Python isSpecialURL 예제들

예제 #1

파일: base.py 프로젝트: tpingili/balrog

 def processSpecialForceHosts(self, url, specialForceHosts):
     if isSpecialURL(url, specialForceHosts):
         if '?' in url:
             url += '&force=1'
         else:
             url += '?force=1'
     return url

예제 #2

파일: base.py 프로젝트: catlee/balrog

 def processSpecialForceHosts(self, url, specialForceHosts, force_arg):
     if isSpecialURL(url, specialForceHosts):
         if '?' in url:
             url += '&force=' + force_arg.query_value
         else:
             url += '?force=' + force_arg.query_value
     return url

예제 #3

 def processSpecialForceHosts(self, url, specialForceHosts, force_arg):
     if isSpecialURL(url, specialForceHosts):
         if '?' in url:
             url += '&force=' + force_arg.query_value
         else:
             url += '?force=' + force_arg.query_value
     return url

예제 #4

파일: base.py 프로젝트: nthomas-mozilla/balrog

 def processSpecialForceHosts(self, url, specialForceHosts):
     if isSpecialURL(url, specialForceHosts):
         if "?" in url:
             url += "&force=1"
         else:
             url += "?force=1"
     return url

예제 #5

파일: base.py 프로젝트: aksareen/balrog

 def processSpecialForceHosts(self, url, specialForceHosts):
     if isSpecialURL(url, specialForceHosts):
         if '?' in url:
             url += '&force=1'
         else:
             url += '?force=1'
     return url

예제 #6

파일: base.py 프로젝트: mozbhearsum/balrog

 def processSpecialForceHosts(self, url, specialForceHosts, force_arg):
     if isSpecialURL(url, specialForceHosts):
         if "?" in url:
             url += "&force=" + force_arg.query_value
         else:
             url += "?force=" + force_arg.query_value
     return url

예제 #7

 def processSpecialForceHosts(self, url, specialForceHosts, force_arg):
     if isSpecialURL(url, specialForceHosts):
         if "?" in url:
             url += "&force=" + force_arg.query_value
         else:
             url += "?force=" + force_arg.query_value
     return url