コード例 #1
0
 def test_while_is_not(self):
     it = iter(string.ascii_lowercase)
     self.assertEqual(['a'], list(iter_utils.while_is_not(it, 'a')))
     it = iter(string.ascii_lowercase)
     self.assertEqual(['a', 'b'], list(iter_utils.while_is_not(it, 'b')))
     self.assertEqual(list(string.ascii_lowercase[2:]),
                      list(iter_utils.while_is_not(it, 'zzz')))
     it = iter(string.ascii_lowercase)
     self.assertEqual(list(string.ascii_lowercase),
                      list(iter_utils.while_is_not(it, '')))
コード例 #2
0
 def test_while_is_not(self):
     it = iter(string.ascii_lowercase)
     self.assertEqual(['a'],
                      list(iter_utils.while_is_not(it, 'a')))
     it = iter(string.ascii_lowercase)
     self.assertEqual(['a', 'b'],
                      list(iter_utils.while_is_not(it, 'b')))
     self.assertEqual(list(string.ascii_lowercase[2:]),
                      list(iter_utils.while_is_not(it, 'zzz')))
     it = iter(string.ascii_lowercase)
     self.assertEqual(list(string.ascii_lowercase),
                      list(iter_utils.while_is_not(it, '')))
コード例 #3
0
    def pformat(self,
                stringify_node=None,
                linesep=LINE_SEP,
                vertical_conn=VERTICAL_CONN,
                horizontal_conn=HORIZONTAL_CONN,
                empty_space=EMPTY_SPACE_SEP,
                starting_prefix=STARTING_PREFIX):
        """Formats this node + children into a nice string representation.

        **Example**::

            >>> from taskflow.types import tree
            >>> yahoo = tree.Node("CEO")
            >>> yahoo.add(tree.Node("Infra"))
            >>> yahoo[0].add(tree.Node("Boss"))
            >>> yahoo[0][0].add(tree.Node("Me"))
            >>> yahoo.add(tree.Node("Mobile"))
            >>> yahoo.add(tree.Node("Mail"))
            >>> print(yahoo.pformat())
            CEO
            |__Infra
            |  |__Boss
            |     |__Me
            |__Mobile
            |__Mail
        """
        if stringify_node is None:
            # Default to making a unicode string out of the nodes item...
            stringify_node = lambda node: six.text_type(node.item)
        expected_lines = self.child_count(only_direct=False) + 1
        buff = six.StringIO()
        conn = vertical_conn + horizontal_conn
        stop_at_parent = self
        for i, node in enumerate(self.dfs_iter(include_self=True), 1):
            prefix = []
            connected_to_parent = False
            last_node = node
            # Walk through *most* of this nodes parents, and form the expected
            # prefix that each parent should require, repeat this until we
            # hit the root node (self) and use that as our nodes prefix
            # string...
            parent_node_it = iter_utils.while_is_not(
                node.path_iter(include_self=True), stop_at_parent)
            for j, parent_node in enumerate(parent_node_it):
                if parent_node is stop_at_parent:
                    if j > 0:
                        if not connected_to_parent:
                            prefix.append(conn)
                            connected_to_parent = True
                        else:
                            # If the node was connected already then it must
                            # have had more than one parent, so we want to put
                            # the right final starting prefix on (which may be
                            # a empty space or another vertical connector)...
                            last_node = self._children[-1]
                            m = last_node.find_first_match(lambda n: n is node,
                                                           include_self=False,
                                                           only_direct=False)
                            if m is not None:
                                prefix.append(empty_space)
                            else:
                                prefix.append(vertical_conn)
                elif parent_node is node:
                    # Skip ourself... (we only include ourself so that
                    # we can use the 'j' variable to determine if the only
                    # node requested is ourself in the first place); used
                    # in the first conditional here...
                    pass
                else:
                    if not connected_to_parent:
                        prefix.append(conn)
                        spaces = len(horizontal_conn)
                        connected_to_parent = True
                    else:
                        # If we have already been connected to our parent
                        # then determine if this current node is the last
                        # node of its parent (and in that case just put
                        # on more spaces), otherwise put a vertical connector
                        # on and less spaces...
                        if parent_node[-1] is not last_node:
                            prefix.append(vertical_conn)
                            spaces = len(horizontal_conn)
                        else:
                            spaces = len(conn)
                    prefix.append(empty_space * spaces)
                last_node = parent_node
            prefix.append(starting_prefix)
            for prefix_piece in reversed(prefix):
                buff.write(prefix_piece)
            buff.write(stringify_node(node))
            if i != expected_lines:
                buff.write(linesep)
        return buff.getvalue()
コード例 #4
0
ファイル: tree.py プロジェクト: FedericoCeratto/taskflow
    def pformat(
        self,
        stringify_node=None,
        linesep=LINE_SEP,
        vertical_conn=VERTICAL_CONN,
        horizontal_conn=HORIZONTAL_CONN,
        empty_space=EMPTY_SPACE_SEP,
        starting_prefix=STARTING_PREFIX,
    ):
        """Formats this node + children into a nice string representation.

