def part_two(data):
buses_by_offset = {}
for i, bus in enumerate(data[1]):
if bus != "x":
buses_by_offset[i] = int(bus)
time = -1
solved = False
step = 1
buses_matched = set()
while not solved:
solved = True
time += step
num_buses_matched = 0
for offset, bus in buses_by_offset.items():
if (time + offset) % bus == 0:
num_buses_matched += 1
if num_buses_matched > len(buses_matched):
buses_matched.add(bus)
# Full disclosure: I saw a spoiler on Reddit about Chinese Remainder
# Theorem that pointed me in this general direction :(
step = lcm.reduce(list(buses_matched), dtype=int64)
continue
else:
solved = False
break
return time
def main():
data = getInts('input')
planets = list()
i = 0
for planet in data:
a = {}
a['pos'] = dict(zip(['x','y','z'], planet ))
a['vel'] = {'x':0, 'y':0, 'z':0}
a['id'] = i
planets.append( a )
i+= 1
pairs = list(combinations(range(len(planets)), 2))
planets2 = planets.copy()
# part 1
simulation(planets, pairs, 1000)
p1 = sum([ getEnergy(x) for x in planets ])
print("p1: {}".format(p1))
# part 2
p2_s = simulation(planets2, pairs, 9999999999, True)
p2 = lcm.reduce([x for x in p2_s.values()])
print("p2: {}".format(p2))
def find_cycle(self):
cycles = [None, None, None]
self.steps = 0
memory = [self.state(0), self.state(1), self.state(2)]
while not all(cycles):
self.next_step()
for k in range(3):
state = self.state(k)
if not cycles[k] and state == memory[k]:
cycles[k] = self.steps
return lcm.reduce(cycles)
def prize_time(buses):
time = 1
interval = 1
for i in range(len(buses)):
bus_ids_to_check = [bus_id for bus_id, _ in buses[:i + 1]]
while True:
if deltas_correct(time, buses[:i + 1]):
break
time += interval
interval = int(lcm.reduce(bus_ids_to_check, dtype=int64))
return time
def get_action_order(action):
"""
calculate the order of a move given as a list of permutations
inputs:
-------
action - (list) of lists of ints - a move given as a list of cycles
returns:
--------
(int) - the order of the given move
"""
cycle_lengths = [len(cycle) for cycle in action]
return lcm.reduce(cycle_lengths)
def loop_finder(positions):
return_times = []
for dimension in range(3):
jupiter = SolarSystem1D(positions, dimension)
steps = 0
states = dict()
states[jupiter.get_states()] = steps
while True:
steps += 1
jupiter.apply_gravity()
jupiter.apply_velocity()
new_state = jupiter.get_states()
if new_state in states:
out = steps - states[new_state]
break
else:
states[new_state] = steps
return_times.append(out)
return lcm.reduce(return_times)
# pad
arg = arg + bytes([16 - len(arg) % 16] * (16 - len(arg) % 16))
n, m = 256, 48
binv = [None] * m
for i in range(m):
binv[b[i]] = i
b = binv[:]
assert None not in b
cycles = []
for pos, val in enumerate(arg):
seen = set()
count = 0
while (pos, val) not in seen:
seen.add((pos, val))
val = a[val]
pos = b[pos]
count += 1
cycles.append(count)
rep = int(lcm.reduce(cycles))
X = b'\xbe\xf5@\xddk"\x80cTH\x87iT\x0b\xa4\x15\x8fp\x8f\x14\x9b\xd1$d\x98\xac\x92\'\x13\x80\xdf[}SH\x9f\xac'
Y = int.to_bytes(
pow(
rep, 65537,
127314748520905380391777855525586135065716774604121015664758778084648831235208544136462397
), len(X), 'big')
print(''.join((chr(x ^ y) for x, y in zip(X, Y))))
def get_common_denominator(probabilities):
"""Return least Z such that each probability is a multiple of 1/Z."""
