예제 #1
0
def part_1():
    start = "shiny gold"
    bags = {}

    raw_data = read_input(7, 1)
    for l in raw_data:
        parent, children = parse_row(l)
        bags[parent] = children

    nodes = bags.keys()
    connected = []
    friends = []

    for k, v in bags.items():
        if k != start:
            if start in v:
                connected.append(k)
                friends.append(k)

    while connected:
        node = connected.pop()
        for k, v in bags.items():
            if k != node:
                if node in v:
                    connected.append(k)
                    friends.append(k)
    print(len(set(friends)))
예제 #2
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def part_2():
    start = "shiny gold"
    bags = {}

    raw_data = read_input(7, 1)
    for l in raw_data:
        parent, children = parse_row(l, with_counts=True)
        bags[parent] = children

    # children = []
    # to_visit = []
    # for child in bags[start]:
    #     count, node = child.split(" ", maxsplit=1)
    #     to_visit.append((node, int(count)))
    #     children.append((node, int(count)))

    # while to_visit:
    #     current = to_visit.pop()
    #     for child in bags[current[0]]:
    #         count, node = child.split(" ", maxsplit=1)
    #         to_visit.append((node, int(count)))
    #         children.append((node, int(count)))
    # print(children)
    total = traverse(bags, start)
    print(total)
예제 #3
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def part_2():
    raw_input = read_input(6, 1)
    grouped = group_partition(raw_input)
    total = 0
    for g in grouped:
        total += len(g)
    print(total)
예제 #4
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def part_1():
    raw_input = read_input(6, 1)
    partitioned = partition_input(raw_input)
    count = 0
    for partition in partitioned:
        p_set = set(partition)
        count += len(p_set)
    print(count)
예제 #5
0
파일: main.py 프로젝트: r-xela/AoC2020
def part_2():
    total = 57195069
    raw_input = read_input(9, 1)
    conv_input = [int(e) for e in raw_input]

    for window_size in range(2, len(conv_input)):
        for w in window(conv_input, window_size):
            if sum(w) == total:
                print(min(w) + max(w))
예제 #6
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def part_1():
    passwords = read_input(2, 1)
    valid = []
    for password in passwords:
        minimum, maximum, character, p = parse_password_row(password)

        letter_counts = Counter(p)
        if int(minimum) <= letter_counts[character] <= int(maximum):
            valid.append(password)

    print(len(valid))
예제 #7
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def part_2():
    """
    Note: For this task, pos1 and pos2 are not 0-based position in the string, that's why the -1
    """
    passwords = read_input(2, 1)
    valid = []
    for password in passwords:
        pos1, pos2, character, p = parse_password_row(password)
        # pos1 and pos2 are not allowed to be identical according to password policy
        if (p[pos1 - 1] != p[pos2 - 1]) and (
            # either pos1 or pos2 needs to be the character
            p[pos1 - 1] == character
            or p[pos2 - 1] == character
        ):
            valid.append(password)

    print(len(valid))
예제 #8
0
파일: main.py 프로젝트: r-xela/AoC2020
def part_2():
    raw_input = read_input(8, 1)
    instructions = get_instructions(raw_input)
    for i in range(0, len(instructions)):
        current = instructions[i]
        if current[0] == "jmp":
            tmp = ("nop", current[1])
        elif current[0] == "nop":
            tmp = ("jmp", current[1])
        else:
            continue

        instructions[i] = tmp
        total, finished = parse_instructions(instructions)
        if finished:
            print(total)
            exit(0)
        instructions[i] = current
예제 #9
0
def part_1() -> List[Dict]:
    passports = []

    puzzle_input_raw = read_input(4, 1)
    current = dict()
    for l in puzzle_input_raw:
        if l:
            entries = l.split(" ")
            for e in entries:
                k, v = e.split(":")
                current[k] = v
        else:
            passports.append(current)
            current = dict()
    passports.append(current)

    valid = [p for p in passports if len(p.keys()) == 8]

    missing_only_one = [p for p in passports if len(p.keys()) == 7]
    missing_only_cid = [p for p in missing_only_one if "cid" not in p]

    return valid + missing_only_cid
예제 #10
0
파일: main.py 프로젝트: r-xela/AoC2020
def part_1():
    puzzle_input_raw = read_input(5, 1)

    highest = 0
    pass_str = ""
    seat_ids = []
    for boarding_pass in puzzle_input_raw:
        row, column = boarding_pass[:-3], boarding_pass[-3:]
        row_number = search(row, 0, 127)
        column_number = search(column, 0, 7)

        seat_id = row_number * 8 + column_number
        seat_ids.append(seat_id)

        # print(
        #     f"{boarding_pass}: row {row_number}, column {column_number}, seat id {seat_id}"
        # )
        if seat_id > highest:
            highest = seat_id
            pass_str = boarding_pass

    print(f"{pass_str}: {highest}")

    return sorted(seat_ids)
예제 #11
0
def part_1(step_x=3, step_y=1):
    raw_input = read_input(3, 1)

    x = 0
    y = 0

    pos_x = 0
    pos_y = 0

    trees = 0

    mod = len(raw_input[0])

    while pos_y < len(raw_input):
        row = raw_input[pos_y]
        field = row[pos_x % len(row)]

        if field == "#":
            trees += 1

        pos_x += step_x
        pos_y += step_y

    return trees
예제 #12
0
from common.read import read_input

if __name__ == "__main__":

    puzzle_input_raw = read_input(1, 1)
    puzzle_input = [int(e) for e in puzzle_input_raw]

    # Puzzle 1 - The sum is supposed to be 2020, which means one of the numbers needs to be >= 1010

    upper = set([e for e in puzzle_input if e >= 1010])
    counter_part = [(2020 - e) for e in puzzle_input if e <= 1010]

    for e in counter_part:
        if e in upper:
            print(f"{e} + {2020-e} = 2020 - {e} * {2020-e} = {e * (2020-e)}")

    # Puzzle 2 - naive approach

    year = 2020
    parts = 3

    # at least one number needs to bee larger than 2020/3 = 673,3 = 674 (when talking about integers)
    first_number = set([e for e in puzzle_input if e >= int(year / 3)])
    # remainders contain the sum of the two missing numbers
    remainders = set([(year - e) for e in first_number])

    # for each of the remainders repeat the same procedure and try to find two numbers from
    # puzzle input that give the sum. Basically reiterate the approach from part 1
    for r in remainders:
        second_number = set([e for e in puzzle_input if e >= int(r / 2)])
        counter_part_3 = set([r - e for e in second_number])
예제 #13
0
파일: main.py 프로젝트: r-xela/AoC2020
def part_1():
    raw_input = read_input(8, 1)
    instructions = get_instructions(raw_input)
    total, finished = parse_instructions(instructions)
    print(f"Finished: {finished}. Acc: {total}")
예제 #14
0
파일: main.py 프로젝트: r-xela/AoC2020
def part_1():
    raw_input = read_input(9, 1)
    conv_input = [int(e) for e in raw_input]
    for sub in window(conv_input, 26):
        check(sub[:-1], sub[-1])