def main():
result = 0
test_numbers = list(range(1, 10000))
for i in test_numbers:
a = sum(list(factors(i))[:-1])
b = sum(list(factors(a))[:-1])
if i == b and a != b:
test_numbers.remove(max(a, b))
result += a + b
return result
def first_triangle_with_divisors(num):
'''
Find the first triangle number with
at least num number of divisors
'''
count = 1
triangle = 1
factor_count = 0
while factor_count < num:
count += 1
triangle += count
if num < 100 or num > 100 and not triangle % 2 and not triangle % 3:
factor_count = len(factors(triangle))
return (triangle, factor_count)
def first_triangle_with_divisors(num):
'''
Find the first triangle number with
at least num number of divisors
'''
count = 1
triangle = 1
factor_count = 0
while factor_count < num:
count += 1
triangle += count
if num < 100 or num > 100 and not triangle % 2 and not triangle % 3:
factor_count = len(factors(triangle))
return (triangle, factor_count)
def is_abundant(num):
if not num % 2 or not num % 3:
return sum(factors(num)) > num
def abundant_numbers(n=1000):
# find all abundant numbers up to n
for i in range(12, n):
a = sum(list(factors(i))[:-1])
if a > i:
yield i
def is_abundant(num): if not num % 2 or not num % 3: return sum(factors(num)) > num
