コード例 #1
0
    def find_sync_regions(self):
        """Return a list of sync regions, where both descendants match the base.

        Generates a list of (base1, base2, a1, a2, b1, b2).  There is
        always a zero-length sync region at the end of all the files.
        """

        ia = ib = 0
        amatches = mdiff.get_matching_blocks(self.basetext, self.atext)
        bmatches = mdiff.get_matching_blocks(self.basetext, self.btext)
        len_a = len(amatches)
        len_b = len(bmatches)

        sl = []

        while ia < len_a and ib < len_b:
            abase, amatch, alen = amatches[ia]
            bbase, bmatch, blen = bmatches[ib]

            # there is an unconflicted block at i; how long does it
            # extend?  until whichever one ends earlier.
            i = intersect((abase, abase + alen), (bbase, bbase + blen))
            if i:
                intbase = i[0]
                intend = i[1]
                intlen = intend - intbase

                # found a match of base[i[0], i[1]]; this may be less than
                # the region that matches in either one
                assert intlen <= alen
                assert intlen <= blen
                assert abase <= intbase
                assert bbase <= intbase

                asub = amatch + (intbase - abase)
                bsub = bmatch + (intbase - bbase)
                aend = asub + intlen
                bend = bsub + intlen

                assert self.base[intbase:intend] == self.a[asub:aend], \
                       (self.base[intbase:intend], self.a[asub:aend])

                assert self.base[intbase:intend] == self.b[bsub:bend]

                sl.append((intbase, intend,
                           asub, aend,
                           bsub, bend))

            # advance whichever one ends first in the base text
            if (abase + alen) < (bbase + blen):
                ia += 1
            else:
                ib += 1

        intbase = len(self.base)
        abase = len(self.a)
        bbase = len(self.b)
        sl.append((intbase, intbase, abase, abase, bbase, bbase))

        return sl
コード例 #2
0
    def find_sync_regions(self):
        """Return a list of sync regions, where both descendants match the base.

        Generates a list of (base1, base2, a1, a2, b1, b2).  There is
        always a zero-length sync region at the end of all the files.
        """

        ia = ib = 0
        amatches = mdiff.get_matching_blocks(self.basetext, self.atext)
        bmatches = mdiff.get_matching_blocks(self.basetext, self.btext)
        len_a = len(amatches)
        len_b = len(bmatches)

        sl = []

        while ia < len_a and ib < len_b:
            abase, amatch, alen = amatches[ia]
            bbase, bmatch, blen = bmatches[ib]

            # there is an unconflicted block at i; how long does it
            # extend?  until whichever one ends earlier.
            i = intersect((abase, abase + alen), (bbase, bbase + blen))
            if i:
                intbase = i[0]
                intend = i[1]
                intlen = intend - intbase

                # found a match of base[i[0], i[1]]; this may be less than
                # the region that matches in either one
                assert intlen <= alen
                assert intlen <= blen
                assert abase <= intbase
                assert bbase <= intbase

                asub = amatch + (intbase - abase)
                bsub = bmatch + (intbase - bbase)
                aend = asub + intlen
                bend = bsub + intlen

                assert self.base[intbase:intend] == self.a[asub:aend], \
                       (self.base[intbase:intend], self.a[asub:aend])

                assert self.base[intbase:intend] == self.b[bsub:bend]

                sl.append((intbase, intend, asub, aend, bsub, bend))

            # advance whichever one ends first in the base text
            if (abase + alen) < (bbase + blen):
                ia += 1
            else:
                ib += 1

        intbase = len(self.base)
        abase = len(self.a)
        bbase = len(self.b)
        sl.append((intbase, intbase, abase, abase, bbase, bbase))

        return sl
コード例 #3
0
    def reprocess_merge_regions(self, merge_regions):
        """Where there are conflict regions, remove the agreed lines.

        Lines where both A and B have made the same changes are
        eliminated.
        """
        for region in merge_regions:
            if region[0] != "conflict":
                yield region
                continue
            type, iz, zmatch, ia, amatch, ib, bmatch = region
            a_region = self.a[ia:amatch]
            b_region = self.b[ib:bmatch]
            matches = mdiff.get_matching_blocks(''.join(a_region),
                                                ''.join(b_region))
            next_a = ia
            next_b = ib
            for region_ia, region_ib, region_len in matches[:-1]:
                region_ia += ia
                region_ib += ib
                reg = self.mismatch_region(next_a, region_ia, next_b,
                                           region_ib)
                if reg is not None:
                    yield reg
                yield 'same', region_ia, region_len + region_ia
                next_a = region_ia + region_len
                next_b = region_ib + region_len
            reg = self.mismatch_region(next_a, amatch, next_b, bmatch)
            if reg is not None:
                yield reg
コード例 #4
0
    def reprocess_merge_regions(self, merge_regions):
        """Where there are conflict regions, remove the agreed lines.

        Lines where both A and B have made the same changes are
        eliminated.
        """
        for region in merge_regions:
            if region[0] != "conflict":
                yield region
                continue
            type, iz, zmatch, ia, amatch, ib, bmatch = region
            a_region = self.a[ia:amatch]
            b_region = self.b[ib:bmatch]
            matches = mdiff.get_matching_blocks(''.join(a_region),
                                                ''.join(b_region))
            next_a = ia
            next_b = ib
            for region_ia, region_ib, region_len in matches[:-1]:
                region_ia += ia
                region_ib += ib
                reg = self.mismatch_region(next_a, region_ia, next_b,
                                           region_ib)
                if reg is not None:
                    yield reg
                yield 'same', region_ia, region_len + region_ia
                next_a = region_ia + region_len
                next_b = region_ib + region_len
            reg = self.mismatch_region(next_a, amatch, next_b, bmatch)
            if reg is not None:
                yield reg
コード例 #5
0
    def find_unconflicted(self):
        """Return a list of ranges in base that are not conflicted."""
        am = mdiff.get_matching_blocks(self.basetext, self.atext)
        bm = mdiff.get_matching_blocks(self.basetext, self.btext)

        unc = []

        while am and bm:
            # there is an unconflicted block at i; how long does it
            # extend?  until whichever one ends earlier.
            a1 = am[0][0]
            a2 = a1 + am[0][2]
            b1 = bm[0][0]
            b2 = b1 + bm[0][2]
            i = intersect((a1, a2), (b1, b2))
            if i:
                unc.append(i)

            if a2 < b2:
                del am[0]
            else:
                del bm[0]

        return unc
コード例 #6
0
    def find_unconflicted(self):
        """Return a list of ranges in base that are not conflicted."""
        am = mdiff.get_matching_blocks(self.basetext, self.atext)
        bm = mdiff.get_matching_blocks(self.basetext, self.btext)

        unc = []

        while am and bm:
            # there is an unconflicted block at i; how long does it
            # extend?  until whichever one ends earlier.
            a1 = am[0][0]
            a2 = a1 + am[0][2]
            b1 = bm[0][0]
            b2 = b1 + bm[0][2]
            i = intersect((a1, a2), (b1, b2))
            if i:
                unc.append(i)

            if a2 < b2:
                del am[0]
            else:
                del bm[0]

        return unc