예제 #1
0
    def graph_implementation(arg_objs, size, data=None):
        """Reduces the atom to an affine expression and list of constraints.

        Parameters
        ----------
        arg_objs : list
            LinExpr for each argument.
        size : tuple
            The size of the resulting expression.
        data :
            Additional data required by the atom.

        Returns
        -------
        tuple
            (LinOp for objective, list of constraints)
        """
        #x = arg_objs[0]
        t = lu.create_var(size)

        # log(1 + exp(x)) <= t <=> exp(-t) + exp(x - t) <= 1
        '''
        obj0, constr0 = exp.graph_implementation([lu.neg_expr(t)], size)
        obj1, constr1 = exp.graph_implementation([lu.sub_expr(x, t)], size)
        lhs = lu.sum_expr([obj0, obj1])
        ones = lu.create_const(np.mat(np.ones(size)), size)
        constr = constr0 + constr1 + [lu.create_leq(lhs, ones)]
        '''

        a = arg_objs[0]
        b = arg_objs[1]

        e_a, e_a_cons = exp.graph_implementation([lu.neg_expr(a)], (1,1))
        e_b, e_b_cons = exp.graph_implementation([lu.neg_expr(b)], (1,1))
        obj0, constr0 = log.graph_implementation(
            [lu.sub_expr(e_b,e_a)],
            (1,1)
        )
        lhs = obj0
        constr = constr0 + e_a_cons + e_b_cons + [lu.create_leq(lhs, t)] + [lu.create_leq(e_a, e_b)]

        return (t, constr)
예제 #2
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    def graph_implementation(arg_objs, shape, data=None):
        """Reduces the atom to an affine expression and list of constraints.

        Parameters
        ----------
        arg_objs : list
            LinExpr for each argument.
        shape : tuple
            The shape of the resulting expression.
        data :
            Additional data required by the atom.

        Returns
        -------
        tuple
            (LinOp for objective, list of constraints)
        """
        x = arg_objs[0]
        ones = lu.create_const(np.mat(np.ones(x.shape)), x.shape)
        xp1 = lu.sum_expr([x, ones])
        return log.graph_implementation([xp1], shape, data)
예제 #3
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파일: log1p.py 프로젝트: nicaiseeric/cvxpy
    def graph_implementation(arg_objs, size, data=None):
        """Reduces the atom to an affine expression and list of constraints.

        Parameters
        ----------
        arg_objs : list
            LinExpr for each argument.
        size : tuple
            The size of the resulting expression.
        data :
            Additional data required by the atom.

        Returns
        -------
        tuple
            (LinOp for objective, list of constraints)
        """
        x = arg_objs[0]
        ones = lu.create_const(np.mat(np.ones(x.size)), x.size)
        xp1 = lu.sum_expr([x, ones])
        return log.graph_implementation([xp1], size, data)
예제 #4
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파일: log_det.py 프로젝트: ThomasLipp/cvxpy
    def graph_implementation(arg_objs, size, data=None):
        """Reduces the atom to an affine expression and list of constraints.

        Creates the equivalent problem::

           maximize    sum(log(D[i, i]))
           subject to: D diagonal
                       diag(D) = diag(Z)
                       Z is upper triangular.
                       [D Z; Z.T A] is positive semidefinite

        The problem computes the LDL factorization:

        .. math::

           A = (Z^TD^{-1})D(D^{-1}Z)

        This follows from the inequality:

        .. math::

           \det(A) >= \det(D) + \det([D, Z; Z^T, A])/\det(D)
                   >= \det(D)

        because (Z^TD^{-1})D(D^{-1}Z) is a feasible D, Z that achieves
        det(A) = det(D) and the objective maximizes det(D).

        Parameters
        ----------
        arg_objs : list
            LinExpr for each argument.
        size : tuple
            The size of the resulting expression.
        data :
            Additional data required by the atom.

