print(item.__dict__)
# ---------------------------
# 变化
def condition01(emp):
return emp.money >= 15000
def condition02(emp):
return emp.did == 9005
# 通用
def find(func):
for emp in list_employee:
# if emp.did == 9005:
# if condition02(emp):
if func(emp):
yield emp
# 变化 + 通用
for item in find(condition02):
print(item.__dict__)
for item in find(condition01):
print(item.__dict__)
for item in IterableHelper.find_all(list_employee, condition01):
print(item.__dict__)
Employee(1003, 9002, "猪八戒", 20000),
Employee(1001, 9002, "师父", 60000),
Employee(1004, 9001, "沙僧", 30000),
Employee(1005, 9001, "小白龙", 15000),
]
# 需求：获取所员工的员工编号
for item in IterableHelper.select(list_employees, lambda item: item.eid):
print(item)
# 1. map映射：
for item in map(lambda item: item.eid, list_employees):
print(item)
# 需求：获取部门编号是9001的所有员工
for item in IterableHelper.find_all(list_employees,
lambda emp: emp.did == 9001):
print(item.__dict__)
# 2. filter过滤：
for item in filter(lambda emp: emp.did == 9001, list_employees):
print(item.__dict__)
max_value = IterableHelper.get_max(list_employees,
lambda element: element.money)
print(max_value.__dict__)
# 3.max 最大 min 最小
max_value = max(list_employees, key=lambda element: element.money)
print(max_value.__dict__)
# 4.
EmployeeModel(1003, 9003, "刘岳浩", 11000),
EmployeeModel(1004, 9007, "冯舜禹", 17000),
EmployeeModel(1005, 9005, "曹海欧", 15000),
EmployeeModel(1006, 9005, "魏鑫珑", 12000),
]
# def condition01(emp):
# return emp.money >= 15000
#
# def condition02(emp):
# return emp.did == 9005
# 通用
def find(func):
for emp in list_employee:
if func(emp):
yield emp
# 变化 + 通用
for item in find(lambda emp: emp.did == 9005):
print(item.__dict__)
for item in find(lambda emp: emp.money >= 15000):
print(item.__dict__)
for item in IterableHelper.find_all(list_employee,
lambda emp: emp.money >= 15000):
print(item.__dict__)
]
# def condition01(emp):
# return emp.money >= 15000
#
# def condition02(emp):
# return emp.did == 9005
# 通用
def find(func):
for emp in list_employee:
if func(emp):
yield emp
# 变化 + 通用
# for item in find_all(condition02):
# print(item.__dict__)
for item in IterableHelper.find_all(list_employee,
lambda item: item.money >= 15000):
print(item.__dict__)
# for item in find_all(condition01):
# print(item.__dict__)
print()
for item in IterableHelper.find_all(list_employee,
lambda item: item.did == 9005):
print(item.__dict__)
list_phones = [
Phone("华为1", 5999, "蓝色"),
Phone("华为2", 6999, "红色"),
Phone("苹果1", 9999, "金色"),
Phone("苹果2", 7999, "白色"),
Phone("三星2", 4999, "白色"),
]
# 将查找条件定义在函数中
# item.color == "白色"
# def condition01(item):
# return item.color == "白色"
# for item in IterableHelper.find_all(list_phones,condition01):
# 调用通用函数
for item in IterableHelper.find_all(list_phones, lambda item: item.color == "白色"):
print(item.__dict__)
# def condition02(item):
# return item.brand == "苹果2"
#
# result = IterableHelper.find_single(list_phones, condition02)
# print(result.__dict__)
result = IterableHelper.find_single(list_phones, lambda item: item.brand == "苹果2")
print(result.__dict__)
# find01()
def find02():
for item in list01:
if item % 3 == 0 or item % 5 == 0:
yield item
def cond01(num):
return num % 2 != 0
def cond02(num):
return num % 3 == 0 or num % 5 == 0
def find_all(func):
for item in list01:
if func(item):
yield item
for i in find_all(lambda a: a % 2 != 0):
print(i)
for i in find_all(lambda num: num % 3 == 0 or num % 5 == 0):
print(i)
IterableHelper.find_all(list01, lambda a: a % 2 != 0)
yield commodity
