def addLists(n1, n2):
if (n1 is None) or (n2 is None):
return None
head = ListNode(0)
cur = head
prev = None
carry = 0
while (n1 is not None) or (n2 is not None):
val = carry
if n1 is not None:
val += n1.val
n1 = n1.nxt
if n2 is not None:
val += n2.val
n2 = n2.nxt
cur.val = val % 10
carry = val // 10
cur.nxt = ListNode(0)
prev = cur
cur = cur.nxt
if carry:
cur.val = carry
else:
prev.nxt = None
return head
def __init__(self, repo, parent=None):
all_heads = [GitTreeNode(head.object.tree, parent=self, name=head.name) for head in repo.heads]
children = [
GitTreeNode(repo.head.object.tree, parent=self, name=repo.head.name),
ListNode(self, all_heads, name="all heads"),
]
ListNode.__init__(self, parent, children)
self.repo_ = repo
def test():
n1 = ListNode(3)
appendToTail(n1, 1)
appendToTail(n1, 7)
n2 = ListNode(5)
appendToTail(n2, 9)
appendToTail(n2, 2)
printList(n1)
printList(n2)
s = addLists(n1, n2)
printList(s)
def addAtTail(self, val: int) -> None:
"""
Append a node of value val to the last element of the linked list.
"""
if not self.tail:
self.tail = self.head = ListNode(val)
return
self.tail.next = ListNode(val)
self.tail = self.tail.next
self.size += 1
def add_two_numbers(self, l1: ListNode, l2: ListNode) -> ListNode:
flag = 0
add_sum, flag = self.add_two(l1.val, l2.val, flag)
_start = start = ListNode(add_sum)
while l1.next is not None or l2.next is not None or flag == 1:
l1_next_val, l1 = (0, l1) if l1.next is None else (l1.next.val,
l1.next)
l2_next_val, l2 = (0, l2) if l2.next is None else (l2.next.val,
l2.next)
add_sum, flag = self.add_two(l1_next_val, l2_next_val, flag)
start.next = ListNode(add_sum)
start = start.next
return _start
def addTwoNums(l1, l2):
l1Num = l2Num = ''
n1, n2 = l1, l2
while True:
if n1 is not None:
l1Num += str(n1.val)
if n1.next is None:
break
else:
n1 = n1.next
while True:
if n2 is not None:
l2Num += str(n2.val)
if n2.next is None:
break
else:
n2 = n2.next
sumNum = int(l1Num[::-1]) + int(l2Num[::-1])
r1 = str(sumNum)[::-1]
r2 = list(map(lambda x: ListNode(x), r1))
for i in range(len(r1) - 1):
r2[i].next = r2[i + 1]
node = r2[0]
return node
def reverse_list(L):
head = ListNode('HEAD', L)
list_iter = head.next
while list_iter.next:
temp = list_iter.next
list_iter.next, temp.next, head.next = temp.next, head.next, temp
return head.next
def addAtIndex(self, index: int, val: int) -> None:
"""
Add a node of value val before the index-th node in the linked list. If index equals to the length of linked list, the node will be appended to the end of linked list. If index is greater than the length, the node will not be inserted.
