コード例 #1
0
def interpolate_multidim_fixed_derivatives(
        support, sign_pattern, kernel, support_derivatives,
        return_coeffs=False):
    assert support.shape[0] == sign_pattern.shape[0]
    assert np.all(
        np.absolute(
            np.sum(np.absolute(sign_pattern) ** 2, axis=1) - 1.0) < 1e-10)
    assert support_derivatives.shape == sign_pattern.shape

    n = support.shape[0]
    m = sign_pattern.shape[1]

    time_deltas = np.outer(support, np.ones(n)) - np.outer(np.ones(n), support)

    kernel_1 = kernel.derivative()
    kernel_2 = kernel_1.derivative()

    kernel_values = kernel(time_deltas)
    kernel_1_values = kernel_1(time_deltas)
    kernel_2_values = kernel_2(time_deltas)

    multiplier = 100.0
    problem_mx = np.bmat([
        [kernel_values, kernel_1_values / multiplier],
        [kernel_1_values / multiplier, kernel_2_values / multiplier / multiplier]]).real

    coeffss = []
    for k in range(m):
        problem_obj = np.hstack(
            [sign_pattern[:, k], support_derivatives[:, k] / multiplier])
        coeffss.append(np.linalg.lstsq(problem_mx, problem_obj)[0])

    return MultiTrigPoly([
        kernel.sum_shifts(-support, coeffs[:n]) +
        kernel_1.sum_shifts(-support, coeffs[n:] / multiplier)
        for coeffs in coeffss])

    problem_mx, problem_obj = (
        _interpolator_linear_constraints_with_derivatives(
            support, sign_pattern, kernel, support_derivatives))

    coeffs = np.linalg.solve(problem_mx, problem_obj)

    kernel_coeffs = [
        coeffs[4*k*n:(4*k+1)*n] + coeffs[(4*k+2)*n:(4*k+3)*n] * 1j
        for k in range(m)]
    kernel_derivative_coeffs = [
        coeffs[(4*k+1)*n:(4*k+2)*n] + coeffs[(4*k+3)*n:(4*k+4)*n] * 1j
        for k in range(m)]

    if return_coeffs:
        return kernel_coeffs, kernel_derivative_coeffs
    else:
        return MultiTrigPoly([
            kernel.sum_shifts(-support, kernel_coeffs[k]) +
            kernel.derivative().sum_shifts(
                -support, kernel_derivative_coeffs[k])
            for k in range(m)])
コード例 #2
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def interpolate_direct(support, sign_pattern, kernel):
    """Toy interpolation model multiplying kernel copies by sign pattern."""
    m = sign_pattern.shape[1]
    return MultiTrigPoly([
        sum((kernel.shift(-t) * sign
             for t, sign in zip(support, sign_pattern[:, i])), TrigPoly.zero())
        for i in range(m)
    ])
コード例 #3
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def interpolate_multidim_only_kernel_l2_min(support,
                                            sign_pattern,
                                            kernel,
                                            return_coeffs=False):
    """Interpolation fixing derivatives at interpolated points in tangent
    plane of sphere, and minimizing L2 norm of the polynomial subject to this
    constraint.
    """
    assert support.shape[0] == sign_pattern.shape[0]
    assert np.all(
        np.absolute(np.sum(np.absolute(sign_pattern)**2, axis=1) -
                    1.0) < 1e-10)

    n = support.shape[0]
    m = sign_pattern.shape[1]

    problem_mx, problem_obj = _interpolator_linear_constraints_kernel_only(
        support, sign_pattern, kernel)

    print problem_mx.shape

    #
    # Build objective quadratic form
    #

    # S is block-diagonal, with k blocks of size 4n x 4n each of which is the
    # same as the objective quadratic form from the one-sample case.
    S_diag_block = kernel.inners_of_shifts(support)
    S = np.kron(np.identity(2 * m), S_diag_block)

