コード例 #1
0
	def _linearUndo(self, target):
		mapview = self.editor.getActiveMapView()
		if mapview is None:
			return
			
		undomanager = mapview.getController().getUndoManager()
		current_item = undomanager.current_item
		
		# Redo?
		item = current_item
		count = 0
		while item is not None:
			if item == target:
				undomanager.redo(count)
				break
			count += 1
			item = item.next
			
		else: 
			# Undo?
			count = 0
			item = current_item
			while item is not None:
				if item == target:
					undomanager.undo(count)
					break
				count += 1
				item = item.previous
				
			else:
				print "HistoryManager: Didn't find target item!"
		
		# Select the current item, important to see if the undo/redo didn't work as expected
		self.update()
コード例 #2
0
ファイル: HistoryManager.py プロジェクト: LilMouse/fifengine
	def _linearUndo(self, target):
		mapview = self.editor.getActiveMapView()
		if mapview is None:
			return
			
		undomanager = mapview.getController().getUndoManager()
		current_item = undomanager.current_item
		
		# Redo?
		item = current_item
		count = 0
		while item is not None:
			if item == target:
				undomanager.redo(count)
				break
			count += 1
			item = item.next
			
		else: 
			# Undo?
			count = 0
			item = current_item
			while item is not None:
				if item == target:
					undomanager.undo(count)
					break
				count += 1
				item = item.previous
				
			else:
				print "HistoryManager: Didn't find target item!"
		
		# Select the current item, important to see if the undo/redo didn't work as expected
		self.update()
コード例 #3
0
	def _itemSelected(self):
		mapview = self.editor.getActiveMapView()
		if mapview is None:
			return
			
		undomanager = mapview.getController().getUndoManager()
		
		stackitem = self.list.selected_item.item
		if stackitem == undomanager.current_item:
			return
		
		if undomanager.getBranchMode() is False:
			self._linearUndo(stackitem)
			return
		
		searchlist = []
		searchlist2 = []
		parent = stackitem
		branch = parent.next
		while parent is not None:
			if parent is undomanager.first_item or len(parent._branches) > 1:
				searchlist.append( (parent, branch) )
			branch = parent
			parent = parent.parent
		
		current_item = undomanager.current_item
		
		parent = current_item
		branch = parent.next
		while parent is not None:
			if parent is undomanager.first_item or len(parent._branches) > 1:
				searchlist2.append( (parent, branch) )
			branch = parent
			parent = parent.parent
			
		searchlist.reverse()
		searchlist2.reverse()
		
		# Remove duplicate entries, except the last duplicate, so we don't undo
		# more items than necessary
		sl = len(searchlist);
		if len(searchlist2) < sl:
			sl = len(searchlist2)
		for s in range(sl):
			if searchlist[s][0] != searchlist[s][0]:
				searchlist = searchlist[s-1:]
		
		s_item = searchlist[0][0]

		# Undo until we reach the first shared parent
		i = 0
		item = current_item
		while item is not None:
			if item == s_item:
				undomanager.undo(i)
				current_item = item
				break
			i += 1
			item = item.previous
		else:
			print "Nada (undo)"
			return
				
		# Switch branches
		for s_item in searchlist:
			 if s_item[0].setBranch(s_item[1]) is False:
				print "Warning: HistoryManager: Switching branch failed for: ", s_item
			 
		# Redo to stackitem
		item = current_item
		i = 0
		while item is not None:
			if item == stackitem:
				undomanager.redo(i)
				break
			i += 1
			item = item.next
		else:
			print "Nada (redo)"
		
		# Select the current item, important to see if the undo/redo didn't work as expected
		self.update()
コード例 #4
0
ファイル: HistoryManager.py プロジェクト: LilMouse/fifengine
	def _itemSelected(self):
		mapview = self.editor.getActiveMapView()
		if mapview is None:
			return
			
		undomanager = mapview.getController().getUndoManager()
		
		stackitem = self.list.selected_item.item
		if stackitem == undomanager.current_item:
			return
		
		if undomanager.getBranchMode() is False:
			self._linearUndo(stackitem)
			return
		
		searchlist = []
		searchlist2 = []
		parent = stackitem
		branch = parent.next
		while parent is not None:
			if parent is undomanager.first_item or len(parent._branches) > 1:
				searchlist.append( (parent, branch) )
			branch = parent
			parent = parent.parent
		
		current_item = undomanager.current_item
		
		parent = current_item
		branch = parent.next
		while parent is not None:
			if parent is undomanager.first_item or len(parent._branches) > 1:
				searchlist2.append( (parent, branch) )
			branch = parent
			parent = parent.parent
			
		searchlist.reverse()
		searchlist2.reverse()
		
		# Remove duplicate entries, except the last duplicate, so we don't undo
		# more items than necessary
		sl = len(searchlist);
		if len(searchlist2) < sl:
			sl = len(searchlist2)
		for s in range(sl):
			if searchlist[s][0] != searchlist[s][0]:
				searchlist = searchlist[s-1:]
		
		s_item = searchlist[0][0]

		# Undo until we reach the first shared parent
		i = 0
		item = current_item
		while item is not None:
			if item == s_item:
				undomanager.undo(i)
				current_item = item
				break
			i += 1
			item = item.previous
		else:
			print "Nada (undo)"
			return
				
		# Switch branches
		for s_item in searchlist:
			 if s_item[0].setBranch(s_item[1]) is False:
				print "Warning: HistoryManager: Switching branch failed for: ", s_item
			 
		# Redo to stackitem
		item = current_item
		i = 0
		while item is not None:
			if item == stackitem:
				undomanager.redo(i)
				break
			i += 1
			item = item.next
		else:
			print "Nada (redo)"
		
		# Select the current item, important to see if the undo/redo didn't work as expected
		self.update()