def do(self, func):
'''todo'''
lns = (
( [2, 4, 3], [5, 6, 4], [7, 0, 8]),
( [0], [0], [0]),
( [1, 8], [0], [1, 8]),
( [5], [5], [0, 1]),
)
for l1, l2, l3 in lns:
l = func(utils.array2listnode(l1), utils.array2listnode(l2))
self.assertEqual(utils.listnode2array(l), l3)
def runAlgorithm(lists: List[int]):
return listnode2array(s.swapPairs(array2listnode(lists)))
def runAlgorithm(l1, l2):
# Convert list to a linked list before passing the params.
# After calling the solution function, re-convert the linked node value to a list value.
return listnode2array(
s.addTwoNumbers(array2listnode(l1), array2listnode(l2)))
def runAlgorithm(lists: List[int], k: int):
return listnode2array(s.reverseKGroup(array2listnode(lists), k))
def runAlgorithm(l1, l2):
return listnode2array(s.mergeTwoLists(array2listnode(l1), array2listnode(l2)))
def runAlgorithm(array, n):
# Convert list to a linked list before passing the params.
# After calling the solution function, re-convert the linked node value to a list value.
return listnode2array(s.removeNthFromEnd(array2listnode(array), n))
def runAlgorithm(lists: List[List[int]]):
return listnode2array(s.mergeKLists([array2listnode(l)
for l in lists]))