denominators = [p.denominator for p in probabilities]
return lcm.reduce(denominators)
moons[moon2] = update_velocity(moons[moon2], moon2_changes)
# now we've calculate the velocities, change the new positions
new_moons = dict()
for moon in moons.keys():
new_moons[add(moon, moons[moon])] = moons[moon]
return new_moons
x_states = set()
y_states = set()
z_states = set()
while True:
x_pos = tuple(i[0] for i in moons.keys())
y_pos = tuple(i[1] for i in moons.keys())
z_pos = tuple(i[2] for i in moons.keys())
x_vel = tuple(i[0] for i in moons.values())
y_vel = tuple(i[1] for i in moons.values())
z_vel = tuple(i[2] for i in moons.values())
x_state = (x_pos, x_vel)
y_state = (y_pos, y_vel)
z_state = (z_pos, z_vel)
if x_state in x_states and y_state in y_states and z_state in z_states:
break
x_states.add(x_state)
y_states.add(y_state)
z_states.add(z_state)
moons = advance_time(moons)
print(lcm.reduce([len(x_states), len(y_states), len(z_states)]))
return hash(state)
step = 0
axis_to_check = {0, 1, 2}
axis_found = set()
states_by_axis = [set(), set(), set()]
periods = []
while True:
# debug output
if step % 100000 == 0:
print(f'{datetime.datetime.now().time()}: After {step} steps')
if not axis_to_check:
result = lcm.reduce(periods)
print(
f'Planets will return where they started after {result} steps')
break
for axis_i in axis_to_check:
current_hash = axis_hash(positions, velocities, axis_i)
if current_hash in states_by_axis[axis_i]:
print(f'Repeat found for {axis_i} after {step} states')
axis_found.add(axis_i)
periods.append(step)
else:
states_by_axis[axis_i].add(current_hash)
axis_to_check -= axis_found
def part2(path):
pos = read_positions(path)
x, y, z = positions_to_pv_coord_pairs(pos)
steps = [steps_until_repeat(pv) for pv in (x, y, z)]
return lcm.reduce(steps)
def partB():
def periods_set(x, y, z):
return (x > 0) and (y > 0) and (z > 0)
moons = [
Moon([14, 15, -2], 'Io'),
Moon([17, -3, 4], 'Europa'),
Moon([6, 12, -13], 'Ganymede'),
Moon([-2, 10, -8], 'Callisto')
]
#moons = [Moon([-8,-10,0],'Io'),Moon([5,5,10],'Europa'),Moon([2,-7,3],'Ganymede'),Moon([9,-8,-3],'Callisto')]
pairs = list(combinations(moons, 2))
x_visited = []
y_visited = []
z_visited = []
x_steps = 0
y_steps = 0
z_steps = 0
while not (periods_set(x_steps, y_steps, z_steps)):
## apply gravity
for (m1, m2) in pairs:
for i, (p1, p2) in enumerate(zip(m1.position, m2.position)):
if p1 < p2:
m1.velocity[i] = m1.velocity[i] + 1
m2.velocity[i] = m2.velocity[i] - 1
elif p1 > p2:
m1.velocity[i] = m1.velocity[i] - 1
m2.velocity[i] = m2.velocity[i] + 1
xpos_vel = []
ypos_vel = []
zpos_vel = []
for m in moons:
m.step()
xpos_vel.append([m.position[0], m.velocity[0]])
ypos_vel.append([m.position[1], m.velocity[1]])
zpos_vel.append([m.position[2], m.velocity[2]])
if xpos_vel in x_visited and x_steps == 0:
print('X STEPS: ', (m.steps - 1))
x_steps = m.steps - 1
if ypos_vel in y_visited and y_steps == 0:
print('Y STEPS: ', (m.steps - 1))
y_steps = m.steps - 1
if zpos_vel in z_visited and z_steps == 0:
print('Z STEPS: ', (m.steps - 1))
z_steps = m.steps - 1
x_visited.append(xpos_vel)
y_visited.append(ypos_vel)
z_visited.append(zpos_vel)
if m.steps % 10000 == 0:
print(m.steps)
#loopsin = []
#for m in moons:
# print(m.periods)
# m_period = lcm.reduce(m.periods)
# loopsin.append(m_period)
#print(loopsin)
print(lcm.reduce([x_steps, y_steps, z_steps]))
if b == 0:
return t0
return (a + 1) * bus_id, bus_id
next_arrivals = [next_arrival(timestamp0, bus_id) for bus_id in bus_ids]
t_arrive, bus_id = min(next_arrivals, key=lambda x: x[0])
print((t_arrive - timestamp0) * bus_id)
# Part 2
from numpy import lcm
with open('p13.txt') as f:
timestamp0 = int(f.readline())
schedule = [(i, int(x)) for i, x in enumerate(f.readline().split(','))
if x != 'x']
N = len(schedule)
t0 = 100000000000000
dt = schedule[0][1]
t = t0 // dt * dt
while True:
ids = [bus_id for phi, bus_id in schedule if (t + phi) % bus_id == 0]
if len(ids) == N:
print(t)
break
t += lcm.reduce(ids)
nvel[j] += 1
# update positions
npos = [pos[i] + nvel[i] for i in range(nmoons)]
return npos, nvel
def key(pos, vel):
return '{},{},{};{},{},{}'.format(*pos, *vel)
periods = []
for dim in [0, 1, 2]:
counter = 0
pos = [positions[i][dim] for i in range(nmoons)]
vel = [0] * nmoons
initkey = key(pos, vel)
#vis = {initkey: 0}
while True:
pos, vel = one_step(pos, vel)
counter += 1
k = key(pos, vel)
if k == initkey:
#if k in vis:
periods += [(counter, pos, vel)]
break
#vis[k] = counter
print(periods)
period = lcm.reduce([p[0] for p in periods])
print(period)
# 2520 is the smallest number that can be divided by each of the numbers from 1 to 10 without any remainder.
# What is the smallest positive number that is evenly divisible by all of the numbers from 1 to 20?
from functools import reduce
from numpy import lcm
smallest_multiple = lcm.reduce(range(2, 21))
print(f"Smallest multiple: {smallest_multiple}")
def create_solution(self):
return [gcd.reduce(self.nums), lcm.reduce(self.nums)]