"""
prev, p, count = None, self.head, 0
while p:
if count == index:
# insert at position here
break
prev = p
p = p.next
count += 1
if count == 0:
self.addAtHead(val)
return
if count == self.size:
self.addAtTail(val)
return
if count > self.size:
return
assert prev is not None
prev.next = ListNode(val)
prev.next.next = p
self.size += 1
def reverseList2(self, head: ListNode) -> ListNode:
if not head or head.next == None:
return head
res = self.reverseList2(head.next)
head.next.next = head
head.next = None
return res
def removeNthFromEnd3(self, head: ListNode, n: int) -> ListNode:
if not head:
self.count = 0
return head
head.next = self.removeNthFromEnd3(head.next, n)
self.count += 1
return head.next if self.count == n else head
def removeNthFromEnd2(self, head: ListNode, n: int) -> ListNode:
# dummy,添加头节点
dummy = ListNode(0)
dummy.next = head
# 快指针先走 n 步
slow, fast = dummy, dummy
for _ in range(n):
fast = fast.next
# 快慢指针同时走，直到 fast 指针达到链表尾部节点，此时 slow 到达倒数第 n 个节点的前一个节点
while fast and fast.next:
slow, fast = slow.next, fast.next
# 删除节点并重新链接
slow.next = slow.next.next
return dummy.next
def list_value(self):
self.tree.append(ListNode())
while self.token[0] in (token_types.atom, token_types.string):
if self.token[0] == token_types.atom:
self.atom()
else:
self.value()
self.expect(token_types.list_end)
self.tree.pop()
def merge(self, l1: ListNode, l2: ListNode) -> ListNode:
"""Merge two lists"""
root = pre = ListNode()
while l1 and l2:
if l1.val < l2.val:
pre.next = ListNode(l1.val)
l1 = l1.next
else:
pre.next = ListNode(l2.val)
l2 = l2.next
pre = pre.next
if l1:
pre.next = l1
if l2:
pre.next = l2
return root.next
def test():
n = ListNode(3)
appendToTail(n, 1)
appendToTail(n, 4)
appendToTail(n, 2)
appendToTail(n, 3)
appendToTail(n, 3)
appendToTail(n, 2)
printList(n)
deleteDupsWithoutBuffer(n)
printList(n)
def test():
n = ListNode(3)
appendToTail(n, 1)
appendToTail(n, 4)
appendToTail(n, 2)
appendToTail(n, 3)
appendToTail(n, 3)
appendToTail(n, 2)
printList(n)
deleteNode(n)
printList(n)
def hasCycle5(self, head: ListNode) -> bool:
# 5. 标记val
while head:
# s = getattr(head, 's', None) # 获取s属性
# if s: # 判断s属性
if head.val == '1':
return True
# head.s = 1 # 添加s属性
head.val = '1'
head = head.next
return False
def removeNthFromEnd(self, head: ListNode, n: int) -> ListNode:
# dummy,添加头节点
dummy = ListNode(0)
dummy.next = head
# 获取链表长度
cur, lenth = head, 0
while cur:
lenth += 1
cur = cur.next
# 找到倒数第 n 个节点前的那个节点
cur = dummy
# 以示例为例，注意长度是 5 而不是 4
for _ in range(lenth - n):
cur = cur.next
# 删除节点并重新链接
cur.next = cur.next.next
return dummy.next
def test():
n = ListNode(3)
appendToTail(n, 1)
appendToTail(n, 4)
appendToTail(n, 2)
appendToTail(n, 3)
appendToTail(n, 3)
appendToTail(n, 2)
printList(n)
print("4th to last:", nthToLast(n, 4))
print("6th to last:", nthToLast(n, 6))
def addAtHead(self, val: int) -> None:
"""
Add a node of value val before the first element of the linked list. After the insertion, the new node will be the first node of the linked list.