        Returns
        -------
        tuple
            (LinOp for objective, list of constraints)
        """
        A = arg_objs[0]  # n by n matrix.
        n, _ = A.size
        X = lu.create_var((2 * n, 2 * n))
        Z = lu.create_var((n, n))
        D = lu.create_var((n, n))
        # Require that X is symmetric (which implies
        # A is symmetric).
        # X == X.T
        obj, constraints = transpose.graph_implementation([X], (n, n))
        constraints.append(lu.create_eq(X, obj))
        # Require that X and A are PSD.
        constraints += [SDP(X), SDP(A)]
        # Fix Z as upper triangular, D as diagonal,
        # and diag(D) as diag(Z).
        for i in xrange(n):
            for j in xrange(n):
                if i == j:
                    # D[i, j] == Z[i, j]
                    Dij = index.get_index(D, constraints, i, j)
                    Zij = index.get_index(Z, constraints, i, j)
                    constraints.append(lu.create_eq(Dij, Zij))
                if i != j:
                    # D[i, j] == 0
                    Dij = index.get_index(D, constraints, i, j)
                    constraints.append(lu.create_eq(Dij))
                if i > j:
                    # Z[i, j] == 0
                    Zij = index.get_index(Z, constraints, i, j)
                    constraints.append(lu.create_eq(Zij))
        # Fix X using the fact that A must be affine by the DCP rules.
        # X[0:n, 0:n] == D
        index.block_eq(X, D, constraints, 0, n, 0, n)
        # X[0:n, n:2*n] == Z,
        index.block_eq(X, Z, constraints, 0, n, n, 2 * n)
        # X[n:2*n, n:2*n] == A
        index.block_eq(X, A, constraints, n, 2 * n, n, 2 * n)
        # Add the objective sum(log(D[i, i])
        log_diag = []
        for i in xrange(n):
            Dii = index.get_index(D, constraints, i, i)
            obj, constr = log.graph_implementation([Dii], (1, 1))
            constraints += constr
            log_diag.append(obj)
        obj = lu.sum_expr(log_diag)
        return (obj, constraints)
예제 #5
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파일: log_det.py 프로젝트: rtruxal/cvxpy
    def graph_implementation(arg_objs, size, data=None):
        """Reduces the atom to an affine expression and list of constraints.

        Creates the equivalent problem::

           maximize    sum(log(D[i, i]))
           subject to: D diagonal
                       diag(D) = diag(Z)
                       Z is upper triangular.
                       [D Z; Z.T A] is positive semidefinite

        The problem computes the LDL factorization:

        .. math::

           A = (Z^TD^{-1})D(D^{-1}Z)

        This follows from the inequality:

        .. math::

           \det(A) >= \det(D) + \det([D, Z; Z^T, A])/\det(D)
                   >= \det(D)

        because (Z^TD^{-1})D(D^{-1}Z) is a feasible D, Z that achieves
        det(A) = det(D) and the objective maximizes det(D).

        Parameters
        ----------
        arg_objs : list
            LinExpr for each argument.
        size : tuple
            The size of the resulting expression.
        data :
            Additional data required by the atom.

        Returns
        -------
        tuple
            (LinOp for objective, list of constraints)
        """
        A = arg_objs[0]  # n by n matrix.
        n, _ = A.size
        X = lu.create_var((2 * n, 2 * n))
        X, constraints = Semidef(2 * n).canonical_form
        Z = lu.create_var((n, n))
        D = lu.create_var((n, 1))
        # Require that X and A are PSD.
        constraints += [SDP(A)]
        # Fix Z as upper triangular, D as diagonal,
        # and diag(D) as diag(Z).
        Z_lower_tri = lu.upper_tri(lu.transpose(Z))
        constraints.append(lu.create_eq(Z_lower_tri))
        # D[i, i] = Z[i, i]
        constraints.append(lu.create_eq(D, lu.diag_mat(Z)))
        # Fix X using the fact that A must be affine by the DCP rules.
        # X[0:n, 0:n] == D
        index.block_eq(X, lu.diag_vec(D), constraints, 0, n, 0, n)
        # X[0:n, n:2*n] == Z,
        index.block_eq(X, Z, constraints, 0, n, n, 2 * n)
        # X[n:2*n, n:2*n] == A
        index.block_eq(X, A, constraints, n, 2 * n, n, 2 * n)
        # Add the objective sum(log(D[i, i])
        obj, constr = log.graph_implementation([D], (n, 1))
        return (lu.sum_entries(obj), constraints + constr)
예제 #6
0
파일: log_det.py 프로젝트: gvanzin/cvxpy
    def graph_implementation(arg_objs, size, data=None):
        """Reduces the atom to an affine expression and list of constraints.

        Creates the equivalent problem::

           maximize    sum(log(D[i, i]))
           subject to: D diagonal
                       diag(D) = diag(Z)
                       Z is upper triangular.
                       [D Z; Z.T A] is positive semidefinite

        The problem computes the LDL factorization:

        .. math::

           A = (Z^TD^{-1})D(D^{-1}Z)

        This follows from the inequality:

        .. math::

           \det(A) >= \det(D) + \det([D, Z; Z^T, A])/\det(D)
                   >= \det(D)

        because (Z^TD^{-1})D(D^{-1}Z) is a feasible D, Z that achieves
        det(A) = det(D) and the objective maximizes det(D).

