Python QUOTED_LITERAL_REの例

コード例 #1

def resolve_column(col):
    """
    Resolve a public schema name to the discover dataset.
    unknown columns are converted into tags expressions.
    """
    if col is None:
        return col
    if col.startswith("tags[") or QUOTED_LITERAL_RE.match(col):
        return col
    return DISCOVER_COLUMN_MAP.get(col, u"tags[{}]".format(col))

コード例 #2

ファイル: discover.py プロジェクト: MasterMann/sentry

def resolve_column(col):
    """
    Resolve a public schema name to the discover dataset.
    unknown columns are converted into tags expressions.
    """
    if col is None:
        return col
    # Whilst project_id is not part of the public schema we convert
    # the project.name field into project_id way before we get here.
    if col == "project_id":
        return col
    if col.startswith("tags[") or QUOTED_LITERAL_RE.match(col):
        return col
    return DISCOVER_COLUMN_MAP.get(col, u"tags[{}]".format(col))