Python I.diffの例

コード例 #1

ファイル: test_diff.py プロジェクト: hridog00/Proyecto

def test_diff():
    x, y = symbols('x, y')
    assert Rational(1, 3).diff(x) is S.Zero
    assert I.diff(x) is S.Zero
    assert pi.diff(x) is S.Zero
    assert x.diff(x, 0) == x
    assert (x**2).diff(x, 2, x) == 0
    assert (x**2).diff(x, y, 0) == 2 * x
    assert (x**2).diff(x, y) == 0
    raises(ValueError, lambda: x.diff(1, x))

    a = Symbol("a")
    b = Symbol("b")
    c = Symbol("c")
    p = Rational(5)
    e = a * b + b**p
    assert e.diff(a) == b
    assert e.diff(b) == a + 5 * b**4
    assert e.diff(b).diff(a) == Rational(1)
    e = a * (b + c)
    assert e.diff(a) == b + c
    assert e.diff(b) == a
    assert e.diff(b).diff(a) == Rational(1)
    e = c**p
    assert e.diff(c, 6) == Rational(0)
    assert e.diff(c, 5) == Rational(120)
    e = c**Rational(2)
    assert e.diff(c) == 2 * c
    e = a * b * c
    assert e.diff(c) == a * b

コード例 #2

ファイル: test_diff.py プロジェクト: jenshnielsen/sympy

def test_diff():
    x, y = symbols('x, y')
    assert Rational(1, 3).diff(x) is S.Zero
    assert I.diff(x) is S.Zero
    assert pi.diff(x) is S.Zero
    assert x.diff(x, 0) == x
    assert (x**2).diff(x, 2, x) == 0
    assert (x**2).diff(x, y, 0) == 2*x
    assert (x**2).diff(x, y) == 0
    raises(ValueError, lambda: x.diff(1, x))

    a = Symbol("a")
    b = Symbol("b")
    c = Symbol("c")
    p = Rational(5)
    e = a*b + b**p
    assert e.diff(a) == b
    assert e.diff(b) == a + 5*b**4
    assert e.diff(b).diff(a) == Rational(1)
    e = a*(b + c)
    assert e.diff(a) == b + c
    assert e.diff(b) == a
    assert e.diff(b).diff(a) == Rational(1)
    e = c**p
    assert e.diff(c, 6) == Rational(0)
    assert e.diff(c, 5) == Rational(120)
    e = c**Rational(2)
    assert e.diff(c) == 2*c
    e = a*b*c
    assert e.diff(c) == a*b