# for commodity in get_commodity_price_less_10000():
# print(commodity.__dict__)
# 变化的
def condition01(com):
return com.cid > 1004
def condition02(commodity):
return commodity.price < 10000
"""
# 不变的
def find_all(list_target, func):
for commodity in list_target:
# if commodity.price < 10000:
# if condition02(commodity):
if func(commodity):
yield commodity
# 连接的: 不变的(变化的)
for item in find_all(list_commodity_infos, condition01):
print(item.__dict__)
"""
for item in IterableHelper.find_all(list_commodity_infos, condition01):
print(item.__dict__)
"""
3. 使用IterableHelper完成下列功能
list01 = [3,43,4,56,6,76,87,9]
-- 在list01中找出所有大于10的数字
-- 在list01中找出第一个偶数
-- 在list01中找出最大的数字
-- 对list01进行升序排列
"""
from common.iterable_tools import IterableHelper
list01 = [3, 43, 4, 56, 6, 76, 87, 9]
for item in IterableHelper.find_all(list01, lambda number: number > 10):
print(item)
result = IterableHelper.find_single(list01, lambda number: number % 2 == 0)
print(result)
result = IterableHelper.get_max(list01, lambda number: number)
print(result)
IterableHelper.order_by(list01,lambda number: number)
print(list01)
print(number)
for number in find02():
print(number)
# －－－－－－－－－－－－－－－－－－
# 提取变化函数
def condition01(item):
return item > 10
def condition02(item):
return item % 2 == 0
# 提取通用函数 -- 万能查找
def find(func):# 创建了钩子
for item in list01:
# if item % 2 == 0:
# if condition02(item):
if func(item):# 拉起钩子(执行条件)
yield item
for number in find(condition02):# 向钩子上挂条件
print(number)
from common.iterable_tools import IterableHelper
for number in IterableHelper.find_all(list01, condition01):
print(number)
Commodity(1002, "倚天剑", 10000),
Commodity(1003, "金箍棒", 52100),
Commodity(1004, "口罩", 20),
Commodity(1005, "酒精", 30),
]
for item in map(lambda item: (item.name, item.price), list_commodity_infos):
print(item)
for item in IterableHelper.select(list_commodity_infos, lambda item:
(item.name, item.price)):
print(item)
for item in filter(lambda item: item.price < 10000, list_commodity_infos):
print(item.__dict__)
for item in IterableHelper.find_all(list_commodity_infos,
lambda item: item.price < 10000):
print(item)
new_list = sorted(list_commodity_infos,
key=lambda item: item.price,
reverse=True)
print(new_list)
tuple01 = ([1, 1], [2, 2, 2], [3, 3, 3])
print(max(tuple01, key=lambda item: len(item)))
print(IterableHelper.get_max(tuple01, lambda item: len(item)))
"""
"""
from common.iterable_tools import IterableHelper
def condition01(item):
return item % 2 == 0
def condition02(item):
return item > 10
def condition03(item):
return item < 50
list01 = [43, 4, 5, 56, 76, 78, 8]
# 查找所有偶数
# 惰性操作 - 节省内存
for item in IterableHelper.find_all(list01, condition01):
print(item)
# 立即操作 - 操作灵活
result = list(IterableHelper.find_all(list01, condition01))
print(result[0])
print(result[-1])
print(result[-3:])
def condition02(item):
return item.money < 10000
# 万能查找
# def find(func):
# for item in list_wifes:
# # if item.money < 10000:
# # if condition02(item):
# if func(item):
# yield item
# for item in find(condition02):
# print(item.__dict__)
for item in IterableHelper.find_all(list_wifes, condition01):
print(item.__dict__)
for item in IterableHelper.find_all(list_wifes,
lambda item: item.face_score > 90):
print(item.__dict__)
# 需求2：定义函数,在老婆列表中,查找姓名是苏荃的老婆对象
# 定义函数,在老婆列表中,查找颜值是100的老婆对象(如有多个返回第一个)
# def find01():
# for item in list_wifes:
# if item.name == "苏荃":
# return item
#
# def find02():
# for item in list_wifes:
self.name = name
self.atk_rate = atk_rate