    # This multiplier value is heuristically chosen.
    multiplier = (kernel.derivative().squared_norm() / kernel.squared_norm() *
                  1e6)
    coeffs = _optimize_quadratic_form(S,
                                      problem_mx,
                                      problem_obj,
                                      multiplier=multiplier)

    print coeffs

    kernel_coeffs = [
        coeffs[2 * k * n:2 * (k + 1) * n] +
        coeffs[(k + 2) * n:(2 * k + 3) * n] * 1j for k in range(m)
    ]
    kernel_derivative_coeffs = [
        coeffs[(4 * k + 1) * n:(4 * k + 2) * n] +
        coeffs[(4 * k + 3) * n:(4 * k + 4) * n] * 1j for k in range(m)
    ]

    if return_coeffs:
        return kernel_coeffs, kernel_derivative_coeffs
    else:
        return MultiTrigPoly([
            kernel.sum_shifts(-support, kernel_coeffs[k]) +
            kernel.derivative().sum_shifts(
                -support, kernel_derivative_coeffs[k]) for k in range(m)
        ])
コード例 #4
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def interpolate_multidim_0Grad(support, sign_pattern, kernel):
    assert support.shape[0] == sign_pattern.shape[0]
    assert np.all(
        np.absolute(
            np.sum(np.absolute(sign_pattern) ** 2, axis=1) - 1.0) < 1e-10)

    n = support.shape[0]
    m = sign_pattern.shape[1]

    kernel1 = kernel.derivative()
    kernel2 = kernel1.derivative()

    time_deltas = np.outer(support, np.ones(n)) - np.outer(np.ones(n), support)
    kernel_values = kernel(time_deltas)
    kernel1_values = kernel1(time_deltas)
    kernel2_values = kernel2(time_deltas)
    problem_mx = np.bmat([
        [kernel_values, kernel1_values],
        [kernel1_values, kernel2_values]])

    coeffss = []
    for k in range(m):
        single_sign_pattern = sign_pattern[:, k]
        problem_obj = np.hstack(
            [single_sign_pattern, np.zeros(single_sign_pattern.shape[0])])
        coeffss.append(np.linalg.solve(problem_mx, problem_obj))

    return MultiTrigPoly([
        (TrigPoly(
            kernel.freqs,
            sum(kernel.coeffs * np.exp(2.0 * np.pi * 1j * kernel.freqs * -t) * c
                for c, t in zip(coeffs[:n], support))) +
         TrigPoly(
             kernel1.freqs,
             sum(kernel1.coeffs * np.exp(2.0 * np.pi * 1j * kernel1.freqs * -t) * c
                 for c, t in zip(coeffs[n:], support))))
        for coeffs in coeffss])

    return MultiTrigPoly([
        sum([kernel.shift(-t) * c for c, t in zip(coeffs[:n], support)],
            TrigPoly.zero()) +
        sum([kernel1.shift(-t) * c for c, t in zip(coeffs[n:], support)],
            TrigPoly.zero())
        for coeffs in coeffss])
コード例 #5
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def interpolate_multidim_only_kernel(support, sign_pattern, kernel):
    """Interpolate only using kernels, no kernel derivatives or derivative
    constraints.
    """
    assert support.shape[0] == sign_pattern.shape[0]
    assert np.all(
        np.absolute(np.sum(np.absolute(sign_pattern)**2, axis=1) -
                    1.0) < 1e-10)

    n = support.shape[0]
    m = sign_pattern.shape[1]

    time_deltas = np.outer(support, np.ones(n)) - np.outer(np.ones(n), support)
    kernel_values = kernel(time_deltas)

    coeffss = []
    for k in range(m):
        single_sign_pattern = sign_pattern[:, k]
        coeffss.append(np.linalg.solve(kernel_values, single_sign_pattern))

    return MultiTrigPoly(
        [kernel.sum_shifts(-support, coeffs) for coeffs in coeffss])
コード例 #6
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def interpolate_multidim_adjacent_samples(
        support, sign_pattern, kernel):
    assert support.shape[0] == sign_pattern.shape[0]
    assert np.all(
        np.absolute(
            np.sum(np.absolute(sign_pattern) ** 2, axis=1) - 1.0) < 1e-10)

    n = support.shape[0]
    m = sign_pattern.shape[1]

    time_deltas = np.outer(support, np.ones(n)) - np.outer(np.ones(n), support)

    kernel_1 = kernel.derivative()
    kernel_2 = kernel_1.derivative()

    kernel_values = kernel(time_deltas)
    kernel_1_values = kernel_1(time_deltas)
    kernel_2_values = kernel_2(time_deltas)

    sign_pattern_real = np.real(sign_pattern)
    sign_pattern_imag = np.imag(sign_pattern)

