コード例 #1
0
    def inverse_anscombe(x):
        """Compute the inverse transform

        This uses an approximation of the exact  unbiased inverse.
        Reference: Makitalo, M., & Foi, A. (2011). A closed-form
        approximation of the exact unbiased inverse of the Anscombe
        variance-stabilizing transformation. Image Processing.
        """
        # should be positive
        # should wotk for dataframe and numpy arrays
        return (1.0 / 4.0 * np.power(x, 2) +
                1.0 / 4.0 * np.sqrt(3.0 / 2.0) * np.power(x, -1.0) -
                11.0 / 8.0 * np.power(x, -2.0) +
                5.0 / 8.0 * np.sqrt(3.0 / 2.0) * np.power(x, -3.0) - 1.0 / 8.0)
コード例 #2
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ファイル: misc.py プロジェクト: sequana/sequana
def normpdf(x, mu, sigma):
    """Return the normal pdf evaluated at *x*; args provides *mu*, *sigma*"

    .. note:: same as scipy.stats.norm but implemented to avoid scipy dependency
    """

    return 1. / (np.sqrt(2 * np.pi) * sigma) * np.exp(-0.5 * (1. / sigma *
                                                              (x - mu))**2)
コード例 #3
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    def generalized_anscombe(x, mu, sigma, gain=1.0):
        """Compute the generalized anscombe variance stabilizing transform

        Data should be a mixture of poisson and gaussian noise.

        The input signal  z  is assumed to follow the Poisson-Gaussian noise
        model::
    
            x = gain * p + n

        where gain is the camera gain and mu and sigma are the read noise
        mean and standard deviation. X should contain only positive values.  
        Negative values are ignored. Biased for low counts
        """
        try:
            # If a dataframe, we do not want to change it
            y = gain * x + (gain**2) * 3.0 / 8.0 + sigma**2 - gain * mu
            return (2.0 / gain) * np.sqrt(np.maximum(y, 0.0))
        except:
            x = np.array(x)
            y = gain * x + (gain**2) * 3.0 / 8.0 + sigma**2 - gain * mu
            return (2.0 / gain) * np.sqrt(np.maximum(y, 0.0))
コード例 #4
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    def anscombe(x):
        r"""Compute the anscombe variance stabilizing transform.

        :param x: noisy Poisson-distributed data
        :return: data with variance approximately equal to 1.

        Reference: Anscombe, F. J. (1948), "The transformation of Poisson,
            binomial and negative-binomial data", Biometrika 35 (3-4): 246-254

        For Poisson distribution, the mean and variance are not independent. The
        anscombe transform aims at transforming the data so that the variance
        is about 1 for large enough mean; For mean zero, the varaince is still
        zero. So, it transform Poisson data to approximately Gaussian data with
        mean :math:`\sqrt{x+3/8} - 1/(4m^{1/2})`
        """

        #if np.mean(x) <4:
        #    logger.warning("Mean of input data below 4")
        try:
            # If a dataframe, we do not want to change it
            return 2.0 * np.sqrt(x + 3.0 / 8.0)
        except:
            return 2.0 * np.sqrt(np.array(x) + 3.0 / 8.0)
コード例 #5
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ファイル: bedtools.py プロジェクト: ranjit58/sequana
 def get_var_coef(self):
     return np.sqrt(self.df["cov"].var()) / self.get_mean_cov()