コード例 #1
0
ファイル: Sort List.py プロジェクト: chyt123/cosmos
 def sortList(self, head: ListNode) -> ListNode:
     if not head or not head.next:
         return head
     if not head.next.next:
         if head.val > head.next.val:
             nxt = head.next
             head.next.next = head
             head.next = None
             return nxt
         return head
     rtn = ListNode()
     rtn.next = head
     slow = fast = rtn
     while fast and fast.next:
         slow = slow.next
         fast = fast.next.next
     right = self.sortList(slow.next)
     slow.next = None
     left = self.sortList(head)
     rtn = tmp = ListNode()
     while left and right:
         if left.val <= right.val:
             tmp.next = left
             left = left.next
         else:
             tmp.next = right
             right = right.next
         tmp = tmp.next
     tmp.next = left if left else right
     return rtn.next
コード例 #2
0
    def reverseBetween(self, head: ListNode, left: int,
                       right: int) -> ListNode:
        if left == right:
            return head
        rtn = ListNode()
        rtn.next = head
        start = rtn
        cnt = 1
        while head and cnt != left:
            start = head
            head = head.next
            cnt += 1

        pre = None
        while head and cnt != right:
            nxt = head.next
            head.next = pre
            pre = head
            head = nxt
            cnt += 1

        if head:
            start.next.next = head.next
            head.next = pre
            start.next = head

        return rtn.next
コード例 #3
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 def swapPairs(self, head: ListNode) -> ListNode:
     cur = ListNode()
     rtn = cur
     while head and head.next:
         new_head = head.next.next
         cur.next = head.next
         head.next.next = head
         head.next = None
         cur = head
         head = new_head
     if head:
         cur.next = head
     return rtn.next
コード例 #4
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    def mergeTwoLists(self, l1: ListNode, l2: ListNode) -> ListNode:
        # if not l1 or not l2:
        #     return l1 if l1 else l2
        dummy = ListNode(0)
        rtn = dummy

        while l1 and l2:
            if l1.val <= l2.val:
                dummy.next = l1
                l1 = l1.next
            else:
                dummy.next = l2
                l2 = l2.next
            dummy = dummy.next
        dummy.next = l1 if l1 else l2
        return rtn.next
コード例 #5
0
 def mergeTwoListsRecursion(self, l1: ListNode, l2: ListNode) -> ListNode:
     """
     递归解法
     :param l1:
     :param l2:
     :return:
     """
     if l1 is None:
         return l2
     if l2 is None:
         return l1
     if l1.val <= l2.val:
         l1.next = self.mergeTwoLists(l1.next, l2)
         return l1
     else:
         l2.next = self.mergeTwoLists(l1, l2.next)
         return l2
コード例 #6
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 def deleteDuplicates(self, head: ListNode) -> ListNode:
     rtn = head
     while head:
         if head.next and head.val == head.next.val:
             nxt = head.next
             head.next = head.next.next
             del nxt
         else:
             head = head.next
     return rtn
コード例 #7
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 def reverseList(self, head: ListNode) -> ListNode:
     if not head:
         return head
     pre, cur = head, head.next
     head.next = None
     while cur:
         nxt = cur.next
         cur.next = pre
         cur, pre = nxt, cur
     return pre
コード例 #8
0
 def removeElements(self, head, val):
     """
     :type head: ListNode
     :type val: int
     :rtype: ListNode
     """
     phead = ListNode(0)
     phead.next = head
     p = phead
     while p:
         while p.next and p.next.val == val:
             p.next = p.next.next
         p = p.next
     return phead.next
コード例 #9
0
ファイル: Partition List.py プロジェクト: chyt123/cosmos
 def partition(self, head: ListNode, x: int) -> ListNode:
     s_pt = s_cur = ListNode()
     l_pt = l_cur = ListNode()
     while head:
         tmp = head.next
         if head.val < x:
             s_cur.next = head
             s_cur = s_cur.next
         else:
             l_cur.next = head
             l_cur = l_cur.next
         head.next = None
         head = tmp
     s_cur.next = l_pt.next
     return s_pt.next
コード例 #10
0
ファイル: solution.py プロジェクト: glcrazier/LeetCodePlay
 def swapPairs(self, head):
     vhead = ListNode(0)
     vhead.next = head
     left = vhead
     middle = head
     right = None
     while middle is not None:
         right = middle.next
         if right is None:
             break
         middle.next = right.next
         left.next = right
         right.next = middle
         left = middle
         middle = left.next
     return vhead.next
コード例 #11
0
 def deleteDuplicates(self, head: ListNode) -> ListNode:
     if not head:
         return None
     sp = ListNode()
     sp.next = head
     pt = head
     pre = sp
     while pt and pt.next:
         if pt.val == pt.next.val:
             while pt.next and pt.val == pt.next.val:
                 pt.next = pt.next.next
             pre.next = pt.next
             pt = pre.next
         else:
             pre = pt
             pt = pt.next
     return sp.next
コード例 #12
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    def reverseKGroup(self, head: ListNode, k: int) -> ListNode:
        dummy = ListNode(0)
        dummy.next = head

