Python TupleArg 예제들

예제 #1

파일: pycodegen.py 프로젝트: loy2000/Ghidra

def generateArgList(arglist):
    """Generate an arg list marking TupleArgs"""
    args = []
    extra = []
    count = 0
    for i in range(len(arglist)):
        elt = arglist[i]
        if isinstance(elt, str):
            args.append(elt)
        elif isinstance(elt, tuple):
            args.append(TupleArg(i * 2, elt))
            extra.extend(misc.flatten(elt))
            count = count + 1
        else:
            raise ValueError, "unexpect argument type:", elt
    return args + extra, count

예제 #2

파일: pycodegen.py 프로젝트: vandys/tauthon

def generateArgList(arglist):
    """Generate an arg list marking TupleArgs"""
    args = []
    extra = []
    count = 0
    for i in range(len(arglist)):
        elt = arglist[i]
        if isinstance(elt, ast.SimpleArg):
            args.append(elt.name)
        elif isinstance(elt, ast.NestedArgs):
            t = tuple(_nested_names(elt))
            args.append(TupleArg(i * 2, t))
            extra.extend(misc.flatten(t))
            count = count + 1
        else:
            raise ValueError, "unexpect argument type:", elt
    return args + extra, count

예제 #3

def generateArgList(arglist):
    """Generate an arg list marking TupleArgs"""
    args = []
    extra = []
    count = 0
    for i in range(len(arglist)):
        elt = arglist[i]
        if util.is_unicode(elt):
            args.append(elt)
        # for Python 2 -- not sure why I got non-unicode
        elif isinstance(elt, str):
            args.append(elt)
        elif isinstance(elt, tuple):
            args.append(TupleArg(i * 2, elt))
            extra.extend(misc.flatten(elt))
            count = count + 1
        else:
            # Not in Python 2.
            #raise ValueError("unexpect argument type:").with_traceback(elt)
            raise ValueError("unexpect argument type: %r (%s)" %
                             (elt, type(elt)))
    return args + extra, count

예제 #4

import imp