Python MinHash.count_commonの例

コード例 #1

def test_diff_seed(track_abundance):
    E1 = MinHash(n=5, ksize=20, track_abundance=track_abundance, seed=1)
    E2 = MinHash(n=5, ksize=20, track_abundance=track_abundance, seed=2)

    for i in [1, 2, 3, 4, 5]:
        E1.add_hash(i)
    for i in [1, 2, 3, 4, 6]:
        E2.add_hash(i)

    with pytest.raises(ValueError):
        E1.count_common(E2)

コード例 #2

ファイル: test_jaccard.py プロジェクト: dib-lab/sourmash

def test_diff_seed(track_abundance):
    E1 = MinHash(n=5, ksize=20, track_abundance=track_abundance, seed=1)
    E2 = MinHash(n=5, ksize=20, track_abundance=track_abundance, seed=2)

    for i in [1, 2, 3, 4, 5]:
        E1.add_hash(i)
    for i in [1, 2, 3, 4, 6]:
        E2.add_hash(i)

    with pytest.raises(ValueError):
        E1.count_common(E2)

コード例 #3

def test_common_1(track_abundance):
    E1 = MinHash(n=5, ksize=20, track_abundance=track_abundance)
    E2 = MinHash(n=5, ksize=20, track_abundance=track_abundance)

    for i in [1, 2, 3, 4, 5]:
        E1.add_hash(i)
    for i in [1, 2, 3, 4, 6]:
        E2.add_hash(i)

    assert E1.count_common(E2) == 4
    assert E2.count_common(E1) == 4

コード例 #4

ファイル: test_jaccard.py プロジェクト: dib-lab/sourmash

def test_common_1(track_abundance):
    E1 = MinHash(n=5, ksize=20, track_abundance=track_abundance)
    E2 = MinHash(n=5, ksize=20, track_abundance=track_abundance)

    for i in [1, 2, 3, 4, 5]:
        E1.add_hash(i)
    for i in [1, 2, 3, 4, 6]:
        E2.add_hash(i)

    assert E1.count_common(E2) == 4
    assert E2.count_common(E1) == 4