コード例 #1
0
    def subn(self, repl, string, count=0):
        """Return the tuple (new_string, number_of_subs_made) found by replacing
        the leftmost non-overlapping occurrences of pattern with the replacement
        repl."""
        filter = repl
        if not callable(repl) and "\\" in repl:
            # handle non-literal strings ; hand it over to the template compiler
            import re
            filter = re._subx(self, repl)
        state = _sre._State(string, 0, sys.maxint, self.flags)
        sublist = []

        need_unicode = (isinstance(string, unicode)
                        or isinstance(repl, unicode))
        n = last_pos = 0
        while not count or n < count:
            state.reset()
            if not _sre._search(state, self._code):
                break
            if last_pos < state.start:
                sublist.append(string[last_pos:state.start])
            if not (last_pos == state.start
                    and last_pos == state.string_position and n > 0):
                # the above ignores empty matches on latest position
                if callable(filter):
                    to_app = filter(SRE_Match(self, state))
                else:
                    to_app = filter
                if isinstance(to_app, unicode):
                    need_unicode = True
                sublist.append(to_app)
                last_pos = state.string_position
                n += 1
            if state.string_position == state.start:
                state.start += 1
            else:
                state.start = state.string_position

        if last_pos < state.end:
            sublist.append(string[last_pos:state.end])

        if n == 0:
            # not just an optimization -- see test_sub_unicode
            return string, n

        if need_unicode:
            item = u"".join(sublist)
        else:
            item = "".join(sublist)
        return item, n
コード例 #2
0
ファイル: app_sre.py プロジェクト: alkorzt/pypy
    def subn(self, repl, string, count=0):
        """Return the tuple (new_string, number_of_subs_made) found by replacing
        the leftmost non-overlapping occurrences of pattern with the replacement
        repl."""
        filter = repl
        if not callable(repl) and "\\" in repl:
            # handle non-literal strings ; hand it over to the template compiler
            import re
            filter = re._subx(self, repl)
        state = _sre._State(string, 0, sys.maxint, self.flags)
        sublist = []

        need_unicode = (isinstance(string, unicode) or
                        isinstance(repl, unicode))
        n = last_pos = 0
        while not count or n < count:
            state.reset()
            if not _sre._search(state, self._code):
                break
            if last_pos < state.start:
                sublist.append(string[last_pos:state.start])
            if not (last_pos == state.start and
                                last_pos == state.string_position and n > 0):
                # the above ignores empty matches on latest position
                if callable(filter):
                    to_app = filter(SRE_Match(self, state))
                else:
                    to_app = filter
                if isinstance(to_app, unicode):
                    need_unicode = True
                sublist.append(to_app)
                last_pos = state.string_position
                n += 1
            if state.string_position == state.start:
                state.start += 1
            else:
                state.start = state.string_position

        if last_pos < state.end:
            sublist.append(string[last_pos:state.end])

        if n == 0:
            # not just an optimization -- see test_sub_unicode
            return string, n

        if need_unicode:
            item = u"".join(sublist)
        else:
            item = "".join(sublist)
        return item, n
コード例 #3
0
    def subn(self, repl, string, count=0):
        "NOT_RPYTHON"
        filter = repl
        if not callable(repl) and "\\" in repl:
            # handle non-literal strings; hand it over to the template compiler
            filter = re._subx(self, repl)
        start = 0
        sublist = []
        force_unicode = (isinstance(string, unicode)
                         or isinstance(repl, unicode))
        n = last_pos = 0
        while not count or n < count:
            match = rsre_core.search(self._code,
                                     string,
                                     start,
                                     flags=self.flags)
            if match is None:
                break
            if last_pos < match.match_start:
                sublist.append(string[last_pos:match.match_start])
            if not (last_pos == match.match_start == match.match_end
                    and n > 0):
                # the above ignores empty matches on latest position
                if callable(filter):
                    piece = filter(self._make_match(match))
                else:
                    piece = filter
                sublist.append(piece)
                last_pos = match.match_end
                n += 1
            elif last_pos >= len(string):
                break  # empty match at the end: finished
            #
            start = match.match_end
            if start == match.match_start:
                start += 1

        if last_pos < len(string):
            sublist.append(string[last_pos:])

