Python EXPRONE.satisfy_oneの例

コード例 #1

ファイル: test_expr.py プロジェクト: JeffBiggers/pyeda

def test_satisfy():
    # Typical cases
    f = a & ~b & c & ~d
    assert EXPRZERO.satisfy_one() is None
    assert EXPRONE.satisfy_one() == {}
    assert f.satisfy_one() == {a: 1, b: 0, c: 1, d: 0}

    # PLE solution
    f = (a | b | c) & (~a | ~b | c)
    assert f.satisfy_one() == {a: 0, b: 0, c: 1}

    points = [p for p in Xor(a, b, c).satisfy_all()]
    assert points == [
        {a: 0, b: 0, c: 1},
        {a: 0, b: 1, c: 0},
        {a: 1, b: 0, c: 0},
        {a: 1, b: 1, c: 1},
    ]
    assert Xor(a, b, c).satisfy_count() == 4

    # Assumptions
    f = OneHot(a, b, c)
    g = Xor(a, b, c)
    with a, ~b:
        assert f.satisfy_one() == {a: 1, b: 0, c: 0}
        assert g.satisfy_one() == {a: 1, b: 0, c: 0}
    with a & ~b:
        assert f.satisfy_one() == {a: 1, b: 0, c: 0}
        assert g.satisfy_one() == {a: 1, b: 0, c: 0}

コード例 #2

ファイル: test_expr.py プロジェクト: e42s/pyeda

def test_satisfy():
    # Typical cases
    f = a & ~b & c & ~d
    assert EXPRZERO.satisfy_one() is None
    assert EXPRONE.satisfy_one() == {}
    assert f.satisfy_one() == {a: 1, b: 0, c: 1, d: 0}

    # PLE solution
    f = (a | b | c) & (~a | ~b | c)
    assert f.satisfy_one() == {a: 0, b: 0, c: 1}

    points = [p for p in Xor(a, b, c).satisfy_all()]
    assert points == [
        {
            a: 0,
            b: 0,
            c: 1
        },
        {
            a: 0,
            b: 1,
            c: 0
        },
        {
            a: 1,
            b: 0,
            c: 0
        },
        {
            a: 1,
            b: 1,
            c: 1
        },
    ]
    assert Xor(a, b, c).satisfy_count() == 4

    # Assumptions
    f = OneHot(a, b, c)
    g = Xor(a, b, c)
    with a, ~b:
        assert f.satisfy_one() == {a: 1, b: 0, c: 0}
        assert g.satisfy_one() == {a: 1, b: 0, c: 0}
    with a & ~b:
        assert f.satisfy_one() == {a: 1, b: 0, c: 0}
        assert g.satisfy_one() == {a: 1, b: 0, c: 0}

コード例 #3

ファイル: test_expr.py プロジェクト: uservidya/pyeda

def test_satisfy():
    # Typical cases
    f = a * -b * c * -d
    assert EXPRZERO.satisfy_one() is None
    assert EXPRONE.satisfy_one() == {}
    assert f.satisfy_one() == {a: 1, b: 0, c: 1, d: 0}
    assert f.satisfy_one() == {a: 1, b: 0, c: 1, d: 0}

    # PLE solution
    f = (a + b + c) * (-a + -b + c)
    assert f.satisfy_one() == {a: 0, b: 0, c: 1}

    points = [p for p in Xor(a, b, c).satisfy_all()]
    assert points == [
        {a: 0, b: 0, c: 1},
        {a: 0, b: 1, c: 0},
        {a: 1, b: 0, c: 0},
        {a: 1, b: 1, c: 1},
    ]
    assert Xor(a, b, c).satisfy_count() == 4