Python SeqPer.coeffの例

コード例 #1

ファイル: test_sequences.py プロジェクト: msgoff/sympy

def test_SeqPer():
    s = SeqPer((1, n, 3), (x, 0, 5))

    assert isinstance(s, SeqPer)
    assert s.periodical == Tuple(1, n, 3)
    assert s.period == 3
    assert s.coeff(3) == 1
    assert s.free_symbols == {n}

    assert list(s) == [1, n, 3, 1, n, 3]
    assert s[:] == [1, n, 3, 1, n, 3]
    assert SeqPer((1, n, 3), (x, -oo, 0))[0:6] == [1, n, 3, 1, n, 3]

    raises(ValueError, lambda: SeqPer((1, 2, 3), (0, 1, 2)))
    raises(ValueError, lambda: SeqPer((1, 2, 3), (x, -oo, oo)))
    raises(ValueError, lambda: SeqPer(n**2, (0, oo)))

    assert SeqPer((n, n**2, n**3), (m, 0, oo))[:6] == [
        n,
        n**2,
        n**3,
        n,
        n**2,
        n**3,
    ]
    assert SeqPer((n, n**2, n**3), (n, 0, oo))[:6] == [0, 1, 8, 3, 16, 125]
    assert SeqPer((n, m), (n, 0, oo))[:6] == [0, m, 2, m, 4, m]

コード例 #2

ファイル: test_sequences.py プロジェクト: abloomston/sympy

def test_SeqPer():
    s = SeqPer((1, n, 3), (x, 0, 5))

    assert isinstance(s, SeqPer)
    assert s.periodical == Tuple(1, n, 3)
    assert s.period == 3
    assert s.coeff(3) == 1
    assert s.free_symbols == set([n])

    assert list(s) == [1, n, 3, 1, n, 3]
    assert s[:] == [1, n, 3, 1, n, 3]
    assert SeqPer((1, n, 3), (-oo, 0))[0:6] == [1, n, 3, 1, n, 3]

    raises(ValueError, lambda: SeqPer((1, 2, 3), (0, 1, 2)))
    raises(ValueError, lambda: SeqPer((1, 2, 3), (x, -oo, oo)))
    raises(ValueError, lambda: SeqPer(n**2, (0, oo)))

コード例 #3

ファイル: test_sequences.py プロジェクト: vinothtronics/sympy

def test_SeqPer():
    s = SeqPer((1, n, 3), (x, 0, 5))

    assert isinstance(s, SeqPer)
    assert s.periodical == Tuple(1, n, 3)
    assert s.period == 3
    assert s.coeff(3) == 1
    assert s.free_symbols == set([n])

    assert list(s) == [1, n, 3, 1, n, 3]
    assert s[:] == [1, n, 3, 1, n, 3]
    assert SeqPer((1, n, 3), (-oo, 0))[0:6] == [1, n, 3, 1, n, 3]

    raises(ValueError, lambda: SeqPer((1, 2, 3), (0, 1, 2)))
    raises(ValueError, lambda: SeqPer((1, 2, 3), (x, -oo, oo)))
    raises(ValueError, lambda: SeqPer(n**2, (0, oo)))

コード例 #4

ファイル: test_sequences.py プロジェクト: AStorus/sympy

def test_SeqPer():
    s = SeqPer((1, n, 3), (x, 0, 5))

    assert isinstance(s, SeqPer)
    assert s.periodical == Tuple(1, n, 3)
    assert s.period == 3
    assert s.coeff(3) == 1
    assert s.free_symbols == {n}

    assert list(s) == [1, n, 3, 1, n, 3]
    assert s[:] == [1, n, 3, 1, n, 3]
    assert SeqPer((1, n, 3), (x, -oo, 0))[0:6] == [1, n, 3, 1, n, 3]

    raises(ValueError, lambda: SeqPer((1, 2, 3), (0, 1, 2)))
    raises(ValueError, lambda: SeqPer((1, 2, 3), (x, -oo, oo)))
    raises(ValueError, lambda: SeqPer(n**2, (0, oo)))

    assert SeqPer((n, n**2, n**3), (m, 0, oo))[:6] == \
        [n, n**2, n**3, n, n**2, n**3]
    assert SeqPer((n, n**2, n**3), (n, 0, oo))[:6] == [0, 1, 8, 3, 16, 125]
    assert SeqPer((n, m), (n, 0, oo))[:6] == [0, m, 2, m, 4, m]

コード例 #5

ファイル: sequences_test.py プロジェクト: zidanewenqsh/my_api_01

# SeqFormula(n**2, (n, 0, 5))
b = sequence((1, 2, 3, 4), (n, 0, 4))
# SeqPer((1, 2, 3), (n, 0, 5))
print(b)

print(a.coeff(3))  # 在自变量取特定值时的值
print(a[:])
print(b[:])
print(b.periodical)  # 周期序列
print(b.period)  # 周期序列长度

k = sympy.symbols('k')
c = SeqPer((k, k**2, k**3), (k, 0, oo))
print(c.periodical)
print(c[0:10])
print(c.coeff(4))

d = SeqFormula(n**3, (n, -oo, 0))  # 不能写0，-oo
print(d[0:6])

print(SeqAdd(SeqPer((1, 2), (n, 0, oo)), S.EmptySequence))
# SeqPer((1, 2), (n, 0, oo))
print(SeqAdd(SeqPer((1, 2), (n, 0, 5)), SeqPer((1, 2), (n, 6, 10))))
# EmptySequence()
print(SeqAdd(SeqPer((1, 2), (n, 0, oo)), SeqFormula(n**2, (n, 0, oo))))
# SeqAdd(SeqFormula(n**2, (n, 0, oo)), SeqPer((1, 2), (n, 0, oo)))
print(SeqAdd(SeqFormula(n**3), SeqFormula(n**2)))
# SeqFormula(n**3 + n**2, (n, 0, oo))

e = SeqAdd(SeqPer((1, 2), (n, 0, oo)), SeqFormula(n**2, (n, 0, oo)))
print(e[0:6])