self.cost_sp = cost_sp
self.duration = duration
list_skills = [
Skill("横扫千军", 1, 50, 5),
Skill("九阳神功", 3, 150, 6),
Skill("降龙十八掌", 3, 150, 5),
Skill("一阳指", 1.2, 0, 2),
Skill("乾坤大挪移", 3.2, 30, 2),
Skill("打狗棍", 1.3, 0, 6),
]
"""
-- 在技能列表中查找名称是"一阳指"的技能对象
-- 在技能列表中查找攻击比例atk_rate大于1的所有技能对象
-- 在技能列表中所有技能名称name和消耗法力cost_sp
"""
skill = IterableHelper.find_single(list_skills,
lambda item: item.name == "一阳指")
print(skill.__dict__)
for skill in IterableHelper.find_all(list_skills,
lambda item: item.atk_rate > 1):
print(skill.__dict__)
for item in IterableHelper.select(list_skills, lambda item:
(item.name, item.cost_sp)):
print(item)
Wife("苏荃", 98, 10000, 30),
Wife("阿珂", 100, 6000, 23),
Wife("铁锤", 80, 0, 35),
]
# def condition1(item):
# return item.face_score > 90
#
#
# def condition2(item):
# return item.money < 100000
#
#
# def find(func):
# for item in list_wifes:
# if func(item):
# yield item.__dict__
#
#
# for item in find(condition1):
# print(item)
#
# for item in find(condition2):
# print(item)
for i in IterableHelper.find_all(list_wifes, lambda item: item.face_score > 90):
print(i)
for i in IterableHelper.find_all(list_wifes, lambda item: item.money < 100000):
print(i)
隔：使用参数隔离具体变化的函数
做：通常使用lambda定义变化函数
练习:
"""
list01 = [42, 45, 5, 66, 7, 89]
# 提取变化函数
# def condition01(item):
# return item > 10
#
# def condition02(item):
# return item % 2 == 0
# 提取通用函数 -- 万能查找
def find(func): # 创建了钩子
for item in list01:
if func(item): # 拉起钩子(执行条件)
yield item
# for number in find_all(condition02):# 向钩子上挂条件
for number in find(lambda item: item % 2 == 0): # 向钩子上挂条件
print(number)
from common.iterable_tools import IterableHelper
# for number in IterableHelper.find_all(list01, condition01):
for number in IterableHelper.find_all(list01, lambda item: item % 2 == 0):
print(number)
"""
lambda应用
"""
from common.iterable_tools import IterableHelper
list01 = [63, 5, 56, 7, 8, 9]
def condtion01(number):
return number < 10
# lambda number:number < 10
# 查找能被5整除的数字
def condition02(item):
return item % 5 == 0
for item in IterableHelper.find_all(list01, lambda number: number < 10):
print(item)
for item in IterableHelper.find_all(list01, lambda item:item % 5 ==0):
print(item)
"""
练习：
将find_all封装到common/iterable_tools的
的IterableHelper类中作为静态方法
实现下列效果：
在列表中查找所有字符串
在列表中查找所有大于20的数字
"""
from common.iterable_tools import IterableHelper
# 参数是列表的每个元素
# 返回值是查找的条件
def condition01(item):
return type(item) == str
def condition02(item):
return type(item) in (int, float) and item > 20
list01 = [43, 45, "56", 67, "78", 9]
for item in IterableHelper.find_all(list01, condition01):
print(item)
for item in IterableHelper.find_all(list01, condition02):
print(item)
# -- 在技能列表中查找名称是"一阳指"的技能对象
# -- 在技能列表中查找攻击比例atk_rate大于1的所有技能对象
# -- 在技能列表中所有技能名称name和消耗法力cost_sp
from common.iterable_tools import IterableHelper
class Skill:
def __init__(self, name="", atk_rate=0.0, cost_sp=0, duration=0):
self.name = name
self.atk_rate = atk_rate
self.cost_sp = cost_sp
self.duration = duration
list_skills = [
Skill("横扫千军", 1, 50, 5),
Skill("九阳神功", 3, 150, 6),
Skill("降龙十八掌", 3, 150, 5),
Skill("一阳指", 1.2, 0, 2),
Skill("乾坤大挪移", 3.2, 30, 2),
Skill("打狗棍", 1.3, 0, 6),
]
if __name__ == '__main__':
employee = IterableHelper.find_single(list_skills, lambda emp: emp.name == "一阳指")
print(employee.__dict__)
for item in IterableHelper.find_all(list_skills, lambda emp: emp.atk_rate > 1):
print(item.__dict__)
for item in IterableHelper.select(list_skills,lambda emp:(emp.name,emp.cost_sp)):
print(item)