print(latex(a)) basisA18=[[0]] basisA18.append(a) ############################################################### ############################################################### ###########A17 ############################################################### ############################################################### a=[0,0,0,0,0,00,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,00,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,00,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,00,0,0,0,0,0,0,0,0,0,0] orderList = order(7) basisA17=[[0]] #We make the basis from basis of A18 a[0]=diagA1(basisA18[1],1,2) a[1]=removeA1(basisA18[1],1) basisA17.append(a[0]) basisA17.append(a[1]) a[0]=expand("[(2,0,0,0,0,0,0)/(0,2,0,0,0,0,0)^2/(0,0,2,0,0,0,0)/(0,0,0,2,0,0,0)/(0,0,0,0,2,0,0)/(0,0,0,0,0,2,0)/(0,0,0,0,0,0,2)/(1,2,1,0,0,0,0)/(1,0,1,0,0,0,0)/(1,1,0,1,1,0,0)/(1,1,0,0,0,1,1)/(1,1,0,1,0,0,1)/$(1,1,0,0,1,1,0)/(1,0,1,1,0,1,0)/(1,0,1,0,1,0,1)/(0,1,1,1,1,0,0)/(0,1,1,0,0,1,1)/(0,0,0,1,1,1,1)/(0,2,0,1,0,0,1)/(0,0,0,1,0,0,1)/(0,2,0,0,1,1,0)/(0,0,0,0,1,1,0)/(0,1,1,1,0,1,0)/(0,1,1,0,1,0,1)]") print("First one in notes corresponds to 1rst one from A18?") print(checker(a[0], basisA17,orderList )) a[1]=expand("[(2,0,0,0,0,0,0,0)/(0,2,0,0,0,0,0,0)/(0,0,2,0,0,0,0,0)/(0,0,0,2,0,0,0,0)/(0,0,0,0,2,0,0,0)/(0,0,0,0,0,2,0,0)/(0,0,0,0,0,0,2,0)/(0,0,0,0,0,0,0,2)/(1,1,1,1,0,0,0,0)/(1,1,0,0,1,1,0,0)/(1,1,0,0,0,0,1,1)/(1,0,1,0,1,0,0,1)/(1,0,1,0,0,1,1,0)/(1,0,0,1,1,0,1,0)/(1,0,0,1,0,1,0,1)/(0,0,1,1,1,1,0,0)/(0,0,1,1,0,0,1,1)/(0,0,0,0,1,1,1,1)/(0,1,1,0,1,0,0,1)/(0,1,1,0,0,1,1,0)/(0,1,0,1,1,0,1,0)/(0,1,0,1,0,1,0,1)]") print(" second that was wrong in notes corresponds to 1rst one from A18?") print(checker(a[0], basisA17,orderList )) a[2]=expand("[ (2,0,0,0,0,0,0)/(0,2,0,0,0,0,0)/(0,0,2,0,0,0,0)/(0,0,0,2,0,0,0)/(0,0,0,0,2,0,0)/(0,0,0,0,0,2,0)/(0,0,0,0,0,0,2)/(1,1,1,0,0,0,0)^2/(1,0,0,1,1,0,0)^2/(1,0,0,0,0,1,1)^2/(1,1,0,1,0,0,1)/(1,1,0,0,1,1,0)/(1,0,1,1,0,1,0)/(1,0,1,0,1,0,1)/(0,1,1,1,1,0,0)/(0,1,1,0,0,1,1)/(0,0,0,1,1,1,1)/(0,1,0,1,0,0,1)^2/(0,1,0,0,1,1,0)^2/(1,0,1,1,0,1,0)/(1,0,1,0,1,0,1)/(0,0,0,0,0,0,0)^3]")
lie=lie+[(0,6,0),(0,0,2),(0,2,0), (0,3,1)] lie=lie+[(1,3,0),(1,4,1)] a1=diagA1(lie,1,3) #print("CASE 12") #print(checker(a1,basisA12,orderList2)) #print(latex(a1)) #Case 13 and 14 print("cases 13 and 14") a=expand("[(0,4,2)/(0,2,4)/(2,0,0)^2/(2,2,2)/(0,2,0)/(0,0,2)]") b=expand("[(0,0,4)/(0,2,2)^2/(0,2,0)/(0,0,2)^3/(0,0,0)/(2,2,0)/(2,0,2)^2/(2,0,0)^2]") print(latex(removeA1(a,1))) print(classifyIncomplete(removeA1(a,1), basisA12,orderList2)) print(latex(removeA1(b,1))) print(classifyIncomplete(removeA1(b,1), basisA12,orderList2)) a=expand("[(0,10)/(4,6)/(2,0)/(0,2)/(0,0)/(0,0)]/(0,0)") print(latex(a)) print(classifyIncomplete(a, basisA12,orderList2)) #Is case (1,22/00^3) in A1D6 somewhere?? a=expand("[(0, 4)^4/(0, 0)^6/(0, 6)/(0, 2)/(2, 3)^4/(0, 3)^4/(2, 0)^6/(2, 4)]") print("HERE")
print("A18") basisA18=[[0]] basisA18.append(a) ############################################################### ############################################################### ###########A17 ############################################################### ############################################################### a=[0,0,0,0,0,00,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,00,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,00,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,00,0,0,0,0,0,0,0,0,0,0] orderList = order(7) basisA17=[[0]] #We make the basis from basis of A18 a[0]=removeA1(basisA18[1],2) a[1]=removeA1(basisA18[1],3) a[2]=diagA1(basisA18[1],2,3) a[3]=diagA1(basisA18[1],3,4) a[4]=diagA1(basisA18[1],3,5) a[5]=diagA1(basisA18[1],1,2) basisA17.append(a[0]) basisA17.append(a[1]) basisA17.append(a[2]) basisA17.append(a[3]) basisA17.append(a[4]) basisA17.append(a[5]) for i in range(1,1): print(i)