        **Example**::

            >>> from taskflow.types import tree
            >>> yahoo = tree.Node("CEO")
            >>> yahoo.add(tree.Node("Infra"))
            >>> yahoo[0].add(tree.Node("Boss"))
            >>> yahoo[0][0].add(tree.Node("Me"))
            >>> yahoo.add(tree.Node("Mobile"))
            >>> yahoo.add(tree.Node("Mail"))
            >>> print(yahoo.pformat())
            CEO
            |__Infra
            |  |__Boss
            |     |__Me
            |__Mobile
            |__Mail
        """
        if stringify_node is None:
            # Default to making a unicode string out of the nodes item...
            stringify_node = lambda node: six.text_type(node.item)
        expected_lines = self.child_count(only_direct=False) + 1
        buff = six.StringIO()
        conn = vertical_conn + horizontal_conn
        stop_at_parent = self
        for i, node in enumerate(self.dfs_iter(include_self=True), 1):
            prefix = []
            connected_to_parent = False
            last_node = node
            # Walk through *most* of this nodes parents, and form the expected
            # prefix that each parent should require, repeat this until we
            # hit the root node (self) and use that as our nodes prefix
            # string...
            parent_node_it = iter_utils.while_is_not(node.path_iter(include_self=True), stop_at_parent)
            for j, parent_node in enumerate(parent_node_it):
                if parent_node is stop_at_parent:
                    if j > 0:
                        if not connected_to_parent:
                            prefix.append(conn)
                            connected_to_parent = True
                        else:
                            # If the node was connected already then it must
                            # have had more than one parent, so we want to put
                            # the right final starting prefix on (which may be
                            # a empty space or another vertical connector)...
                            last_node = self._children[-1]
                            m = last_node.find_first_match(lambda n: n is node, include_self=False, only_direct=False)
                            if m is not None:
                                prefix.append(empty_space)
                            else:
                                prefix.append(vertical_conn)
                elif parent_node is node:
                    # Skip ourself... (we only include ourself so that
                    # we can use the 'j' variable to determine if the only
                    # node requested is ourself in the first place); used
                    # in the first conditional here...
                    pass
                else:
                    if not connected_to_parent:
                        prefix.append(conn)
                        spaces = len(horizontal_conn)
                        connected_to_parent = True
                    else:
                        # If we have already been connected to our parent
                        # then determine if this current node is the last
                        # node of its parent (and in that case just put
                        # on more spaces), otherwise put a vertical connector
                        # on and less spaces...
                        if parent_node[-1] is not last_node:
                            prefix.append(vertical_conn)
                            spaces = len(horizontal_conn)
                        else:
                            spaces = len(conn)
                    prefix.append(empty_space * spaces)
                last_node = parent_node
            prefix.append(starting_prefix)
            for prefix_piece in reversed(prefix):
                buff.write(prefix_piece)
            buff.write(stringify_node(node))
            if i != expected_lines:
                buff.write(linesep)
        return buff.getvalue()