        pre = dummy
        end = dummy
        while end.next is not None:
            for i in range(k):
                end = end.next if end is not None else None
            if end is None:
                break
            start = pre.next
            next = end.next
            end.next = None
            pre.next = self.reverse(start)
            start.next = next
            pre, end = start, start
        return dummy.next
コード例 #13
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 def removeNthFromEnd(self, head: ListNode, n: int) -> ListNode:
     rtn = ListNode()
     rtn.next = head
     mem = [rtn]
     slow = fast = head
     scnt = fcnt = 0
     while fast and fast.next:
         mem.append(slow)
         slow = slow.next
         scnt += 1
         fast = fast.next.next
         fcnt += 2
     fcnt += 0 if not fast else 1
     idx = fcnt - n + 1
     while len(mem) < idx + 2 and slow:
         mem.append(slow)
         slow = slow.next
     if len(mem) < idx + 2:
         mem.append(None)
     mem[idx - 1].next = mem[idx + 1]
     return rtn.next
コード例 #14
0
ファイル: solution.py プロジェクト: glcrazier/LeetCodePlay
    def reverseKGroup(self, head, k):
        if k < 2:
            return head
        vhead = ListNode(0)
        vhead.next = head

        #search for next k nodes
        def hasNodes(nodeHead, numNodes):
            c = nodeHead.next
            while numNodes > 0:
                if c is None:
                    return False
                c = c.next
                numNodes = numNodes - 1
            return True

        def reverseNodes(nodeHead, numNodes):
            c0 = nodeHead
            c1 = c0.next
            c2 = c1.next
            c3 = c1
            n = numNodes - 1
            while n > 0:
                t = c2.next
                c2.next = c1
                c0.next = c2
                c1 = c2
                c2 = t
                n = n - 1
            c3.next = t
            return c3

        cur = vhead
        while hasNodes(cur, k) is True:
            cur = reverseNodes(cur, k)
        return vhead.next
コード例 #15
0
ファイル: reverse.py プロジェクト: jasonchuang/python_coding
from util import ListNode, printListNode

#class ListNode(object):
#    def __init__(self, x):
#        self.val = x
#        self.next = None
#
#def printListNode(head):
#    while (head):
#        print head.val
#        head = head.next

node11 = ListNode(2)
node12 = ListNode(4)
node13 = ListNode(6)
node11.next = node12
node12.next = node13
'''
1: pre, 2(p)->4->6
    1.1: 2(p)->4(tmp)->6
    1.2: None(pre)<-2(p)  4->6
    1.3: None<-2(prev/p)  4->6
    1.4: None<-2(pre)  4(p)->6

2: None<-2(prev) 4(p)->6
    2.1: None<-2(prev)  4(p)->6(tmp)
    2.2: None<-2(prev)<-4(p)  6(tmp)
    2.3: None<-2<-4(prev/p)  6
    2.4: None<-2<-4(prev)  6(p)
...
'''