"""
tmp = self.head
self.head = ListNode(val)
self.head.next = tmp
if not self.tail:
self.tail = self.head
self.size += 1
def reverse_sublist(L, s, f):
head = sublist_head = ListNode('HEAD', L)
for _ in range(1, s):
sublist_head = sublist_head.next
sublist_iter = sublist_head.next
for _ in range(f - s):
temp = sublist_iter.next
sublist_iter.next, temp.next, sublist_head.next = temp.next, sublist_head.next, temp
return head.next
def add(self, item): ''' adds an item to the list ''' if item is not instanceof(Node): item = ListNode(item) if self.head is None: self.head = item else: self.tail.next = item self.tail = item return
def merge_lists(L1, L2):
res = head = ListNode(data='HEAD')
tail = ListNode()
L1, L2 = L1.next, L2.next # filter out dummy head nodes
while L1 and L2:
if L1.data <= L2.data:
head.next = L1
L1 = L1.next
else: # L2.data < L1.data
head.next = L2
L2 = L2.next
head = head.next
while L1:
head.next = L1
L1 = L1.next
head = head.next
while L2:
head.next = L2
L2 = L2.next
head = head.next
head = tail
return res
def merge_sorted_lists(L1, L2):
""" Assume L1 and L2 are sorted """
head = tail = ListNode('HEAD')
while L1 and L2:
if L1.data <= L2.data:
tail.next = L1
L1 = L1.next
else: # L2.data < L1.data
tail.next = L2
L2 = L2.next
tail = tail.next
# print(head)
# print("L1", L1)
# print("L2", L2)
tail.next = L1 or L2
return head.next
def test():
a = ListNode('A')
b = ListNode('B')
c = ListNode('C')
d = ListNode('D')
e = ListNode('E')
a.nxt = b
b.nxt = c
c.nxt = d
d.nxt = e
e.nxt = c
print(findBeginning(a).val)
return head.next
def reverse_list(L):
head = ListNode('HEAD', L)
list_iter = head.next
while list_iter.next:
temp = list_iter.next
list_iter.next, temp.next, head.next = temp.next, head.next, temp
return head.next
if __name__ == '__main__':
print('Revers a single sublist!')
n2 = ListNode(2)
n7 = ListNode(7, n2)
n5 = ListNode(5, n7)
n3 = ListNode(3, n5)
n11 = ListNode(11, n3)
L = n11
print("L -> {}".format(L))
L = reverse_sublist(L, 2, 4)
print("L -> {}".format(L))
n2 = ListNode(2)
n7 = ListNode(7, n2)
n5 = ListNode(5, n7)
n3 = ListNode(3, n5)
n11 = ListNode(11, n3)
sumNum = int(l1Num[::-1]) + int(l2Num[::-1])
r1 = str(sumNum)[::-1]
r2 = list(map(lambda x: ListNode(x), r1))
for i in range(len(r1) - 1):
r2[i].next = r2[i + 1]
node = r2[0]
return node
# Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
# Output: 7 -> 0 -> 8
n2 = ListNode(2)
n4 = ListNode(4)
n3 = ListNode(3)
n2.next = n4
n4.next = n3
l5 = ListNode(5)
l6 = ListNode(6)
l4 = ListNode(4)
l5.next = l6
l6.next = l4
r = addTwoNums(n2, l5)
while r is not None:
print(r.val)
class Solution:
def getIntersectionNode(self, headA: ListNode,
headB: ListNode) -> ListNode:
""""""
nodeA, nodeB = headA, headB
while nodeA != nodeB:
nodeA = nodeA.next if nodeA else headB
nodeB = nodeB.next if nodeB else headA
return nodeA
if __name__ == '__main__':
s = Solution()
# [4, 1, 8, 4, 5]
# [5, 6, 1, 8, 4, 5]
nodei = ListNode(8)
nodei.next = ListNode(4)
nodei.next.next = ListNode(5)
headA = ListNode(4)
headA.next = ListNode(1)
headA.next.next = nodei
headB = ListNode(5)
headB.next = ListNode(6)
headB.next.next = ListNode(1)
headB.next.next.next = nodei
# [2,6,4]
# [1, 5]
# headA = ListNode(2)
head.next = L1
L1 = L1.next
head = head.next
while L2:
head.next = L2
L2 = L2.next
head = head.next
head = tail
return res
if __name__ == '__main__':
print("Merging two sorted linked lists!")
n7 = ListNode(data=7)
n5 = ListNode(data=5, next_node=n7)
n2 = ListNode(data=2, next_node=n5)
L1 = ListNode(data='HEAD', next_node=n2) # always start with a dummy node
n11 = ListNode(data=11)
n3 = ListNode(data=3, next_node=n11)
L2 = ListNode(data='HEAD', next_node=n3)
print("L1 -> {}".format(L1))
print("L2 -> {}".format(L2))
print("merged -> {}".format(merge_lists(L1, L2)))
print("-----")
n7 = ListNode(data=7)
n5 = ListNode(data=5, next_node=n7)