        Parameters
        ----------
        arg_objs : list
            LinExpr for each argument.
        size : tuple
            The size of the resulting expression.
        data :
            Additional data required by the atom.

        Returns
        -------
        tuple
            (LinOp for objective, list of constraints)
        """
        A = arg_objs[0] # n by n matrix.
        n, _ = A.size
        X = lu.create_var((2*n, 2*n))
        Z = lu.create_var((n, n))
        D = lu.create_var((n, 1))
        # Require that X and A are PSD.
        constraints = [SDP(X), SDP(A)]
        # Fix Z as upper triangular, D as diagonal,
        # and diag(D) as diag(Z).
        Z_lower_tri = lu.upper_tri(lu.transpose(Z))
        constraints.append(lu.create_eq(Z_lower_tri))
        # D[i, i] = Z[i, i]
        constraints.append(lu.create_eq(D, lu.diag_mat(Z)))
        # Fix X using the fact that A must be affine by the DCP rules.
        # X[0:n, 0:n] == D
        index.block_eq(X, lu.diag_vec(D), constraints, 0, n, 0, n)
        # X[0:n, n:2*n] == Z,
        index.block_eq(X, Z, constraints, 0, n, n, 2*n)
        # X[n:2*n, n:2*n] == A
        index.block_eq(X, A, constraints, n, 2*n, n, 2*n)
        # Add the objective sum(log(D[i, i])
        obj, constr = log.graph_implementation([D], (n, 1))
        return (lu.sum_entries(obj), constraints + constr)
예제 #7
0
    def graph_implementation(arg_objs, size, data=None):
        """Reduces the atom to an affine expression and list of constraints.

        Creates the equivalent problem::

           maximize    sum(log(D[i, i]))
           subject to: D diagonal
                       diag(D) = diag(Z)
                       Z is upper triangular.
                       [D Z; Z.T A] is positive semidefinite

        The problem computes the LDL factorization:

        .. math::

           A = (Z^TD^{-1})D(D^{-1}Z)

        This follows from the inequality:

        .. math::

           \det(A) >= \det(D) + \det([D, Z; Z^T, A])/\det(D)
                   >= \det(D)

        because (Z^TD^{-1})D(D^{-1}Z) is a feasible D, Z that achieves
        det(A) = det(D) and the objective maximizes det(D).

        Parameters
        ----------
        arg_objs : list
            LinExpr for each argument.
        size : tuple
            The size of the resulting expression.
        data :
            Additional data required by the atom.

        Returns
        -------
        tuple
            (LinOp for objective, list of constraints)
        """
        A = arg_objs[0]  # n by n matrix.
        n, _ = A.size
        X = lu.create_var((2 * n, 2 * n))
        Z = lu.create_var((n, n))
        D = lu.create_var((n, n))
        # Require that X is symmetric (which implies
        # A is symmetric).
        # X == X.T
        obj, constraints = transpose.graph_implementation([X], (n, n))
        constraints.append(lu.create_eq(X, obj))
        # Require that X and A are PSD.
        constraints += [SDP(X), SDP(A)]
        # Fix Z as upper triangular, D as diagonal,
        # and diag(D) as diag(Z).
        for i in xrange(n):
            for j in xrange(n):
                if i == j:
                    # D[i, j] == Z[i, j]
                    Dij = index.get_index(D, constraints, i, j)
                    Zij = index.get_index(Z, constraints, i, j)
                    constraints.append(lu.create_eq(Dij, Zij))
                if i != j:
                    # D[i, j] == 0
                    Dij = index.get_index(D, constraints, i, j)
                    constraints.append(lu.create_eq(Dij))
                if i > j:
                    # Z[i, j] == 0
                    Zij = index.get_index(Z, constraints, i, j)
                    constraints.append(lu.create_eq(Zij))
        # Fix X using the fact that A must be affine by the DCP rules.
        # X[0:n, 0:n] == D
        index.block_eq(X, D, constraints, 0, n, 0, n)
        # X[0:n, n:2*n] == Z,
        index.block_eq(X, Z, constraints, 0, n, n, 2 * n)
        # X[n:2*n, n:2*n] == A
        index.block_eq(X, A, constraints, n, 2 * n, n, 2 * n)
        # Add the objective sum(log(D[i, i])
        log_diag = []
        for i in xrange(n):
            Dii = index.get_index(D, constraints, i, i)
            obj, constr = log.graph_implementation([Dii], (1, 1))
            constraints += constr
            log_diag.append(obj)
        obj = lu.sum_expr(log_diag)
        return (obj, constraints)