def test_arg_and_kwargs():
args = "arg1_value", "arg2_value", 3
assert m.args_function(*args) == args
args = "a1", "a2"
kwargs = dict(arg3="a3", arg4=4)
assert m.args_kwargs_function(*args, **kwargs) == (args, kwargs)
def test_arg_and_kwargs():
args = 'arg1_value', 'arg2_value', 3
assert m.args_function(*args) == args
args = 'a1', 'a2'
kwargs = dict(arg3='a3', arg4=4)
assert m.args_kwargs_function(*args, **kwargs) == (args, kwargs)
def test_arg_and_kwargs():
args = 'arg1_value', 'arg2_value', 3
assert m.args_function(*args) == args
args = 'a1', 'a2'
kwargs = dict(arg3='a3', arg4=4)
assert m.args_kwargs_function(*args, **kwargs) == (args, kwargs)
def test_args_refcount():
"""Issue/PR #1216 - py::args elements get double-inc_ref()ed when combined with regular
arguments"""
refcount = m.arg_refcount_h
myval = 54321
expected = refcount(myval)
assert m.arg_refcount_h(myval) == expected
assert m.arg_refcount_o(myval) == expected + 1
assert m.arg_refcount_h(myval) == expected
assert refcount(myval) == expected
assert m.mixed_plus_args(1, 2.0, "a", myval) == (1, 2.0, ("a", myval))
assert refcount(myval) == expected
assert m.mixed_plus_kwargs(3, 4.0, a=1, b=myval) == (3, 4.0, {
"a": 1,
"b": myval
})
assert refcount(myval) == expected
assert m.args_function(-1, myval) == (-1, myval)
assert refcount(myval) == expected
assert m.mixed_plus_args_kwargs(5, 6.0, myval, a=myval) == (
5,
6.0,
(myval, ),
{
"a": myval
},
)
assert refcount(myval) == expected
assert m.args_kwargs_function(7, 8, myval, a=1, b=myval) == (
(7, 8, myval),
{
"a": 1,
"b": myval
},
)
assert refcount(myval) == expected
exp3 = refcount(myval, myval, myval)
assert m.args_refcount(myval, myval, myval) == (exp3, exp3, exp3)
assert refcount(myval) == expected
# This function takes the first arg as a `py::object` and the rest as a `py::args`. Unlike the
# previous case, when we have both positional and `py::args` we need to construct a new tuple
# for the `py::args`; in the previous case, we could simply inc_ref and pass on Python's input
# tuple without having to inc_ref the individual elements, but here we can't, hence the extra
# refs.
assert m.mixed_args_refcount(myval, myval,
myval) == (exp3 + 3, exp3 + 3, exp3 + 3)
assert m.class_default_argument() == "<class 'decimal.Decimal'>"
def test_args_refcount():
"""Issue/PR #1216 - py::args elements get double-inc_ref()ed when combined with regular
arguments"""
refcount = m.arg_refcount_h
myval = 54321
expected = refcount(myval)
assert m.arg_refcount_h(myval) == expected
assert m.arg_refcount_o(myval) == expected + 1
assert m.arg_refcount_h(myval) == expected
assert refcount(myval) == expected
assert m.mixed_plus_args(1, 2.0, "a", myval) == (1, 2.0, ("a", myval))
assert refcount(myval) == expected
assert m.mixed_plus_kwargs(3, 4.0, a=1, b=myval) == (3, 4.0, {"a": 1, "b": myval})
assert refcount(myval) == expected
assert m.args_function(-1, myval) == (-1, myval)
assert refcount(myval) == expected
assert m.mixed_plus_args_kwargs(5, 6.0, myval, a=myval) == (5, 6.0, (myval,), {"a": myval})
assert refcount(myval) == expected
assert m.args_kwargs_function(7, 8, myval, a=1, b=myval) == \
((7, 8, myval), {"a": 1, "b": myval})
assert refcount(myval) == expected
exp3 = refcount(myval, myval, myval)
assert m.args_refcount(myval, myval, myval) == (exp3, exp3, exp3)
assert refcount(myval) == expected
# This function takes the first arg as a `py::object` and the rest as a `py::args`. Unlike the
# previous case, when we have both positional and `py::args` we need to construct a new tuple
# for the `py::args`; in the previous case, we could simply inc_ref and pass on Python's input
# tuple without having to inc_ref the individual elements, but here we can't, hence the extra
# refs.
assert m.mixed_args_refcount(myval, myval, myval) == (exp3 + 3, exp3 + 3, exp3 + 3)