        if n == 0:
            # not just an optimization -- see test_sub_unicode
            return string, n

        if force_unicode:
            item = u"".join(sublist)
        else:
            item = "".join(sublist)
        return item, n
コード例 #4
0
ファイル: rsre_re.py プロジェクト: Darriall/pypy
    def subn(self, repl, string, count=0):
        "NOT_RPYTHON"
        filter = repl
        if not callable(repl) and "\\" in repl:
            # handle non-literal strings; hand it over to the template compiler
            filter = re._subx(self, repl)
        start = 0
        sublist = []
        force_unicode = (isinstance(string, unicode) or
                         isinstance(repl, unicode))
        n = last_pos = 0
        while not count or n < count:
            match = rsre_core.search(self._code, string, start,
                                     flags=self.flags)
            if match is None:
                break
            if last_pos < match.match_start:
                sublist.append(string[last_pos:match.match_start])
            if not (last_pos == match.match_start
                             == match.match_end and n > 0):
                # the above ignores empty matches on latest position
                if callable(filter):
                    piece = filter(self._make_match(match))
                else:
                    piece = filter
                sublist.append(piece)
                last_pos = match.match_end
                n += 1
            elif last_pos >= len(string):
                break     # empty match at the end: finished
            #
            start = match.match_end
            if start == match.match_start:
                start += 1

        if last_pos < len(string):
            sublist.append(string[last_pos:])

        if n == 0:
            # not just an optimization -- see test_sub_unicode
            return string, n

        if force_unicode:
            item = u"".join(sublist)
        else:
            item = "".join(sublist)
        return item, n
コード例 #5
0
ファイル: _sre.py プロジェクト: hartsock/graalpython
    def subn(self, repl, string, count=0):
        self.__check_input_type(string)
        n = 0
        pattern = self.__tregex_compile(self.pattern)
        result = []
        pos = 0
        literal = False
        if not callable(repl):
            self.__check_input_type(repl)
            if isinstance(repl, str):
                literal = '\\' not in repl
            else:
                literal = b'\\' not in repl
            if not literal:
                import re
                repl = re._subx(self, repl)
                if not callable(repl):
                    literal = True

        while (count == 0 or n < count) and pos <= len(string):
            match_result = tregex_call_exec(pattern.exec, string, pos)
            if not match_result.isMatch:
                break
            n += 1
            start = match_result.getStart(0)
            end = match_result.getEnd(0)
            result.append(string[pos:start])
            if literal:
                result.append(repl)
            else:
                _srematch = Match(self, pos, -1, match_result, string, pattern)
                _repl = repl(_srematch)
                result.append(_repl)
            pos = end
            if start == end:
                if pos < len(string):
                    result.append(string[pos])
                pos = pos + 1
        result.append(string[pos:])
        if self.__binary:
            return b"".join(result), n
        else:
            return "".join(result), n
コード例 #6
0
ファイル: _sre.py プロジェクト: yjstyle/RustPython
    def _subx(self, template, string, count=0, subn=False):
        filter = template
        if not callable(template) and "\\" in template:
            # handle non-literal strings ; hand it over to the template compiler
            import re
            filter = re._subx(self, template)
        state = _State(string, 0, sys.maxsize, self.flags)
        sublist = []

        n = last_pos = 0
        while not count or n < count:
            state.reset()
            state.string_position = state.start
            if not state.search(self._code):
                break
            if last_pos < state.start:
                sublist.append(string[last_pos:state.start])
            if not (last_pos == state.start
                    and last_pos == state.string_position and n > 0):
                # the above ignores empty matches on latest position
                if callable(filter):
                    sublist.extend(filter(SRE_Match(self, state)))
                else:
                    sublist.append(filter)
                last_pos = state.string_position
                n += 1
            if state.string_position == state.start:
                state.start += 1
            else:
                state.start = state.string_position

        if last_pos < state.end:
            sublist.append(string[last_pos:state.end])
        item = "".join(sublist)
        if subn:
            return item, n
        else:
            return item
コード例 #7
0
ファイル: nodes.py プロジェクト: xxoolm/Ryven
 def update_event(self, inp=-1):
     self.set_output_val(0, re._subx(self.input(0), self.input(1)))