プロジェクト: Qiujm/MyPython
from listNode import ListNode


class Solution(object):
    def removeNthFromEnd(self, head, n):
        """
        :type head: ListNode
        :type n: int
        :rtype: ListNode
        """
        if not head.next:
            return
        slow = fast = head
        for i in range(n):
            fast = fast.next
        if not fast:
            head = head.next
            return head

        while fast.next:
            fast = fast.next
            slow = slow.next
        slow.next = slow.next.next
        return head


node = ListNode(1)
node.next = ListNode(2)
result = Solution().removeNthFromEnd(node, 2)
print(result.val)
コード例 #24
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def main():
    print(removeDuplicateNodes(ListNode.make([])))  # None
    print(removeDuplicateNodes(ListNode.make([1, 2, 3, 3, 2, 1])))  # [1, 2, 3]
    print(removeDuplicateNodes(ListNode.make([1, 1, 1, 1, 2])))  # [1, 2]
コード例 #25
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def main():
    print(removeNthFromEnd(ListNode.make([1, 2, 3, 4, 5]), 2))  # 1->2->3->5
    print(removeNthFromEnd(ListNode.make([1, 2]), 2))  # 2
    print(removeNthFromEnd(ListNode.make([1]), 1))  # None
コード例 #26
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ファイル: No2AddTwoNumbers.py プロジェクト: Qiujm/MyPython
    def addTwoNumbers2(self,l1,l2):
        carry = 0
        root = n = ListNode(0)
        while l1 or l2 or carry:
            v1 = v2 = 0
            if l1:
                v1 = l1.val
                l1 = l1.next
            if l2:
                v2 = l2.val
                l2 = l2.next
            carry, val = divmod(v1 + v2 + carry, 10)
            n.next = ListNode(val)
            n = n.next
        return root.next

    def printList(self,l1):
        node = l1
        while node:
            print(node.val,end=',')
            node=node.next

l1 = ListNode(2)
l1.next = ListNode(4)
l1.next.next = ListNode(3)
l2= ListNode(5)
l2.next = ListNode(6)
l2.next.next = ListNode(4)
lyst = Solution().addTwoNumbers(l1,l2)
Solution().printList(lyst)
コード例 #27
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ファイル: reverseList.py プロジェクト: zcg741/leetcode

class Solution:
    def reverseList(self, head: ListNode) -> ListNode:
        tmpNode = head
        newNode = None
        while tmpNode != None:
            newFlagListNode = ListNode(tmpNode.val)
            newFlagListNode.next = newNode
            newNode = newFlagListNode
            tmpNode = tmpNode.next
        return newNode


s = Solution()
head1 = ListNode(1)
head2 = ListNode(2)
head3 = ListNode(3)
head4 = ListNode(4)
head46 = ListNode(6)
head5 = ListNode(5)
head6 = ListNode(6)
head1.next = head2
head2.next = head3
head3.next = head4
head4.next = head46
head46.next = head5
head5.next = head6
print(head1)
newListNode = s.reverseList(head1)
print(newListNode)
コード例 #28
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def main():
    # test
    A = ListNode('A')
    B = ListNode('B')
    C = ListNode('C')
    D = ListNode('D')
    E = ListNode('E')
    F = ListNode('F')
    G = ListNode('G')

    A.next, B.next, C.next, D.next, E.next, F.next = B, C, D, E, F, G
    G.next = B
    # print(A.traverse()) #this will enter a loop when linked list has a cycle

    print(has_cycle(A))
    print(has_cycle_inplace(A))
コード例 #29
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def main():
	# test
	A = ListNode('A')
	B = ListNode('B')
	C = ListNode('C')
	D = ListNode('D')
	E = ListNode('E')
	F = ListNode('F')
	G = ListNode('G')
	H = ListNode('H')
	I = ListNode('I')
	A.next, B.next, C.next, D.next = B, C, D, E
	# E.next, F.next = F, D
	print(A.traverse())
	print(E.traverse())
コード例 #30
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def main():
    print(reverseList(ListNode.make([1, 2, 3, 4, 5])))  # 5->4->3->2->1