def get_version(self, lines, filename):
# we will try to find python3+ as well as python2+
# currently regex will probably find a single string "lib/python3.6"
# where 3.6 is the version similarly "lib/python2.7" where 2.7 is the version
version_info = super().get_version(lines, filename)
# we will check if the guess returned some version probably 3.6 or 2.7 in our example
# return version_info
if "version" in version_info and version_info["version"] != "UNKNOWN":
# we will update our regex to something more precise 3.6.d
# where d is unknown and we will find d. which will return 3.6.9 or some other version
version_pattern = [
rf"([{version_info['version'][0]}]+\.[{version_info['version'][2]}]+\.[0-9])"
]
version_regex = list(map(re.compile, version_pattern))
new_version = regex_find(lines, version_regex)
# we will return this result
version_info["version"] = new_version
# else guess was unknown so we update our regex
elif version_info:
version_pattern = [
r"Version: ([23]+\.[0-9]+\.[0-9])+",
r"version: ([23]+\.[0-9]+\.[0-9])+",
r"Python ([23]+\.[0-9]+\.[0-9])+",
]
version_regex = list(map(re.compile, version_pattern))
new_version = regex_find(lines, version_regex)
version_info["version"] = new_version
return version_info
def get_version(self, lines, filename):
version_info = dict()
if any(pattern.search(filename) for pattern in self.FILENAME_PATTERNS):
version_info["is_or_contains"] = "is"
if "is_or_contains" not in version_info and self.guess_contains(lines):
version_info["is_or_contains"] = "contains"
if "is_or_contains" in version_info:
version_info["version"] = regex_find(lines, self.VERSION_PATTERNS)
return version_info