    #
    # Build linear constraint data
    #

    zeros = np.zeros((n, n))
    problem_mx_rows = []
    problem_obj_cols = []

    rand_scale = 1.0 / np.sqrt(n)

    vj_p1_real = np.append(np.asarray([sign_pattern_real[i + 1,:] for i in range(n-1)]), np.zeros((1,m))).reshape((n,m))
    vj_m1_real = np.append(np.zeros((1,m)), np.asarray([sign_pattern_real[i ,:] for i in range(n-1)])).reshape((n,m))
    # vj_p1_real = np.random.normal(loc=0.0, scale=rand_scale, size=(n, m))
    # vj_m1_real = np.random.normal(loc=0.0, scale=rand_scale, size=(n, m))
    vj_coeffs_real = np.diagonal((vj_p1_real - vj_m1_real).dot(sign_pattern_real.T) )

    vj_p1_imag = np.append(np.asarray([sign_pattern_imag[i + 1,:] for i in range(n-1)]), np.zeros((1,m))).reshape((n,m))
    vj_m1_imag = np.append(np.zeros((1,m)), np.asarray([sign_pattern_imag[i ,:] for i in range(n-1)])).reshape((n,m))
    # vj_p1_imag = np.random.normal(loc=0.0, scale=rand_scale, size=(n, m))
    # vj_m1_imag = np.random.normal(loc=0.0, scale=rand_scale, size=(n, m))
    vj_coeffs_imag = np.diagonal((vj_p1_imag - vj_m1_imag).dot(sign_pattern_imag.T) )

    for k in range(m):
        # Row of real part constraint
        row1 = []
        for _ in range(4 * k):
            row1.append(zeros)
        row1.append(kernel_values)
        row1.append(kernel_1_values)
        row1.append(zeros)
        row1.append(zeros)
        for _ in range(4 * (m - 1 - k)):
            row1.append(zeros)
        problem_mx_rows.append(row1)

        # Row of imaginary part constraint
        row2 = []
        for _ in range(4 * k):
            row2.append(zeros)
        row2.append(zeros)
        row2.append(zeros)
        row2.append(kernel_values)
        row2.append(kernel_1_values)
        for _ in range(4 * (m - 1 - k)):
            row2.append(zeros)
        problem_mx_rows.append(row2)

        # Objective
        problem_obj_cols.append(sign_pattern_real[:, k])
        problem_obj_cols.append(sign_pattern_imag[:, k])

    for k in range(m):
        row1 = []
        for _ in range(4 * k):
            row1.append(zeros)
        row1.append(kernel_1_values)
        row1.append(kernel_2_values)
        row1.append(zeros)
        row1.append(zeros)
        for _ in range(4 * (m - 1 - k)):
            row1.append(zeros)
        problem_mx_rows.append(row1)

        # Row of imaginary part constraint
        row2 = []
        for _ in range(4 * k):
            row2.append(zeros)
        row2.append(zeros)
        row2.append(zeros)
        row2.append(kernel_1_values)
        row2.append(kernel_2_values)
        for _ in range(4 * (m - 1 - k)):
            row2.append(zeros)
        problem_mx_rows.append(row2)

        # Objective
        problem_obj_cols.append(
            (vj_p1_real[:, k] - vj_m1_real[:, k] -
             np.multiply(vj_coeffs_real, sign_pattern_real[:, k])) / 1000.0)
        problem_obj_cols.append(
            (vj_p1_imag[:, k] - vj_m1_imag[:, k] -
             np.multiply(vj_coeffs_imag, sign_pattern_imag[:, k])) / 1000.0)


    problem_mx = np.bmat(problem_mx_rows)
    problem_obj = np.hstack(problem_obj_cols)

    #
    # Solve
    #
    coeffs = np.linalg.solve(problem_mx, problem_obj)

    #Or L2 min
#     S_diag_block = _interpolator_norm_quadratic_form(kernel, support)
#     S = np.kron(np.identity(m), S_diag_block)

#     # This multiplier value is heuristically chosen.
#     multiplier = kernel_1.squared_norm() / kernel.squared_norm() * 1e3
#     coeffs = _optimize_quadratic_form(
#         S,
#         problem_mx,
#         problem_obj,
#         multiplier=multiplier)


    return MultiTrigPoly([
        (kernel.sum_shifts(-support, coeffs[4*k*n:(4*k+1)*n]) +
         kernel_1.sum_shifts(-support, coeffs[(4*k+1)*n:(4*k+2)*n]) +
         kernel.sum_shifts(-support, coeffs[(4*k+2)*n:(4*k+3)*n] * 1j) +
         kernel_1.sum_shifts(-support, coeffs[(4*k+3)*n:(4*k+4)*n] * 1j))
        for k in range(m)])